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Estimate the slope of the tangent line (rate of change= f(z) secant lines through the points listed below.at Iby finding the slopes of theState answersthree decimal...

Question

Estimate the slope of the tangent line (rate of change= f(z) secant lines through the points listed below.at Iby finding the slopes of theState answersthree decimal places(0.8, 03 and 1.2,secant slope iut(0.9,and(114) secant slope mstc

Estimate the slope of the tangent line (rate of change= f(z) secant lines through the points listed below. at I by finding the slopes of the State answers three decimal places (0.8, 03 and 1.2, secant slope iut (0.9, and (114) secant slope mstc



Answers

Estimate the slope of the tangent line to each curve at the given point $(x, y) .$

So one point on the tangent line is to to and looking at the graph here, let's try to find another point so I can see the Y intercept here as 04 So 04 is another point. Now let's work with that. So, um, why is equal to or the slope em is? Why? To minus y one over x two minus x one. So why to minus y one over x two minus X one. That's the slope em. Start labeling here. So four minus 2/0 minus two. So that's two over minus two. That's minus one, So our slope is equal to minus one.

So looking at our graph here and number seven, we have a point minus two to on the tangent line. Now let's find a another point so I can see here there is 23 So 23 will be another point for us. So, Slope is why? To minus y one or x two minus x one. I start labeling here. So why to is three minus two over Tu minus negative too. So that'll be one over for So our slope is 1/4.

So for problem. Eight. We have the 0.3 negative one on the graph, so let's try to find another point. Ah, to work from So another point would be minus two, approximately minus two and through your actually minus three and four. Based on the graph that would look more backers of minus three and four. So let's do this one. So slope is equal to y Tu minus y one over x two minus X one. So let's start labeling X one y one and x two y two. Remember Y two is four. What I want is minus one that's minus three minus three. So that would be five over negative six. So slope is minus 5/6.

So for a number nine, we're looking here. It looks like it's a horizontal line to minus three and minus three is one point. It's a horizontal line. We can definitely say Slope is zero just by the fact it's or is hung horizontal. That's let's pick another point in order to, ah justifies that. That so zero minus three is another point. Let's do the slope equation. So that's why to minus y one over x two minus X one. So that's minus three minus negative. Three over zero minus negative three. So that would be 0/3, which is zero always on its horizontal slope zero.


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