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For the AP: Maximun frequency. Is 10000 The APIsecond refractory period 1s msec new action potential higher than Can be induced if & stimulus strength is the th...

Question

For the AP: Maximun frequency. Is 10000 The APIsecond refractory period 1s msec new action potential higher than Can be induced if & stimulus strength is the threshold considerably a+6 btc All of the above One ofthe following is not factor Passive inffecting the flow of ions across the cell membrane: The - transportation against the electrochemical permeability of the membrane, gradient_ Electrical Fields_ Diffusion gradient

For the AP: Maximun frequency. Is 10000 The APIsecond refractory period 1s msec new action potential higher than Can be induced if & stimulus strength is the threshold considerably a+6 btc All of the above One ofthe following is not factor Passive inffecting the flow of ions across the cell membrane: The - transportation against the electrochemical permeability of the membrane, gradient_ Electrical Fields_ Diffusion gradient



Answers

In the propagation of a nerve impulse: a. the refractory period begins as the $\mathrm{K}^{+}$ channel opens, allowing $\mathrm{K}^{+}$ ions to flow outward along their concentration gradient. b. $ \mathrm{Na}^{+}$ ions flow out of the axon with their concentration gradient. c. positive charges lower the membrane potential to its lowest action potential. d gated $\mathbb{K}^{+}$ channels open at the same time as the activation gate of $\mathrm{Na}^{+}$ channels closes. the depolarizing stimulus lowers the membrane potential to open the Na $^{+}$ gates.

Hello, everyone, this is Ricky and today working on problem number eight from chapter 35. All right, so I'm gonna be listing off the steps required for neurons fire an action potential. So first, we have membrane the polarization. And if you don't remember what the polarization means, that just means the membrane on the inside is becoming more positive relative to the outside. Then we have the polarization to threshold, and threshold is the value where where you see 50% of the voltage gated sodium channels activate, allowing for an action potential to be sent. I dont see action potential peak, right? This is when, uh, the inactivation of voltage gated sodium channels occur and you have actual potential for slash re polarization and then in some neurons Oh, and this is due to potassium we channels and the sodium potassium pump. And in some neurons, you have hyper polarization caused by voltage gated potassium channels. Um, so remember, for a neuron to fire an action potential, you need to hit a threshold. So what? This video was helpful and I will see you tonight

Mhm. This question is asking us about the action potential speed. Um and how it is influenced or by what factor it is influenced. So let us see how the action potential it's happening in the new on. So this is a neuron, this is the cell body. Mhm. This is the eggs on our main concern and this is the eggs on terminal. On the exam we have marlin sheet and the function of marlin sheet is to insulate the action potential. That means protect the signals, protect the action potential from losing it and increase its speed because violin sheet acts as an insulator. So it increases the speed of action potential. And that is one factor. Mhm. Mile and sheet which helps um us track the speed of action potential. And the second is the diameter of the exane. So as this is the eggs on. Right starting from here to here. So the bigger the diameter is the faster the action potential will go. So the diameter of the eggs on is the second factor that contributes an increasing the speed of action potential. So the correct answer is e, yeah thank you.

Yeah. Hello everyone. This is Ricky and today we're working on chapter 44. Um problem No seven. The rate of propagation of an action potential depends on a couple key factors. So let's draw and acts on. Or a neuron rather please forgive my ugly drawings. I studied biology, not art although to be honest understanding how to draw proper diagrams as biologists is extremely helpful in your understanding of material. But I digress so the rate of propagation of an actual potential depends on my inclination. The myelin is this fatty membrane wrapping that is produced by who yourselves such as alexander sites or Schwann cells. Depending on if you're in the central nervous system or the peripheral nervous system and myelin helps increase the rate of propagation by altering the capacitance of the membrane. Um If you don't know biophysics don't worry too much about that. Just know that the more tightly insulated the ax on the faster and actual potential can propagate. Um Another factor that goes into um that goes into action potential propagation speed is the and I'll draw kind of a close up. Yeah. Yeah. Yeah. Is the diameter cross sectional area which are both related of the Exxon itself. Hopefully this looks kind of cylindrical to all y'all. But basically as you increase diameter, the radius increases. Which increases the cross sectional area of the axon squared. If you don't understand the math, don't worry about it too much. Just know that with increasing exon exon of diameter um You have a proportional increase or you have a also an increase in the cross sectional area of the Exxon. And the larger that cross sectional area is, the faster that islands can propagate down this tube. Um So Myelin Chief and or Myelin Nation and cross sectional area or diameter of the Axiron are what determine provocations for you. Hopefully this video was helpful. I'll see you in the next one.

High. In the given problem, sodium irons are passing through the nerve cells, each having a charge off. Equal to that over a proton means this is 1.6 in two Standish Bar minus 19 Coulon. The number density off these so their minds. He's given us 5.6 into 10. Dish part 11. This much number off irons are passing through the nerve cells for meter, so the charge passing through than ourselves will be given. Ask you is equal toe end in tow e Here This charge is represented as e the charge of world our proton. So the total charge passing through the nerve cells will be given us. Q. Is going toe end into E and the time taken Baga. So the amounts to pass through the nerve cell is given us, then milliseconds. Or we can say this extent in tow tended bar minus three seconds, which comes out to be tended bar minus two seconds. So the current electric current passing through herself will be given by I is equal to total charge by total time, the time weight off flow off charge through the nerve cells, so that will be given s n e y d and spreading in on non values. This current he's given us 5.6 into 10 to ship our 11 into 1.6 into 10. Dish par minus 19. Cool. The total charge divided by 10 days for minus two second the total time. So this current comes out to be 8.96 in tow. 10. Dish par minus six emptier Or we can say this is I is equal toe 8.96 Microbe and beer, which is answer for given problem. Thank you.


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