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10 mL of ~0.200 M acetic acid sample is titrated with 0.100 M NaOH standard solution.1. What is the volume of NaOH required for this titration?2. What is the pH at ...

Question

10 mL of ~0.200 M acetic acid sample is titrated with 0.100 M NaOH standard solution.1. What is the volume of NaOH required for this titration?2. What is the pH at equivalence point?

10 mL of ~0.200 M acetic acid sample is titrated with 0.100 M NaOH standard solution. 1. What is the volume of NaOH required for this titration? 2. What is the pH at equivalence point?


Answers

10 mL of ~0.200 M acetic acid sample is titrated with 0.100 M NaOH standard solution.
1. What is the volume of NaOH required for this titration?
2. What is the pH at equivalence point?

The first right the balanced chemical equation as etc Toe Ste Ordo in a criss plus an emeritus in a solution, the acting together to give any C two extra or doing a quest less water. The military show in this equation is one issue one between base and as it now five points 57 mL of solution will be equal toe 5.75 multiplied by 10 for minus 10 balls off etc. Toe see photo Business back calculation shown here the polarity off, etc. To extra order will be 5.75 multiplied by 10 by minus three. Mole at sea to SDO toe, divided by 0.500 liters, which gives the polarity as 0.115 m.

Similarity of acetic acid. They simply don't know the moles of the sea tick acid in the volume of the season Caspit. The volume is given to us at 10.0. Mileva. To calculate the moles of the CD gases, you simply can take the volume of sodium hydroxide that reacted with the acetic acid in milliliters and converted into leaders. Then use the polarity of sodium hydroxide to take leader. So you hydroxide into mole sodium hydroxide. And then once we have the mole sodium hydroxide, we know the Tokyo metric relationship is one more sodium hydroxide reacts with one more hcea H c two h 302 So now we have moles of H C two h 302 moles acetic acid up top. We then divide by the volume of acetic acid that corresponds to that many moles of acetic acid about being 10 milliliters converted toe leaders. When we get a polarity of 100.8 to 5, Moeller

So in first part of the problem, we have to calculate the initial pH Nick Mintz the ph of the solution before the addition of the base. So seal the acid present here is a we can't sit. That is acidic acid. So being an as week s it, we need to find out how much H plus down will be generated in the initial solution. And for that, we need to sort of a reaction of acid with the water. So that will be age. See toe age three Oh two reacting with the water and we will get H three o plus and, um, see to age three. Oh, to minors. Now, so are the initial concentration of us. It is the sirah point one, oh five and our initial concentration of them. It's true. Coppola's is Cyril. Also the initial cause her of the acid around is also zero. Now, if we assume that, um, ex Moller, his plan his place on our produced are h mueller off this, it is being dissociated. Then we subject x from here and we add explorers through a plus and explore eyes it around, seeing the equilibrium off this reaction we'LL have zero plan one ofthe five minus X Mueller Acid explorations Yo Plus and Explorer Asset around. So from here we can sit up a relation between the Kiev alot with the product concentrations on top over them created concentration that is H three or plus concentration times C two H three or to minus concentration over H C too. H three orto concentration. So and as you know that the cave l A for the city as it is one point eight times ten to the power minus five and on the product side, both of these ham and the concentration of X So we have excess square on the top, and in bottom we have no zero pon one o five minus X. Now we can ignore this ex being very small compared to the point one off five Miller concentration. And if we saw this equation for the sex, we'LL have a value ofthe X as, um one point three seven times ten to the par minus three. So this is the initial concentration of the H three opal a Cylon produced. That means the pH or the initial pH will be the negative. Log off thes fellow here. And this will give us a pH off two point eight six. So this is the initial P H on the solution. Now, in part b of the problem, we have to find out the volume of the base added to reach the cumulus point, we can find that by simply applying the m one view on Is it kill? Tow him Tto ri to formula. Where am one is the concentration of the acid viewing is the volume of this city Em two is the concentration of them. Ah, base and feet was the volume of the base required reached the end point. So ah, from here the volume required one of me. The concentration times the volume ofthe acid which is point one Oh five molars times twenty million later over em two, which is the concentration of the acid point one two five Moeller. So from this calculation will have a volume off sixteen point eight millimeter. So this is the volume of the base required to reach them. Equivalence point? No, in part. See, we have to find out the pH of tradition ofthe five ml base. So for that first you have to know the number of malls of their citric acid. Then we have to calculate it on the number of most of sodium hydroxide in five minutes volume. And then we have to set up the reaction between the sodium hydroxide added with the acid. From there, we'LL have tto Ah, I'm black in the final number of malls in the Henderson has allowed equation to find a pH at that point. So let's start with finding the number off mall's off acidic acid. So the initial number of months of acidic A said most on the acid is basically the concentration of their scent. Times its volume, which is twenty millimeter, are zero point zero two zero later, and this will give us toe point one times ten to the poor, minus three more. So this is the number of all of the city can sit. Now we have to find out the ah number of moles off be's in five ml because they're adding five mil of base That disappoint. So we have to multiply the concentration of the base, which is zero point one two five more par later times the following, which is five millimeters zero point zero zero five liter. So from here we'LL have the number of most of base as zero point six to five times ten to the par minus three more. So this is the number of most of base in five militar. Now we have to set up the reaction that will occur between the and IT base. And that's it. So we're adding here, sodium hydroxide two, the city has said, and we're producing. Sorry. Um, acid ate and water. So now our initial concentration off the acidic acid is two point one times ten to the poor minus three. Now we're adding, um, zero point six to five more base. That means this much. Ah, basically reacted the same amount off acid. That means it was subtract zero point six to five ah, more from there said. And it will add zero point six to five more sodium acid so and off in the resulting solution we'LL have and the number of most ofthe acid as the subtraction off these values, which is one plant for seven five times, generally for minus three. Now we know the number of malls off acid after the edition ofthe final base and we also know the number of most of base. So if you just plug in this values in the Henderson hassled regulation, we'LL be able to find a pH at this point. So, according to Henderson, has a vacation piece ableto be care to. The peak air for accident said, is four point seven four, plus log off based concentration over acid concentration are we can write it mall sorbets over most ofthe acid if the volume for the business either. Same. So we have malsom base over most ofthe ass in. And so if we just plug in the Melissa Be's and balls of acid here as, ah these values, we'LL see that on the Ph will mean four point three seven. So this is the beach from the solution. After the addition off five ML base now in part deal, we have to find a pH at one half off. They've given a spine. So since it's a weak acid, strong based attrition in such cases the ph and half urine spined is basically equal to the big K of the acid. So here our Ph is equal toe peek a on the acid or the circus it, which we already have seen. That is full point seven four. So thes who will be the pH and the half equivalence point for this patrician. Now we have to calculate the peach and the equivalence point. So at the unis point, the pH of the solution will be due to the reaction of the acid it down with water. So first we have to calculate the concentration off acid are in the flask at the balance point. No, to find that we have to go. Ah, you know the number of malls off acid around and they're gonna spine. So since and they give an aspirant the total acidic as it will be reacted, that means the concentration off a sit down are the number of malls of acid around. And the unit's point is the initial number of malls off acidic acid, which is we have already calculated as stupid one times into the poor minus three mole. So this is our number of malls off acid around. Now we have to find a concentration of us around at the acuteness point. So we have to divide this smalls by the total volume of the solution at a given its point which is we already had their six solution as to Inti Ml And to reach the cumulus point, we have a red sixteen point eight ml on the base that missing total we have thirty six point eight a m l r. Zero pined zero three six eight litre in volume. It's apparently the concentration of there. Sit down at the given its point will be zero planned zero five seven one Mueller. Now, as you have said that at the bonus point we'LL have the reaction between they're sitting down and the water that means they're set up the reaction. Ah, a sit down. This will react with the water, um to make an equilibrium between oh, it on the acidic acid and wage minus sound will be produced now So and they even inspired we have seen that the concentration off Ethel Ann is zero point zero five seven one Moeller And on dead point, we have zero moller acidic acid and Z roller hydroxide down now. So if we if we assume that no ex Mueller off the yes sir down will react with the water. We subject x from here and we and explore acid and explain hydro surround. So in the Librium off this reaction, we will have there Sit around concentration as syrup are zero five seven one minus X and explorer Acid and exploration minus now. So since here we're producing Hydro Sit down Ah, we have toe such an expression for Gaby Velo. So that gave me will be their product concentrations over the reactant concentration And here we have both of the product concentration as X. So we'LL put Xs square over the reacting concentration which is born zero five seven one minus x. Now we don't know that gave Eve Hello here but we know the cave Hello for the acidic acid which is one point eight times ten to the minus five. So there's a relation between gay and gay B, which is Gaby's equal toe que es over kw. Sark eval is one point eight times ten to the power minus five for their city incident. Care of love. L o as you know, this one times ten to the poor, minus fourteen as always. So from here we can find that the Gaby Velo floor Ah, the reaction we are talking about is five point six times generally poor minus ten. So this is our give evil. Oh, so if you just plug this fellow here and if we ignore this ex being very small compared to this fellow and we solved the equation for the sex, the value ofthe X will name five point six times ten to the minus six. So this is our which minus concentration. So to find the pH, we have to know the age plus on concentration. And, as you know, again, that the relation between H plus and Wish miners is simply ah, Kate and blew over this, which minus concentration and again, kid of love. Hello is basically the's. Fellows. If we put this fellow over that wage when Assan concentration we have just found we will have the H plus sound concentration is one point seven seven times ten to the four minus nine. So this is our X plus and concentration, and from here we can find a bee age by taking the negative log off This fellow ah, usually was a fellow off eight point seven five. So this is the pH at the equivalents burned off this day, attrition and finally we have to calculate it or find a pH after eating. Five m. L a based beyond the given its point. So for this part, we have to first know the number of malls for five mil sodium hydroxide. For that, we just simply multiply the concentration off the base with five mil or zero Plant um zero part zero zero five litre. And here we will have the concentration as zero point zero zero zero six two fine mole. So this is the number of malls on the sodium hydroxide for five m l now so ah, now we have to find a concentration off the excess sodium hydroxide we're adding after they could respond. So we'LL just find this by simply putting thiss number of malls over the total volume and the time so tourists they given this point, we have already had a thirty six point eight Mueller and now we have added more five thirty six point eight millimeter no hair that more five millimeters. So in total, we have forty one point eight militar are zero planned zero for one eight later. So from there we'LL have the Constitution of the excess sodium hydroxide were buried here That will be zero planned, zero one for Mueller. Now, since sodium hydroxide is a strong as said, that means on the excess sodium hydroxide concentration will be basically no the which minus and concentration at that point. So that which minus and concentration here is zero point zero one for Mueller. From here we can find the each class and concentration at that plant, which will be simply, um, the value ofthe kw over the which minus concentration. That means one times ten to the power minus fourteen Over these wish my ass concentration zero point zero one four. And from this calculation, we'LL have the age plus on concentration as, um six point six eight a times tend to the bar minus thirteen Mueller and now just taking the are negative log off thiss each class and concentration. We can find a pH at that point, which will be twelve point one seven. So this is the page. After adding five military airbase beyond a given its point

This question is a titillation calculation question. For arbitration calculations, we need a balanced chemical reaction. So we know the story geometry. The balanced chemical reaction is provided. One mole acetic acid reacts with one mole sodium hydroxide, producing one mole water and sodium acetate. To calculate the concentration of acetic acid. We need to know the moles of acetic acid and the volume of the acetic acid solution. The acetic acid solution is vinegar and the volume of the vinegar was provided. But we do need to calculate the moles of acetic acid. We can do that by starting with the volume of the N. H. O. H. That reacted with acetic acid. We have 16.5 mL, which we can convert to leaders by dividing by 1000. We can then convert the leaders into moles of sodium hydroxide by multiplying by the more clarity of the sodium hydroxide solution. Once we have moles sodium hydroxide, we can then convert it into molds acetic acid, recognizing the 1 to 1 relationship. Now that we have moles acetic acid, we simply divided by the leaders of the vinegar solution. 10 mL is point to one leaders, and we get a concentration of 10.8 to 5 molar acetic acid in the vinegar solution.


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