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1. (20 points) Draw the product(s) for each of the boxes below: If more than one product would result, indicate which is major and which is minor_Clz, AIClaSO3, HzS...

Question

1. (20 points) Draw the product(s) for each of the boxes below: If more than one product would result, indicate which is major and which is minor_Clz, AIClaSO3, HzSO4Zn, HCIHNOz; HzSO4MeCl (1 equiv)AICla

1. (20 points) Draw the product(s) for each of the boxes below: If more than one product would result, indicate which is major and which is minor_ Clz, AICla SO3, HzSO4 Zn, HCI HNOz; HzSO4 MeCl (1 equiv) AICla



Answers

Draw the major product formed in each reaction.

Okay. This problem is asking us to predict the products of each of these reactions. So first things first, I'm gonna go to the 1st 1 I noticed that I haven't up oxide, and I have the HCL and methanol. Okay, so what I'm gonna do is I recognize em in a set of conditions. So I'm gonna go straight away, and Protein ate my auction because that's the most basic Adam of this molecule. Okay, so I should be left with this. My protein of the oxide with a positive charge and then the remainder of my compound. Okay, so now I have to consider Michael Redd, and then I have to consider my methadone. Okay, So what's gonna happen is my methanol is going to be the one that is behaving as a nuclear file. Okay? Because it's better. Nuclear, Father, My chloride. Okay, so my methanol is going to come in and attack one of these two carbons yet we don't know which one yet. Let's let's discuss this. So if it were to attack this carbon, then that would mean that I would have to move the electrons onto that oxygen. So that's an option. The other option is it attacks this carbon and I move the electrons that way. So which is the correct one? The correct one is the one that is a kind of a mixture between the s and one type of reaction and the s and to type of reaction. Because right now, this all is going to happen on the same step. It's gonna be basically occurring simultaneously where I have my new profile attack and my electric file, my leading group leave. But it's not gonna behave in the same exact way as an s and two So it's a mixture of s and one s into. So what I'm gonna do is I have to recognize that the addition of this hydrogen makes it so that this bond right here is super weak because I have the the auction with deposit charge Auction is so Electra negative. It doesn't want to have that positive charge. It wants to have as much electron density around as possible. And with the addition of that posit charge, it makes it less so. So it's a go is going to want to kind of withdraw electrons towards it so that I can have that electron density around it so has a choice. They can either take electrons primarily from this carbon, that bond or primarily from this carbon bond. It's going to take it primarily from this carbon bond. So I'm gonna be basically pushing electron density towards the auction. And if I do that, then I'll create a partial positive, partial partial positives on the carpets. So, for example, if I have my blonde right there, I'm gonna have a slight die poll moments on this carbon. So we can kind of think of that as a carbon cut on, because if our to just straight up move the electrons onto the auction, then we would be left with a church, your car, because I right there. So it's the same thing, except we're dealing with di polls. OK, so it's a slight partial positive there, and then that's a slight partial negative right there because it's pushing electron density or pulling election etc. Towards it. So with that in mind, I'm going to use my methanol to attack that carbon, the super electro positive carbon. And in the process of doing that, I'm gonna have to move the electrons up to the auction to create this compound. So there's my alcohol. Here's its bond. So this bond right here is this bond right there next up, I'm going to force this one over, and then next up is the connection to my two methyl groups and a connection to my methanol. It's like this. And then, of course, I have my pro native methanol, but we can just alleviate that with another methanol or even recorded. So let's receives Michael. Right? So we can have some differences. Great to my core. It is going to go ahead and check that we're leaving that methanol of its posit charge. So we get this as my product. Okay? So just like that. Okay, a box that and move on to the next one. Okay. Except we have this one. So this one is a little bit different in the previous one because we're not an acidic conditions and said we're in basic conditions. So when we're in, basic conditions are actually all back up. One of our in acidic conditions. We first off protein ate my auction, and then we attack with nuclear, filed the most substitute side. That's because it's a mixture of s and one. And that's into we have a leaving group leave at the same time Medical file tax. But we attack the more, um hindered Carbon. Where it's for this one way are only in basic conditions, no set of conditions. So this is going to perform in a purely ash into reaction. So we don't have to consider the fact that we're gonna have a pronation set which isn't actually gonna occur. Or we don't have to consider the fact that we have a mixture of s and one slash s and to type of actions. It's on Lee s and two. So what is s and to prefer, it prefers the least abled carbon. So just straight away, I'm going to attack this carbon, and I'm gonna move the electrons out to that auction so I should get the following in which I have my auction slash meth, uh, with oxide connected to my ch two connected to my two method groups and then connected to my oxygen with a negative charge. Okay. And I'm just gonna show the circle around that just to differentiate between the formal charge and the method group of my if oxide oxide. Okay, so now I have to go ahead. And Protein ate that auction with a mega charge. And I'm just gonna go ahead and use the hydrogen on my methanol, so they should be my product of that just like this. Okay, next up. Okay. So, uh, these ones before even start, I say that they're the exact same structure. OK, so that means I'm probably gonna have some differences in the product, but we'll see. Okay, so first up, I see that Minister conditions FM in a set of conditions. That means I'm gonna go ahead and Protein ate that auction. And remember what I said. If we're in a set of conditions, we have a mixture of s and one and s and to type of reaction. So we would attack with my new profile the most, um, hysterically hindered carbon. So what is this hysterically Henry Carbon? Well, we don't have one because we have this one or we have this one. It's a symmetrical shape oxide. So we just have a choice. We're just going to attack this one just because it would be the signatures attacking that one says, Go ahead and do that. I'm gonna move the elections after the auction resulting in this compound. So there is my methanol with a pro nation. Okay. And then here's my alcohol. Just like that, Okay? And we don't. And then, actually, well, we have to deeper Nate that So we're gonna deep Renate it with the corridor just like that, Okay? And then we should get This is my final product. Okay, Now, let's move on to the next one for this one. We're in basic conditions. And remember what I said. Basic conditions prefer s into, but because this is a symmetrical shape oxide, it doesn't matter which one attack could I like that one, Or it could attack that one. Okay. So just because I did attack the one on the right before I'm just gonna show that we could also attack the one on the right. Still, even though it's in basic conditions, right, because it's symmetrical. It doesn't matter. So this should should be the intermediate of that. So I have my auction with another charge and then the remainder of my compound. And then, of course, I have to put me at that auction with an IQ of charge. I'm just going to use the hydrogen and methanol so I should form the exact same product as I did up here. So just duplicate that we should get these two products.

Here were asked for the major products obtained from the reaction of each of these compounds with one of Corbyn of HCL, and they were also asked to indicate the kinetic and thermodynamic products. The first one is to three dimethyl 13 pence a dying which I've drawn on screen here. And so we're gonna number this or we're gonna number are dying one through four. Just those four carbons that participate in the dying and we're gonna number. It's what we get the most stable carbon cat I in, uh, couple Catalans overall. So if I go from this side, my car broke a tie. Ins are always on carbons two and four. So if I go from this side over here, I would have tertiary on two and a secondary on four. If I went from the other direction, I'd have a tertiary onto in a primary on four. So I'm gonna go from this direction, so I get tertiary and secondary instead of tertiary in primary. This will be one too 34 on, and then the first step is to have that 12 double bond. Grab our hydrogen off of the chlorine and give us A car broke out. I am so that carbon cut. I would look like this, um, be hydrogen here. Went on to carbon one is that we can have the call carbon to be the carbon cat I And since that will be a Lilic, um, so that is our first intermediate. And then there's this also has a resonance contributor. If we move that double bond right there and that residents contributor looks like this, it's no never bonds here, and our car broke out I and is up here and then we'll get a product from each of these just by attacking the car. Broke a tie ins with the C L minus the Korean nuclear file that was left over from the HCL. So from this top one right here will have the chlorine on this carbon up here and are double bond stays over here. This is our 12 product, and then from the bottom, we will have double bond right here and a chlorine over here. And this is our 14 So a zipper, kinetic and thermodynamic, the one to product is always the kinetic product. Who's, um now, keep in mind that the Connecticut promoting them. It could be the same products. But the kinetic product is always 12 because of the proximity effects soapy for proximity effect. And that just means that because when this hydrogen is pulled off the chlorine, the Korean then is right next to this carbon cat are in a position to. So it's really easy for just going attack just because of the proximity. So that will be the Connecticut product. And then the thermodynamic product is going to be the most stable product on. And we're talking about thes reactions that usually means the most stable out keen. And so here the most Abel Kane is usually going to be the AL Keen. That is some of substituted, Um, and so here, that is going to be the 14 So this will be our thermodynamic product because the Al Keen is more stable. Um, and then let's part want our part A and then for part B, we're going to the same thing. We're gonna number our, um, carbons to get the most stable carbon cattle. And so if I go from the left here, I would have tertiary on number two in Turkey. Area number four. I went from the right. I would have secondary unto in primary and four, so I definitely want both of those tertiary res. So we're gonna go this direction and then do the same process so my one to bond will grow up the hydrogen and kick off that chlorine and we'll get a carbo cat ion that looks like this for that one and then not will have a residence contributor. That looks like this for that over here. Um, and if you'll notice these, they're actually the same thing. Just flipped over. So if you were to have your hand on a table with your palm facing up and you flipped it over so your problem is facing down, you would get, uh, the other version of this actually, the same the same structure. So, um, here we're actually on only going to get one product. It's what that is the 12 and the 14 product. It will be exactly the same. Um, and so that products. Oops. Well, look like this. I'm just gonna draw it on this side of the glory will be here, and the double bond will be over here, so that is our products. That is obviously going to be both the kinetic and thermodynamic products, since it is the 12 and the one for product. So this is Medic and thermo, since it's 12 and 14 at the same time.

Richard. Yeah. Mhm. Mhm. Yeah, Yeah. Julie. Yes! Yes, yes! Yeah! Mhm. Mhm. Yeah, Yeah, yeah, yeah, Exactly. I actually have a here. Want me to bring it down? That's cool. That's fine. All right, let's go. All right. Please. Yeah. Mhm. Yeah. Prison. What? Yeah, that's right. Yeah, right. Uh huh. Mhm. Mhm. Yeah. Mhm. Yeah, sure. Yeah. Person Mhm. Yeah. Mhm. Yeah, Yeah, Yes! Yeah. See? Yeah. Anybody? Yeah, sure.

Whereas the neural structures of the products in the following reactions the first one is one fentanyl or just fentanyl with sodium discriminate, or the decree made ion mhm. And whenever you treat a primary alcohol with a strong oxidizing agent, like sodium discriminate or another example is lithium aluminium, hide with them aluminum hydride. You're gonna get a car box silk acid. So we have pet milk acid. The second one is broderick acid. Mhm with ethanol. Yeah, the presence of an acid. So the first step is that the is pronation of the acid, where the hydroxide grabs hydrogen from H three plus and turns into a better leaving group. So it leaves. We don't have a primary carbon cat iron. Yeah, The next step is for ethanol to attack it, giving us this structure the positive charge because they don't need a pair of electrons, they were negative. The final step is for the sulfuric acid that lost parts on and the first step to take it back, giving us a foxy substitute. So we have Ethel, do you know it to, um, the beetle is the four carbons and the oh, it is just the kitchen with Esther. Yeah, So the last one is two math award beauty with HBR. So they are keen is the nuclear file. Its electron rich pertains Electra fall. You pull a response so it takes both electrons. You know, I have a tertiary carbon cat on which is more stable than secondary or primary, because the method is an electron donating group that stabilizes the carbon cast iron view the inductive effect. The final step is for bring me into attack it giving us this two bromo two metal butane.


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