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3. Pick a card; keep it; pick another card: DO NOT SIMPLIFY (12 points) Find the probability of getting a. exactly 2 kings: b. exactly king: kings:...

Question

3. Pick a card; keep it; pick another card: DO NOT SIMPLIFY (12 points) Find the probability of getting a. exactly 2 kings: b. exactly king: kings:

3. Pick a card; keep it; pick another card: DO NOT SIMPLIFY (12 points) Find the probability of getting a. exactly 2 kings: b. exactly king: kings:



Answers

A hand of 13 cards is to be dealt at random and without replacement from an ordinary deck of playing cards. Find the conditional probability that there are at least three kings in the hand given that the hand contains at least two kings.

Everyone this exercise were asked to find the probability to draw two kings out of his tender deck of cards. When we do this is to separate the two draw us in two different events. So first we will find the probability to draw a single king out of this tender deck. Tender deck is 52 cards, and there are four kings in this tender day. So to find the probability of drink one king out of 52 cards, we simply divide for by 52. This is one event. The second event is the second row, where we need to drop yet another king now. This time, however, since we already grew king, those numbers are changing. Our second event only have 51 cards today and treatments because we Truman and it's now out of the deck. Probably of the second events happening is Tree divided by 51 Conroe in poverty is that thio combine the probability of two events into one? In other words, to find the probability that two different events happen, we need to multiply the probabilities, and so the total probability is gonna be given by 12. That's fourth Street divided by 51 times 52 which is 26 100 52. And this could be reduced to one overt. 220. There you have it. This is the property of drawing exactly two kings out of a deck of 52 cards. Thank you.

Everyone this exercise were asked to find the probability to draw two kings out of his tender deck of cards. When we do this is to separate the two draw us in two different events. So first we will find the probability to draw a single king out of this tender deck. Tender deck is 52 cards, and there are four kings in this tender day. So to find the probability of drink one king out of 52 cards, we simply divide for by 52. This is one event. The second event is the second row, where we need to drop yet another king now. This time, however, since we already grew king, those numbers are changing. Our second event only have 51 cards today and treatments because we Truman and it's now out of the deck. Probably of the second events happening is Tree divided by 51 Conroe in poverty is that thio combine the probability of two events into one? In other words, to find the probability that two different events happen, we need to multiply the probabilities, and so the total probability is gonna be given by 12. That's fourth Street divided by 51 times 52 which is 26 100 52. And this could be reduced to one overt. 220. There you have it. This is the property of drawing exactly two kings out of a deck of 52 cards. Thank you.

I guess this problem. We want to calculate the probability that we drove to kings and rode out of the standard deck of cards. So tender deck of cards. That's 52 cards. And I'm sure everyone knows there's four Kings in his tender deck of cards and sort of probability to draw. Walking for Mr New Deck of cards will be four over 52 because there's four cards in the 52 guards that we'll be kings. Now the question is about drying to King's exactly two kings and nothing else. And so far, Sigan draw. Um, well, first of all, there's only 51 cards left in the deck, and since we know we drift king on this in the first drawer, there's only treating left. So those are two different events, drawing one king and then drawing a second thing after having drawn one thing. If we want to calculate the probability that both those events happen, we need to multiply them. That's the rule pontification for probability. So you multiply probabilities when combining evidence. So what we do here, well, simply multiply those two numbers. We end up with 12 over 2600 and 50 years on that can be reduced to one over 221. And for those of you who are curious and want to change, isn't a person ditch that zero? They're zero point for 5%. So there. That's the probability that when you got two cars of deck, both of them are kings.

For this problem, we'd like to find the probability of obtaining a king In a standard deck of 52 cards when you choose one card. So this should be a fraction, because each of the cards is equally likely to be obtained, it will be the number of successes over the total number of ways to choose a card. Now there's four kings in the deck, 1, 1 for the heart, diamond spade in the clubs, So that's four total over 52 total cards. You could simplify that to be won over 13.


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