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The product isolatcd from reaclion had mass ol 53.2 grams If the reaction percent yield was equal to 77.29, wnzt was the theoretical vield of the eaction?27.88110.g...

Question

The product isolatcd from reaclion had mass ol 53.2 grams If the reaction percent yield was equal to 77.29, wnzt was the theoretical vield of the eaction?27.88110.g411668.9182 %

The product isolatcd from reaclion had mass ol 53.2 grams If the reaction percent yield was equal to 77.29, wnzt was the theoretical vield of the eaction? 27.88 110.g 4116 68.9 182 %



Answers

If the theoretical yield of a reaction is $24.8 \mathrm{g}$ and the actual yield is $18.5 \mathrm{g},$ what is the percent yield?

Find the percent yield. First, we're gonna multiply. Excuse me. Divide the Moeller, the masses of each reacting by their respective more mass. So for the Platen compound, this is equal to 415 point no. Nine grams for every mole. That means for this button compound. We have 0.0 8 to 4 moles of this potassium plotting carbide compound doing the same thing for the ammonia dividing. But it's molar mass, which is 17.3 brands. For every more we find that we have Europe 0.681 Moles of any three available notice that the multiple ratio here is 1 to 2. So I need twice as much ammonia as I have of this Platon compounds he pulling a platinum compound. Um, clearly, I have way more than twice as much ammonia, so that means that ammonia is my excess reactant. And this is my limiting reactant because it is limiting is gonna determine how much product this form. So I can basically ignore the ammonia for now and use this other reacting to the term and how much product is produced. Now. Notice that these also react in 1 to 1 more ratios. So that means for every one more all of this, I will make one mole of this pardon. So because of the 1 to 1 more mole ratio, I also get 0.8 to 4 moles of this button. However, um, we're gonna deal with mass when it comes to this button. So we're gonna multiply by the molar mass assist button, which is 300 point no. Five grams for everyone. More fun. Notice the small units cancel. We find that I would expect 2.47 grams of product. This is known as a theoretical yield. If I used up all the reactions that I made all the possible product, that's how much product that would expect. But I'm told that in reality I only made two point away grams compared to 2.47 So the percent yield is going to allow me to make this comparison. Using the ratio 2.8 grams divided by 2.47 grams, I'm gonna multiply by 100% to get a percent and find that the percent yield is equal to 84.1%

Yeah. Problem. 16. The DACA off you d believed. Can you take a yield off? The reaction is given they find 118 grand. They actually this 0.10 program. We have to find me West Indies deliberation. So personally, yield personally yield. Often the reaction equals. Actually, you divided theoretical need multiplies 100. So that a substitute of these values in this actually really 0.104 200 Where the bomb. You feel boring. 11 ft. This equals 88.14 year, 1% 88.1%.

So if you're given like a hypothetical reaction. Um and you have the amount of a. Let's put coefficients. You have the amount of of reacting A. Um that is available to react. And you know the actual amount of B that's produced. The person field would be the amount of B. That's actually formed over. Um The theoretical amount of the and what is the theoretical amount theoretical? Let me just write it first theoretical Amount would be and we multiply it by 100% because it's a percentage yield. So theoretical amount is if you know how much a. You have using strike geometry and the mole ratios, how much be could possibly be formed. Now if you use the moles of actual to theoretical yield, you have like you know some amount okay of moles of be over some other amount of mousavi. And then if you wanted to um find the the same percent yield in grams, you would be multiplying by um the molar mass of B. And then by the molar mass of be on both sides, top and the bottom. So the value of the fraction would not change except within like the magnitude of era of rounding in um where you run off the moles and where you run off the molar mass. Um But the ratios should be the same value for percent yield in moles and mass because of the fact that you're multiplying the top and the bottom by the same number to relate the two.

Kristen age. Look at that. Yeah. What is the theoretical yield in a chemical reaction? Political the politically in recent maximum. My mondo product forms maximum amount off the product that can be formed. That can be form in a chemical reaction based on the amount of limiting the haptic. These Tony Amonte up limiting Reacted. For example, if you take up Sorry, my drug side Al Attiyah reacting to form Syrian declaration water in terms of all our grilling. 40 g off shooting drugs here the actual 36.5 young. So why didn't already gas mhm to bomb get 15 hands off sodium glory so, I suppose, were provided with 42 g of sodium hydroxide and 36.5 grandma. It's silly. They you can see here. The limiting reactant is it's here. It's only one more when sweetie Majak cities more than one more. The slight exorcism, So 36.5 g will be completely consumed in the reaction and the maximum my mother, really that can be obtained is who create one high gloves for the employees on the reaction is with cerebral container year two branches foreign without Syria and reactive. So the theoretical real data maximum a model from 36 point where you can get a maximum 48 151 that is yeah.


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