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3:38Homework: LO1 Homewo Score: 0 af 1 pt 3.10,15 Evaluate t dealive @th borngarton [cot "(iwj]l "(=...

Question

3:38Homework: LO1 Homewo Score: 0 af 1 pt 3.10,15 Evaluate t dealive @th borngarton [cot "(iwj]l "(=

3:38 Homework: LO1 Homewo Score: 0 af 1 pt 3.10,15 Evaluate t dealive @th borngarton [cot "(iwj]l "(=



Answers

For the following exercises, use reference angles to evaluate the expression.
If $\cot t=9.23,$ what is the $\cot (-t) ?$

So here in this problem we have to determine the sign of the given functions and the given function is the first one is Contingent of 110°.. The next one is second 309 degree. Now here we see that this one is the first quadrant, this one is the second quadrant, this one is the third quadrant, and finally this one is the fourth quadrant. Now in the first quadrant, this one all trick geometric functions are positive and the second quadrant only the sign theater and the classic interior is positive. Other trigonometry functions are negative. Similarly in the third quarter only change in theater and contingent theater are positive, others are negative. And similarly for the fourth quarter the first function is got injured 110 degree. This angle lies in this quadrant and in this squadron contagion theater is negative from the advance contingent 110° is negative. The next one is the 2nd 309 degree which lies in this quadrant. and in this squadron second today is positive. That means the second 309 Degree is positive. So this is the solution for the given problem. I hope you have understood the problem. Thank you.

Internal cool See D dying Cody? Yeah, yeah, DT 5.6 to buy a bond to. So here we know that the integral of calls a t time Coty which is okay. Mega do mhm coz e d 5.6 two 5.2 So here we put the limits and we get negative. Cool. See by 8.2 negative. Go See 5.6. Now we put the limit of Kosek 5.2 and Kosek 5.6. So here we get negative one negative two. So we get one and it is all final answer.

Okay. We want to use a calculator to find the co tangent of 270°.. 1st of all, the tangent is one over the tangent of 270°.. And if we do one over the tangent of 2 70 we're going to get um zero. Yeah, that's a post is a good calculator. You get zero because someone calculated some of your hand helps. Might tell you that it's undefined, but it isn't. It is actually zero. Okay.

In this question. We are going to evaluate the given trig functions using the unit circle. Yeah. Yeah. Second of 135° is one over co sign Of 135°. Yes, Co sign of 135° Is negative route to over two. Yeah. So we can take one and multiply by the reciprocal. We need to rationalize we get negative to route to over two and two divided by two is one 2nd of 135° is negative route to Yeah. Mhm. Next casa can't is the reciprocal of sign? No. Yeah. The sign of 210° Is -1/2. Yeah multiply by the reciprocal and we know that Co seeking of 210° is negative. two tangent is sine over. Co sign. Yeah, Sign of 60° Is Route 3/2. Mhm. Co sign of 60° is 1/2 multiply either. Reciprocal two divided by two is 1 Tangent of 60° is Route three. Mhm. And finally. Okay. Co tangent is co sign and over signed. Co sign of 225° is negative route to over two. So is sign of 225°. That makes co tangent of 225° positive one


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