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A certain element consists of two stable isotopes_The first has an atomic mass of 34.9689 amu and percent natural abundance of 75.53 %. The second has an atomic mas...

Question

A certain element consists of two stable isotopes_The first has an atomic mass of 34.9689 amu and percent natural abundance of 75.53 %. The second has an atomic mass of 36.9474 amu and a percent natural abundance of 24.47 %_What is the atomic weight of the element?amu

A certain element consists of two stable isotopes_ The first has an atomic mass of 34.9689 amu and percent natural abundance of 75.53 %. The second has an atomic mass of 36.9474 amu and a percent natural abundance of 24.47 %_ What is the atomic weight of the element? amu



Answers

A certain element consists of two stable isotopes. The first has an atomic mass of 137.9068 amu and a percent natural abundance of $0.09 \% .$ The second has an atomic mass of 138.9061 amu and a percent natural abundance of $99.91 \% .$ What is the atomic mass of the element?

So from the textbook, we can't get the formula for to determine the atomic weight off element A. You cold pool the atomic weight off each office as a tope, say the first isotope in this instance, times the abundance off the first as a top plus the atomic weight off the 2nd 1 times the abundance off the second isotope. Plus it's acceptable. So if a substitute the numbers into I everyone into this formula, they can get one. The at home, the atomic weight off this element it's the atomic great. Off the first assault hope, which is 1 20 0.9038 a. M. You plums the 5 57 14 percent, which is the abundance off this first isotope. Plus they won 22 0.904 through a m you times one minus. Since they only highest to assert hopes, the abundance off the other after took is has Toby one miners. This abundance of the first I should hope on dhe by suffer duty all these numbers into the calculator we will get the answer which is 1 21 175 60 I am you, which is see atomic weight off the this impair element

Hello, everyone. And thanks for joining me, Miss Hallstrom, For a brief discussion on atomic mass First, atomic math is the weighted average of all naturally occurring occurring isotopes. Here's the equation that we would use to calculate atomic mass. It's equal to the mass of the first isotope times, the relative abundance of the first isotope. We add to that the mass of the second isotope times, the relative abundance of the second isotope. And we do this for each isotope for the element in question. Relative abundance. Okay, it is just percent. With the decimal moved to left. Let me show you if we had a number 71.42% that's our percent number. Our decimal would be 0.7 142 no units. So relative abundance is just the percent with the decimal moved back to to the left. When we add up, the some of all relative abundance is equal to one just like percent. When we add up, all the parts of a percent of equal to 100 to to the left of 100 is one. Let's do our problem for this problem. Were given the following information we have two isotopes, isotope one and isotope to but for isotope one were given a mass of 120 point 9038 AM use and were given a relative a percent abundant abundance of 57.4% which has road abundance of 0.574 Okay, I will switch colors for this isotope to we have a mass of 1 22 0.9042 atomic mass units. And we're not given our relative abundance here, but for step one, let's recall that the some clips to me that's some of relative abundance equals one. So one minus 0.574 equals zero point. Um, where my 4 to 6. So this wasn't given, but we know it. 0.4 to 6. And for step two, we're going to sub insolvent to our equation from the previous page. Okay, I'm going to abbreviate. Average atomic mass is a M. Average atomic mass is equal to the mass of isotope one times a relative abundance of isotope one plus the massive isotope to times a relative abundance of isotope to, and you're probably very capable figuring this the rest of this out on your own. But since it's the first problem, I'll do this. The product of those two numbers is 69.40 Add to that the product of these two numbers, which is 52 0.36. Add them together and I get 1 21.76 and those Aaron units of AM use. The final answer, reported to the correct number of sick gigs, is 1 21 0.8 I am use. And that's our first problem for atomic mass units. Thanks for watching.

From the given that we can find that the element has twice adopts and the facts in abundance. Also given for the same to identify the unknown element from the given data. Multiply the isotopic mask with the fractional governance and then something of the obtained value gives the atomic weight of unknown element. That's for the first S. A. Jobs. That isotopic masses 49 wine 9472 Atomic months unit. This is multiplied by factional abundance. 0.00 to fight. This is equals to your appoint 1-4 868 atomic mass unit. For a second. I saw dogs. The isotopic mass is 15.944 zero. Atomic mass unique. Is multiplied by vaccinate abundance. 0.997. Right. This is equals two 50 0.81 66 What atomic mass unit? Now summing up the obtained values therefore some is 50 point eight. Sorry 50.9 50.9 415 atomic mass. You need. Now running of value is hippie 194 Atomic Mass Unit. Hence the atomic weight of element is 50.94 atomic mass unit. These measures with the element when Indians, Therefore the unknown element is mhm. They're not. Element is when idea with atomic mass 50.94 Atomic Mass Unit.

Hi everyone. So in this question they have given naturally occurring silver concession to a sort of one of the I sort of says a mass of 106.90509 A. M. U. I'm 51.84% abundance. What is the atomic mass of the other is sort of so master first I sort of physical 106.90509 AM you percentage abundance of pushed a sort of 51.84%. And that's operational isotopic abundance is equal to 51.84 upon 100. That is he called the .5184. So silver mass number on the periodic table 107.87 AM you so atomic mass up. I thought of one physical 106 by 90509 into 0.5 and 84. That's called 55.4196 AM you. So therefore 107.87 minus 55.4196 That is called to 52.4504 a. M. So one minus 10.51 84. That is equal 2.4816 So massive fedora is set up. That is equal to 52.450 for upon 0.48169 is equal 108.90863 AM you. The mass of powder I set up of silver is 108.909 AM you nuclear symbol for silver 47 8.


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