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Question 7At tec0/1ptson#ibuuns croupdenormcd xpermci measure thc resistarce clafesistor; The manulacturer thcuncertaintyofthe 10O chms resistor usedin the experime...

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Question 7At tec0/1ptson#ibuuns croupdenormcd xpermci measure thc resistarce clafesistor; The manulacturer thcuncertaintyofthe 10O chms resistor usedin the experimentas 45. Yourmeasured value 93ohms with uncertainty ohms You made dlol and whisker plots - compare the measured valuewith the specified vale; According to lhe plot; docs the meazured value and the given value agrce with each other?Comparison Using Unceratainty|thr uncemalnteIt Utrhiniicthtovo crljo 50 W eInconduierTha dotDecnuik &quo

Question 7 At tec 0/1pts on#ibuuns croupdenormcd xpermci measure thc resistarce clafesistor; The manulacturer thcuncertaintyofthe 10O chms resistor usedin the experimentas 45. Yourmeasured value 93ohms with uncertainty ohms You made dlol and whisker plots - compare the measured valuewith the specified vale; According to lhe plot; docs the meazured value and the given value agrce with each other? Comparison Using Unceratainty | thr uncemalnte It Utrhiniicthtovo crljo 50 W eInconduier Tha dot Decn uik "tlntic} dent overijo Wlicy Jptee becn



Answers

The values of current $I$ flowing in a given resistor for the corresponding values of potential difference $V$ across the resistor are given below $\begin{array}{l}I \text { (amperes) } & 0.5 & 1.0 & 2.0 & 3.0 & 4.0 \\ V \text { (volts) } & 1.6 & 3.4 & 6.7 & 10.2 & 13.2\end{array}$ Plot a graph between $V$ and $I$ and calculate the resistance of that resistor.

Okay, So this is the potential versus current graph. As you inside of the gravity is a straight line that meets the night grown obeys the Lone Star in this case. Okay. And the resistance in the resistor is just simply you go through the slope phonograph, which is you ve a be over. I, as you can tell the slope here is it to three point a. So there for the resistance, you see 4 to 3 point a omega. And these are the answers for this question.

And this question, we are given the voltage on current values for micro wire. I'm not no down the points again, but provide a let's draw a graph. You would do this on a crafty and hence it would be much more, much better on more formal. I'm trying it roughly to scare. Now let's finish drawing a graph scale first. Now we want to draw a graph ofthe V vs so that when we did the slope we buy, tell Dobby build, I would be our assistance. No, we need to choose proper. Yet we know that all data the voltage goes from Syria. The current goes from 0.5 ampere 24 ampere on the whole discourse from 1.94 for 15 0.5 Do. Let's track down the rest of them do. It's one ampere and two amperes on the Although it has been 3.8 and 7.76 now, it's an important skill to choose your unit's properly when you draw any glass, as you see that the current goes from 0.5 before a proper unit charge would be 012 and three and four, whereas for hold it because it calls from almost to toe almost 16 properly. Choice would be 16 12 84 and zero. This way all of her points will be within this. Great. Now the units here, our world on the messier amperes. Mind you, mother, you know this was simply we simply dirty points now for syrup on five ampere which is about here We see that the voltage is almost fooled. Just have off this grid Hence this is almost a point when you do it, Ana gas it or even better on the computer. This will be much better and more exact. Let's use a different color. This is our first point now for second point. It is at one AM Pierre. It's almost fore ward, which is this for the third point at two AM peers, it is almost eight fold. So it's almost here. And for the last point, it is that at four AM Pierre, it's almost 16 world which is almost here. I was there a line through it are even better. Do it with a scale on a graph or do a fit on a computer. It will be much better, but you can see that they're almost on a straight line, which takes us to the second part. It looks like it always the onslaught. A better way to take it is to find out we to buy even aunt compare it with a two by one. Now if we equal toe I r on our physical Toby by eye, then for the same resistance we expect we buy I to be the same on. Hence we expect we to buy everyone to be equal toe. Edouard, I won and we can see the 3.84 by 1.4 is too, which is the same as one by 0.5 and two boys are upon five is four, which is the same as 7.76 by 1.9 for and it is eight for the last case on. If you do a fit on a computer, you'll see that all of the line, all of the points, like exactly on the straight line off your friends, which is how you know the onslaught is obeyed in this case Now for party, we want to find the resistance cells, which is simply Delta V vital that I so we can simply take the lot. The first data data point with the last data point. Dobby is 15.52 World minus 1.9 forward, divided by Hilda is for ampere minus 0.5 ampere which stands out away 3.88 Oh!

Hello. In this problem here we have this graph on the right that represents the relationship between the voltage or the difference in potential across a certain resistance and the current in this resistance measured in million pairs here. So the first thing that we can calculate from this graph here is the resistance. Because we know here that if we got the slope of any of these curves here, the slope which is the tangent of this angle here, for example, is equal to their resistance because V. Is equal to IR. So if we're graphing Vis on the horizontal vertical and graphing I on the horizontal, then are here is equivalent to the slope of this curve here. So from this we can calculate first are one. R one is the slope of the red line here slope which is equal to In that case we have 18 or let's first make it V over I. So here we have 18 divided by three and let's put 10 to the power of negative free to make our units and emperors instead of milly emperors. We will find them that the resistance of our one is 6000 homes. Same for our two. We will find out that Value of R two is 4000, Dividing 12/3 times 10 to the power of -3. We have our cue And its value is 4000 homes. Now for our three taking the slope of the green line. The over I The slope is six divided by three Times 10 to the power of -3. And just give us the value which is 2000 Home for Our three. Now the question here is given this configuration. Here we have a battery whose voltage is six votes. So this battery of 6V here and the resistors are connected as follows. Here we have our one and then here we have our two. That's our one Or sorry, that's our three. And here that's our one. This is the correct configuration. Excuse me. Are one in here, that's our two. So given this configuration, the question is to determine that current that will be in resistance to in this circuit. So the question here is to get the current i That is flowing through this resistance here of our two. There are many ways to proceed in that question here. But first let me get the equivalent resistance of this entire circuit here because this is something that we definitely need to get. So here let's first get the equivalent resistance of one and two. And you can see that these two resistors are connected in parallel. So the rule for two parallel resistors is Are one multiplied by our two Divided by R one Plus R two. So in that case we have 6000 Multiplied by 4000 divided by 6000 plus 4000. And the answer for this is 2400 homes. And that's the equivalent resistors of these two resistors here, one and two. Then the equivalent total resistance would be the equivalent of one and two plus R. Three. That is connected in serious to these two connectors. So here that's our three plus the equivalent resistance of one and two. So our three is 2000 homes Plus the equivalent of the other two resistors which is 2400. So the equivalent resistor is 4400 homes from this. We can get the total current that is flowing in the circuit here. So here we have I let's make it I total and it's equal to V. Of the battery divided by our equivalent, So we have the battery of 6V divided by 4400 and blood. In these numbers we will find that the current in that circuit is one 0.3 six male. The emperors Or 1.36 times 10 to the power of -3 emperors. So that's I hear that is flowing in the circuit and this I gets here at this branch point here And it's divided two I one that flows in our one and then I to that flows and are too The target here is to get the value of i. two. So we know that here when two to into resistance are connected in parallel, the current will be divided on them in inverse to the values of their resistance themselves. So here if we have are you here multiplied by their equivalent resistance which is to 1004 100. This is their difference in potential across The group or across these two resistors and that's equal to The potential difference across any of the resistors. So a free multiplied I to buy our two. We will get the same value of this. So here we have 1.3 six Multiplied by 2400. And let's divide by the value of our two and the value of our two is 4000. And if we block this, we will have the value of I two, which is around 4.82 Mellie emperors. So that's the answer. And this is the current that will flow through the resistor or two in that given configuration.

Here. We want to place it in ascending order. So Warner start from the lowest, which is Resistor seven. And then after that, we have a resistor three. Then there is this, your six to four one and life.


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