Hi there. In this problem, we were asked to evaluate this triple integral. So as always, let's start from the inside Out. And let's just focus on this inner integral with respect to X. So as always. Just so we don't forget where we are. Well copy these outer to integral. But we're really just focusing on the inner integral in this step. So we need the anti derivative of why times sine Z with respect to X. Luckily for us. Uh, since we're with respect to X, Y and Z are both those constants. So you really can pull those out. In other words. Think of this whole thing as why? Uh, why Sandy Times 1? Um, so the anti derivative with respect to X is just X. Right? And then times this constant and we pulled out. Okay. Um, the limits of integration then should go right here. As always. This is just just like calderon. And we'll evaluate by plugging in Hi in zero for X. And that's attracting. Okay, so the Y signs the those will stay there since they're outside the brackets. And if we plug in pie for X. And subtract, I'll write it out. We plug in pi for X. And then subtract the results of plugging in zero for X. Well, clearly this will just end up as pie right here. I'll give you a couple of seconds to look at that. But I'm pretty sure at this point in Calif three you can look at this and realize, well, everything here just becomes pie. In other words, we just get why sci fi times pi and we can pull that pie out to the very outside if we want. So why don't we do that at this step? Just so it looks a little easier. So, there's times pi here since pie is a constant, we can just pull that to the outside. All right. So we went from three into girls down to two. That is going in the right direction. Now again, we'll start from the inside. And now this is with respect to the variable. Why? So, we are going to need the anti derivative of all this with respect to Y. Well, again, sign Z can be pulled out since the Z is a constant. We're only uh finding anti derivative with respect to why and the anti derivative of the Y. Part. We know what that is. That's why I squared over two. And again, the pie in the zero as the limits of integration will put those there. And let's see what we get. So, we get signs E. Okay? So, if we plug in pi for why we get pi squared over two, then if we plug in At zero for why? Zero squared over two, which of course becomes zero. All right, So let's see where we are copying the outside. You get signs E. In this hole Heart here is just pi squared over two. So again those are all constants. Let's pull those out to the outside. Just makes your life easier. So pi times pi squared is pi the third all over two. So that's our constant on the very outside. And the good news is we are down to one variable just dizzy. So this should feel exactly like a calico an integral because it is Uh huh. Anti derivative of sine Z. Is minus. Cosine Z. Yeah. And we're plugging in one and 0. So let's see if we get minus co sign of one minus minus will make that a big plus Co sign of zero. So we're basically done. Let's just simplify what we can here, Coastline of one. We really can't simplify but coastline of zero we can co sign of zero is just the number one. So this certainly could be a final answer or if you prefer to change the order. Either way we get part of the 3rd over two times 1 minus the co sign of one. And we are done. And hopefully this was helpful.