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Q1. Thc confusion matrix for classification mcthod with Class and Class 1S givcn bclow.Confusion Matrix Predicted classActual class221 30100 3000What arc thc pcrccn...

Question

Q1. Thc confusion matrix for classification mcthod with Class and Class 1S givcn bclow.Confusion Matrix Predicted classActual class221 30100 3000What arc thc pcrccnt crror ratcs for Class 0 and Class 1?003 and 0.2150.026 and 0.5710.012 and 0.317d. 0.010 and 0.312

Q1. Thc confusion matrix for classification mcthod with Class and Class 1S givcn bclow. Confusion Matrix Predicted class Actual class 221 30 100 3000 What arc thc pcrccnt crror ratcs for Class 0 and Class 1? 003 and 0.215 0.026 and 0.571 0.012 and 0.317 d. 0.010 and 0.312



Answers

Identify the class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary. The frequency distributions are based on real data from Appendix B. $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Age (yr) of Best Actress } \\ \text { When Oscar Was Won } \end{array} & \text { Frequency } \\ \hline 20-29 & 29 \\ \hline 30-39 & 34 \\ \hline 40-49 & 14 \\ \hline 50-59 & 3 \\ \hline 60-69 & 5 \\ \hline 70-79 & 1 \\ \hline 80-89 & 1 \\ \hline \end{array}$$

In problem sex. We have the frequency distribution for the age off best actors who one Oscars at winning. It's given in this table we have in the age when the best actor won the Oscar from 20 to 29 30 to 39 and so on. We have you lost two close from 70 years to 79 years on the frequency is given in this column you have one 28 36 15 61 It's required to calculate the close with the class made points class boundaries and the number the number off individuals. The number off individuals included in this analysts starting by the close with it's the difference between any conservative lower boundaries or about bounds. For example, we can get 30 minus 20 equals 30 minus 20 equal stone. This is the width off each close. For the close mid points, we get the average between the lower and the higher the upper boundary in each close. For example, this is the lower for this close, and this is the uber, then the midpoint is 50 plus 59 divided by two, which equals 54.5 years. Then the classmate points for all the closest. We just add 4.5 to the lower bones. We have 24.5, 34.5, 54.5 54. This is 44.5 54.5, 64.5 and finally 74.5. And for the class boundaries we have here 123456 we have six classes, which means we have seven boundaries. For each close, we have a lower cross boundary and on other class bound. The close boundary is the number between the lower frequency and the previous higher frequency, which is this one. The average between these two numbers is 69.5, which means we just add 4.5 toe the lower. We just add 4.5 toe. The other boundaries I exist. We adhere seven 9.5, we had 4.5 or we subtract 4.5 from the lower frequency. For example, here we subtract 4.5 from 20 we have 20.5 then the class boundaries are 19.5, 29.5 39 by in five 49.5 39. 59 0.5, 69.5 and finally 79.5. We have £8. We have seven boundaries. Four. The six close. Finally, for the number of individuals included in this study, it's just the number of actors we can get it, boy. Calculating the sum for all these numbers it equals want plus 28. 36 was 15 lost six plus one equals 87 individuals, and this is the final answer. Our problem.

In problem seven. We have the frequency distribution for the blood platelet count off males given in this table we have here the count and the closest is from 0 to 99 100 199 and so on. 400 500 finally 600 to 699. And the frequency is given in this column 1 51 90 can 001 It required to calculate the close with and close made points and close boundaries. And finally, the number off individuals included in this study starting by the class with we can create a close with by subtracting any lower or upper frequency from the previous lower or about frequency, respectively. For example, it take 100 minus. The previous lower frequency 100 by 90 equals 100. A recount for the classmate points. We just get the average between the lower and the upper frequency off each close. For example, we add 200 to 299 then divide by two. We got 200 49 by in five, which means we just add 49.5 to the lower frequency of each clause, which means we have 49 0.5, 149.5, 249.5, 349.5, 400 49.5, 500 and 49.5. And finally we have 649.5. We have six made points 46 six close. We have seven mid points for the seven class. For the class boundaries, we have seven clauses, which means we have eight close bombs for each close. We have a boundary from above on a boundary from no, we can calculate each boundary by getting the number between 600 which is the lower frequency here and the previous lower upper frequency. The previous other frequency, the bravest. Our frequency is 599 and the number in between is 599.5. We just add 0, 00.5 toe the other frequency or we subtract 4.5 from the lower frequency, which means we have here the lower boundary or the lower boundary for the class. The class boundary is minus or boy in five minus 4.5. Then we have 99.5, 199.5, 299.5, 399.5, 499.5, 599.5. I'm finally 699.5. We must have eight class boundaries for the seven close. Finally, the number of individuals included in this study is just the number of meals, and it can be calculated using the summation off all these frequents. She means it equals one. Class 51 plus 90 plus 10 plus zero plus zero plus one equals 153 individual, and this is the final answer off our property.

Problem it we have the blood platelet count females given in this step. We have you the account from 100 who are mounted on 99. The first close, the second close 202 199 and so on. And we have in the last two close the frequencies are given in this column you have 25 92 28 zero and two. It's required to concrete the class with classmate Boynes, close boundaries and finally, the number off individuals included in this study for the class with we can calculate it by subtracting any lower frequency from its A previous one. For example, 200 minus 100 equals 200 minus 100 which gives 100 100 count for the classmate points. We just get the average or the midpoint between the lower frequency or the lower boundary, the lower boundary for each of clothes, and it's our boundary. For this close, we can create the midpoint by adding 303 199 then divide by two, which gives 300 49.5, which means we can just add for 49.5 so the lower boundary for each close then the classmate points is 149.5, 249.5, 349.5, 400 49.5 and finally 549.5 For the class boundaries we have here five close, which means we have six close bumps for each close. We have a boundary here on the boundary here for the above boundary. We just get the number between the other frequency off these clothes and the following lower frequency. Lower boundary. Sorry. The average between this number and this number, which means we just add 4.5. So the other frequency or subtract Oh boy. In five, from the lower boundary, we add 4.5 the lower to the upper boundary and subtract 4.5 from the lower bound. Then we can get the class boundaries from here. The first one we just subtract over and five from 100 which gives 99 one in five. Then we add 4.5 toe the upper bounds 190 100 99.5, 299.5, 300 99.5, 499.5 on finally, 599.5, we have six class boundaries, 45 classes. And to get the number of individuals included in this study, we just add all frequencies together. ID equals 25 plus 92 plus 28 plus zero plus two, which equals we have 30 40 30 55 100 4147 in the video, and this is the final answer off our problem.

Okay, So what we have here is a prepaid for May thinks we're in. We're asked to get its reduced role as you import minutes round. So based from our previous lessons, we need to convert this first with its role. Excellent form. So that means it's drunk and to go further operations to convert it to reduce grow. Actually, for so the industrial accident for has the same operations Withrow excellent form. But that's different. Very here. Yeah. So we say that a matrix is in its reduced erosion and port if it satisfies the requirements first, the first non zero number in the first of all is the number. What second? The second row also starts with the number one, which is further to the right than the leading into the first room for every subsequent room, the number one must be further to the right, so it should look like this. We sure Sambo sister keys they're living and in each row must be the only non zero number it's called, and finally, and in an zeros are placed at the bottom of the matrix. So we can do this by performing syriza elementary row operations, including inter changing wonder with another multiplying one grow bananas zero constant and replacing one drug with one drop plus a constant times another grow. So with this example, we're going to convict this first its role petulant for okay, So first step A What we're going to do now is the trans seldom leaving for efficient off artery by doing all right, buddy is equal toe artery minus 2/3 off are you by doing that? We now have zero one go one zero ready one who and 00 negative to over three and negative 1/3. If you are, don't notice this is already in its role echelon farm. So we are asked to the meat It's Trump and by definition, round is the maximum number off leaner, independent foreign Imitrex, which is equivalent to the number off non zeros in its role, petulant the tricks. So for our example, we have 12 and three rows with non zero element which is rolled. One broke through in the three, therefore our runk history. So we're not done yet since we are asked to get its reduce grow at you, look for so for over next step We want to make zeros in calling toe. Except the entry. A throw one called to good. This we need to sub drop. But he are one from art. Now we have zero one don't. One 00 negative. Five negative one and then 00 Negatives to over three and negative. 1/3 for a step. See, we want to make zeros in column three except the entry A troll toe fall of three. To do this, we need toe divide Are too. We'll make it the fight by doing that, we now have zero one. Oh, one 001 one over. Fine. 00 Negatives to over three and negative 1/3. We're a next step. We are going to send it up. So I do. From what? That we now have zero 10 30 over. Five 001 1/5 and 00 Negative over three. And they get the one over the next. We want to add. Roto won't be played by 2/3 to wrote three. So by doing that, we know how. Zero 10 pretty over five 001 in 1/5. Then 000 negative one Oversight for step if we want the MiG zeros in column four Except the entry a throw pre called before to do these We had raw three multiplied by 301 By doing that, we now have 0100 zero 01 in 1/5, then 000 negative one over. Fight for step G. We want to I proto and what city. And with that we now have cereal. 100 0010 000 Negative 1/5. So far, our find us that we are just going to multiply artery win negative fight. So our reduced Groeschel inform therefore is 01000010 and then 000 one. So this is our final answer with cheese The reduce grow excellent for off the meetings.


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