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Fill up the empty boxes with the correct chemical structures: (15 points total)CablCh...

Question

Fill up the empty boxes with the correct chemical structures: (15 points total)CablCh

Fill up the empty boxes with the correct chemical structures: (15 points total) Cabl Ch



Answers

Fill in the boxes with the appropriate reagents:

Okay. This problem is asking us to show the necessary reagents in order to make the following transformations. So let's go ahead and identify the 1st 1 So, for this 1st 1 I see that I have an Al Keen, and I'm going to transform it into a primary alcohol. So if I have my O keane right there, in which you have 1234 carbons and I end up with four carbons. 1234 and I have my alcohol in that last carbon. Then that means that I had to produce my alcohol and I had to put it into this fourth carbon. Okay? And that would be the less substance side of while came. And I know that in order to add an alcohol, the last up to the least up suit inside of my cocaine, I need to use the regents be age three T h f and sodium hydroxide, hydrogen peroxide and water. Okay. And that is called hydra operation. It essentially adds an alcohol to the list to the least subsidy side of my Okay. Okay. So now I'm transforming in my primary alcohol into this, in which I have an l king. And this is going to be a die subsidy, joking because on this arcane, I have my carbons. And then I have the connection to only one other carbon on each of those carpets. Okay, so that's a dice opposite of cocaine, which is more stable than a model subsidy, oking, which is what we started out with right here. Okay, so let's go ahead and identify this in order to make it all came in the first place, starting with an L cane, starting with an alcohol. We sure to use the radiance of acid and heat it. And then we can make necessary transformations after that. But those air the go to regions so acid and heat Maisto us a four and heat Well, that's produced the necessary product. Let's see. So, first up, I'm going to protein ate my alcohol with my acid. So is to posit charge. And I'm gonna make that leave. Okay, But if I make that leave, I'm gonna end up with a primary carbon cotton right there. So primary carbon ketones are not favorable. So at the same time that I have my water leave, I'm going to have to de protein eight. This hydrogen when it deponent that carbon with water. Okay, so just like that, I'm gonna have to move the electrons from that carbon 100 bond onto that carbon carbon bonds. Okay, so that's going to produce this intermediate ch two siege to and then ch two anymore. It's just ch, and that's connected to ch two. So this right here is what I started out with at the very beginning. Okay, But this is actually gonna undergo another reaction with itself. So after I impregnated my always to I will have produced, um, Hydro me, um, which is 300 units attached to my auctions. Okay, so that means that this is considered the acidic. I'm gonna go ahead and Protein ate my Elke just like that, moving the electrons onto the oxygen, producing this new intermediate huge too ch. And then c h three with a positive charge on this carpet. Okay, so this carbon needs to undergo, or this particular subject substance needs to undergo another elimination reaction in which I have a deep rotation step to relieve this carpet of its positive charge. So again, I have water in the solution that water is going to deep rotate this 100 in this time to produce a keen onto that carbon between this carbon and this carbon. Okay, And then that will produce my desired product, which is right here. So it's basically two steps with just this single reaction. Okay, next up, we need to make this die subsidy cocaine into an al hide. So let's identify how many carbons we have. 1234 And we need We're going to produce only one, too. So we need to shorten our carbon chain and half essentially, and the region, in order to do that is called those analysis. So that's 03 So one step two step is my dimethyl sulfide. Okay? And that essentially just splits apart my bond in my cocaine in half and adds an auction to both sides. Okay. And that's going to produce this compound right here. Okay, so next up is this one so same thing I start off with same exact substance. 1234 carbons. I'm going to produce a primary alcohol. So same exact things before we use hide reparation, which is B H three to you, Jeff. That's the solvent and then the second step of sodium hydroxide, hydrogen peroxide and water again as my alcohol to the list to the least subsidy side of my feet. Now I'm gonna produce from my primary alcohol this compound in which I have 1234 carbons. And I started out with 1234 carbon. So I didn't get rid of any carbons like I did in the previous one and said I got I kept the same number of carbons. All I did was oxidize my compound right here. I haven't alcohol, and right here I haven't Alba hide. So there, Agent. Necessary to do that is just any standard, um, not super strong oxides agent. So, such as H o CEO, that's going to oxidize my alcohol, my primary alcohol into another hide. If we're to you something super strong like h two c r. A four. That would be Jones. Regent Jones reagent would oxidize my primary alcohol all the way into a carb oxalic acid, which we don't want. Okay, so next up, I'm going to produce from this cycle. Heck, seen a bro most cycle Hexi. Okay, so what I'm gonna do is all I need is HBR. What that essentially does is prone. It's my cocaine. And then Groman is gonna come in as a nuclear file. Okay, Now, starting from my bro me, I need to produce this my alcohol. So the region needed to do this is simply and a ohh sodium hydroxide. Okay, this is going to be an S n two reaction because sodium hydroxide, even though, is a good base. It is also a good nuclear file. So it's going to come in and replace. I brought me like that, and I'm gonna move out that Romy. Okay, so this could actually form a mixture of the elimination product and the substitution product, but we're just going to go with the substitution product, OK, next up from this alcohol, we need to produce this key tone and the product or their agent needed to do that is simply a strong oxidizing agent. And this is a case in which we can use Jones region because this is only a secondary alcohol. Even if we're teams strong oxidizing agent, we're not gonna have a situation in which we produce and at carb oxalic acid, so we can use age too CR 04 for this one, okay. And then those would be the reason it's necessary to make those transformations.

You do syriza reactions have given in which they had to fill up the intimidates on board the reasons first one. But the North is converted, and so c est a b r. This is converted in your intermediate using re agents using two steps Malaysia and second is here on their syndrome. Idiot is converted into see it's date. See, it's too boy. Now we can see here the final product, he said Alcohol and there is no answer in this C s trivia. That means this whole thing has to come from one of these steps. One of these occasions should contain this region's who can be on this region should continue. Also get that means a primary alcohol. Can you obtain from, uh, often in a metallic reactions using for money head so we can write woman in here? So this is possibly for my behavior. That's after with the great not with organo metallic compound. So this can be it's here by yourself? A No, the organ. A metallic compound. It should be that reacts should be it. See it three twice. Look, see you away to paint di middle. You can live diameter desperate when the team, David different reacts with formerly headed that you get alcohol. So that means conversion of die middle A middle government toe became diameter to break involves treatment with lithium first and then reaction with papa related on the first step Formation of conversion off media alcohol in Duke CST br request TV a tree PBR three in presence of building necessary is it? We didn't celebrate the second series of reaction in wars. Uh, reacting meeting molecules. See it for converted into CS trivia again. On that CST beer is converted into intermediate in the same passion on Finally, the final product is so one more feet to for it again, we'll will follow the same strategy before the same strategy. You see a three ch 21 with you there is one more. See it too. So see, it's too for it now. This will be so There are two carbons to be introduced here we have only one carbon. So we were a to government species. So the two governments pieces which reacts with organic material. Reason is it is not so. So again, this final step will be reaction with little alongside on that will be welcome. Light. Finally it's here. Readability So again way We have C X three life. See you and night. So here it is Lithium. I'm good bread today I'm here also meeting you meet I Brahman is blowing. It's you and this will be access.

Class of chemical bonds where the valence electrons are shared between atoms. These are typically just non metals. Here. We're looking at lower structures and formal charges. So the first one we have here, We can draw out, we have c single one c. Taliban. Oh and then we can add on our hydrogen where we need to have to learn paths to the oxygen. So we have two carbon atoms, four hydrogen, one oxygen, and the carbon, hydrogen and oxygen atoms have 416 valence electrons respectively. The formal charges on all of the species is zero. So overall we have a formal charge of zero. So in other notation we could just write zero next to every single element Because the oxidation state is zero. So the next example we have is as follows, we've got N three. So we've got nitrogen double bond nitrogen, double bond nitrogen and we have an overall negative charge here. So each nitrogen atom has five valent electrons. So what we have here is the nitrogen is with to line pairs, we have a minus one charge associated with them. The central nitrogen has a plus one. The terminal nitrogen remember have a minus one. So overall What we have is -1 plus one at minus one. So overall we get -1 as the formal charge. Final example we have here. So we have carbon in the center and then we have carbon, triple bond nitrogen and then we have some hydrogen, so the nitrogen into one lone pair. And that accounts for why lone pairs and all of the species here. How was a formal charge of 0?

Class of chemical bonds where the valence electrons are shared between atoms. These are typically just non metals. Here. We're looking at lower structures and formal charges. So the first one we have here, We can draw out, we have c single one c. Taliban. Oh and then we can add on our hydrogen where we need to have to learn paths to the oxygen. So we have two carbon atoms, four hydrogen, one oxygen, and the carbon, hydrogen and oxygen atoms have 416 valence electrons respectively. The formal charges on all of the species is zero. So overall we have a formal charge of zero. So in other notation we could just write zero next to every single element Because the oxidation state is zero. So the next example we have is as follows, we've got N three. So we've got nitrogen double bond nitrogen, double bond nitrogen and we have an overall negative charge here. So each nitrogen atom has five valent electrons. So what we have here is the nitrogen is with to line pairs, we have a minus one charge associated with them. The central nitrogen has a plus one. The terminal nitrogen remember have a minus one. So overall What we have is -1 plus one at minus one. So overall we get -1 as the formal charge. Final example we have here. So we have carbon in the center and then we have carbon, triple bond nitrogen and then we have some hydrogen, so the nitrogen into one lone pair. And that accounts for why lone pairs and all of the species here. How was a formal charge of 0?


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