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Identify the absolute configuration of the chirality centers in each of the following compounds as R or S: Note: if multiple chirality centers are present; indicate...

Question

Identify the absolute configuration of the chirality centers in each of the following compounds as R or S: Note: if multiple chirality centers are present; indicate the stereochemical designations as: RR, SS, RS or SR (Other terms used for 'chirality center include chiral center; stereocenter; and stereogenic center:)CH3COzHRR SS SR RSCOzH

Identify the absolute configuration of the chirality centers in each of the following compounds as R or S: Note: if multiple chirality centers are present; indicate the stereochemical designations as: RR, SS, RS or SR (Other terms used for 'chirality center include chiral center; stereocenter; and stereogenic center:) CH3 COzH RR SS SR RS COzH



Answers

Which of the following molecules are chiral? Identify the chirality center(s) in each.

So we're continuing to work with Stereo is a MERS and so this is defined as the branch of chemistry that is concerned with a three dimensional arrangement of atoms and molecules in space and how this effects are chemical reactivity. So starting with example, A to the compounds are the same and they have the S configuration. If we rotate them, you can see that we have the same compound moving on to the second example we have financial mus, so these are non super impossible mirror images. So that example is Dia stereo Eisner's. They are not super imposible, non mirror images. So for our next example, we have the one s thio ask configuration and now the same compound. Just simply rotating one of them will reveal that to us. Next, we have a pair off dia stereo. I summers So we have the two configurations the one Earth to us one our to our next we have constitutionalism er's So this means that we have the same molecular formula A different arrangement of atoms, different connectivity of atoms mixed you up, Dia Steri rice. Once again following this, we have a non Chalmers. Next we have same compound. Next we have different compliments of the same molecule. Almost a the end. Now with our list, we have financials. So with this one that was came I missed a Kyra page again. So we have Dia story. Oh, is a MERS. Well, we have the same compound with and we have diced terrorism er's following And we have constitutionalism er's after and we have oh, peaky left. So we have diced story I summers, Pete, we have the same molecule as we do for Q on both have no Kyrill centers.

Enabling us to assign our or s configuration to the Cairo Center. In each of the following molecules, it's was go ahead and start with the one and A We have so in this case. So we already have. Hydrogen is our lowest priority groups, so there's no shoes there that it's already in the back. It's actually let's go ahead and draw a Mach one just so we complete the numbers down. So we have four. Get this in the front like that. Free now between a sulfur, a carbon and a carbon, the sulfur has higher priority. So are one is gonna be facing towards us, then we need decide. Well, what has higher priority. So actual. Let's draw with this group out, so that should be a car box. Cilic. How's it? And then over here we just have three hydrogen is attached. So if we do the little punch out game, notice that well, we have a hydrogen and then this carbon. Actually, it's the re oxygen's attached to it. So because of that, the car box so gas is gonna take higher priority, so we'd have to there and then we're going tohave three like that. So now all we need to do is to our rotation, since our lowest part of group is in the back and so we're going to rotate and like this here. So the way I like to remember this is so when you're drawing and are you draw it like this it's a notice that the curve goes like that. So this is going to be to the rate or are or you just remember our is to the right and then for us, a lot of time are normally when you draw on us, you start up here and the rotation goes like that. So this is going to be to the left. So notice over here were rotating to the left. So that means this Cairo center here is going to be s. I was going in box that now for B, Let's go ahead and draw a little skeleton to start. So it's gonna be like this here. You don't wanna do that. So, like that now, this hydrogen is going to be our lowest priority groups, so that's for sure going to be in the back. Then we're gonna compare a carbon, carbon and oxygen able oxygen has a higher priority between those. So because of that, we're going to have a one up top. So it's important that when you're doing this priority that you don't look too far down the line. Because if we were to let's erase this and draw it out as well. So we draw this out, you might be tempted. Say, Oh, well, there's essentially three Oxygen's down the line here, so that should have higher priority. But we have to go step by step and kind of do like this old knockout game. So because of that, this oxygen has the higher priority. So that's why it's one there. Now we need to compare this carbon that has an oxygen three oxygen's attached to this one over here that has three hydrogen. It's well, oxygen's have a higher priority than hydrogen. So that means over here that's gonna be two in the back in three on the other one. There, rich. Now we need to get four into the back. So what I'm going to do is I'm going to hold three here. I'm gonna pinch this one, and I'm gonna rotate Ford to 2 to 1 and then 1 to 4. And so after we do our rotation, so three hasn't moved Now one is gonna be in the front four is in the back, and then two is in the plane. So when we do our rotation now, notice is going to go. So we do 123 So it should go like this here. So this is rotating to the left. So this is going to be s as well now for our last one here. So this one's drawing a little bit differently. But we still have two groups facing forward us into groups facing a way. So let's go ahead and draw the skeleton for this again. So we have this little bowtie here essentially, and then we have two groups going back like that. So this hydrogen, what we already know hydrogen should have the lowest priority. And then would we first to go out well, we have carbons versus oxygen, so the oxygen has higher priority. Then we have to compare this carbon to that carbon. Well, this carbon appear has to oxygen's attached. Well, this one only has one, and it remember, that's to do toothy double bonds. So that's going to and then three. So now we want to get four in the back. So it doesn't matter if we put it here or here because both of those groups are facing away from us. So let's just go ahead and rotate it like this. We're going to first hold one in place and then rotate the other. So four goes 2 to 2, goes to three and then three goes to four. And doing that would gives a lib stroll E skeleton begin. So remember we pinched one and rotated the other one. So one is still there now, too. Should be on the very bottom three should be over here on the left and implores the up top. So now when we do our rotation, we go 123 like this. And now that is going to be so. We're rotating to the right this time, so that's going to be our So we end up with S s and then are for the Cairo ality for these centres

So this question asked us to assign configuration for each of the carol centers in each of the following molecules. So, looking at, we actually see for that For each of one of them, we're going to have two different ah Steri genic centers. And so I labeled one with green dot and one with blue dot just to guide my discussion. So, looking at or get a compound A I'm looking at the Cairo center that is designated with green dot and so I'm gonna go ahead and a sign configuration for that one. And so what I see here is when I designate my priority is that the oxygen, of course, is going to be prior to number one. And then we see that this carbon connected to the chloride or the chloral groups one to be number two. Um and then this carbon here connected to the rest of the chains gonna be three, and then our hydrogen is going to be number four. And so it looks like we are going clockwise, which we would normally say are However, we want our ah hydrogen to be going away from us. But here we see it's coming towards us. So instead of our it's actually going to be ah s. And so I would say, um, this group here is going to be s okay. And so now looking at the blue one, I'm gonna sign my party's for that Carl center, and I see that the coral group's gonna be number one, and then the, um, carbon connected to the hydroxy group is going to be never to, And then the carbon connect to the rest of the change. It's gonna be number three, and then the hydrogen is number four. And so what I see here is that right? I'm going counterclockwise. And so I would say that this s and I will in fact have s because the hydrogen is going away from us. So I go in, right? That here and that. That this parasite is s okay. And now, looking at B, I'm gonna go ahead and look at the Green Carl center. And what I see here is that our priority number one is going to be, uh, this particular carbon here. Because if we go ahead and look and where were Ah, well, this one's a little bit tricky. So Let's actually take a step back here. Ah, and we go ahead and compare the next carbons. So that would be this one, This one and this one. And we see that they're all ch to write and say we're going to have to go to the next carbon. And so that would be this one, which we see is connected. Teoh to two carbons and one hydrogen. Oh, and then we see that, um, this one here is connected. Teoh One carve it into hydrogen. Whereas this carpet here is connected. Teoh three hydrogen is right and so we can designate priority based on that, right? So I'm gonna go and take away all those dots away. And so what we see here is that this What we saw is that this is the highest priority because eventually it's going to be connected to mark our bins. And then this is the second highest priority. And then this is the the the third priority because it's eventually gonna be connected to just three hydrogen. And then we have our hydrogen, of course, which is priority number four. And so what we see here is looks like we are going clockwise, which we would normally say are. However, we want our hydrogen to be going away from us. And so we would say we would designate that as s instead and now we could do the same thing for the right side here. And of course, we're gonna sign the same priority. So this particular Carmen is gonna be number one because it will be connected to mark our bits on. Then this is going to be too. And then this is going to be three because it eventually only be connected to three hydrogen. And then we have the hydrogen is number four. And so what we see here is we're going looks like counterclockwise, and this will in fact be s because they're hydrogen is going away from us. And so that stereo center will be ah s. And now, looking at our compound C would go ahead and look at the Karl Center. Ah, the green Carl Center. And of course, our oxygen is going to be number one. And then this carbon is going to be number two because it it'll eventually be connected to the hydroxide group and therefore this is going to be three because it will be connected to more carbons. And then our method group will be priority number four because it's only gonna be connected to three different hydrogen. Okay. And so what we see here is looks like we are going clockwise. And this would be the case because our Lloris pirate a group, which is our method, is going away from us. And so we are actually going to have the are configuration here and then for the, uh, the blue ah stereo genic center and do the same priorities here. So, of course, our oxygen number one, our ah carbon here, which will be eventually connected to the hydroxide group, will be number two and then we'll have number three here. And then, of course, our method group will be number four because it's connected to our three hydrogen. The carbon is connected to do 300 ends. And so what we see here is that we're going counterclockwise and this is great. We're actually going to have the s configuration because the lowest priority group, which is our method group, is going away from us, which is exactly what we want. So those will be all of the the configurations for each of the Carl's

So we have to organic molecules here, and we want to go ahead and identify the Cairo centers as well as a sign that configuration for each Carl center. So looking at, ah, organic compound A here, um, looks like we have two different carl centers and with so I'll go ahead and to note one with a red here a little red dot So that's gonna be one Kyle center because it is connected to four different groups are connected to our method group are hydrogen are promo, and then the rest of the parent chain are two carbons and as well as the promo and hydrogen. So you would say that is a different group. Um, so another Carl center is gonna be this one here. We'll go ahead and drawing and green this time, so it'll be easier for me. Teoh refer to later. And of course, we can say the same thing that it's connected to the four different chains as well and now looking ATS organic Compound B. Um, we see that we have a carl center right here because it is connected to the final group the hydrogen, the alcohol group and the, um rest the parent chain. The carpet sold acid. So we would say those air four different groups and then for this. Ah, this is another Carl center here because we are connected to our carpets. Silk acid are a mean our hydrogen and the rest of the parent chain, which is eventually connected to the final group. And so you would say that we do have four different groups there, and then we want to go ahead and a sign configuration for each Carol center. So I'll start with the organic compound A at the red one. So assigned my priorities. Priority number one goes to the broom. A group, of course, because it is the highest weight. And then this carbon is going to be number two as it is connected to the the promo group. And then this is our method group's gonna be number three and our Hodgins gonna be number four. And so it looks like we are going counterclockwise. And this is gonna be correct because we do have a hydrogen going away from us, which is desired. And so he would say that that is going to be on s right. And so now looking at the green one we see that are broken. Groups number once like before. And then the ah carbon connected to the Burma group just like before is gonna be number two and methods number three and Haider's number four. And so here looks like we're going counterclockwise as well. And this is great because our hydrogen is going away from us. And so this is also going to be an s. So for both of our Karl centers, air, we have s okay now looking at organic compound be. I'm gonna go ahead and refer to the red one here and a sign our priorities. So our drugs or groups will be number one because they're oxygen. And then, ah, this carbon here is going to be number two because it is connected to a nitrogen, Uh, which is, Ah, higher priority over the carbon. So that would be number two and then this is carbon is going to be number three and then our hydrogen is number four. It's, um looks like we are going counterclockwise. And we would say that this is correct because the hydrogen is going away from us, just like just like we want. And so we would say this is going to be asked as well and looking at the green here, I'm gonna sign A priorities are nitrogen is going to be number one as it has higher priority. Over the carbons are our car broke, Cilic ass. It's gonna be number two because this carbon is going to be bonded to oxygen three times, whereas the next carbon, which would be a number three here, it's only going to be bonded to the ah, the oxygen of the alcohol group once. And so that's the third priority, And then our hydrogen is going to be fourth priority. So here looks like we're going clockwise. And this is exactly what we're gonna get because they're 100 is going away from us just like we want it to be. And so he would say that this particular Cairo signer is going to be our and so that gives us all the Cairo centers reading from left to right for Compound A, we have S s. And for Compound B, we have s are


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