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(b) Calculate 99 percent prediction interval for the demand for Fresh in the future sales period. Hint: n= 30 and 640 Optional technicab note needed. The distance v...

Question

(b) Calculate 99 percent prediction interval for the demand for Fresh in the future sales period. Hint: n= 30 and 640 Optional technicab note needed. The distance value equals Leverage (Round your answers to 5 decimal places:)99% PI [

(b) Calculate 99 percent prediction interval for the demand for Fresh in the future sales period. Hint: n= 30 and 640 Optional technicab note needed. The distance value equals Leverage (Round your answers to 5 decimal places:) 99% PI [



Answers

(A) Using the price-demand function $$ p(x)=75-3 x \quad 1 \leq x \leq 20 $$ from Problem $87,$ write the company's revenue function and indicate its domain. (B) Complete Table 10 , computing revenues to the nearest million dollars. (C) Plot the points from part (B) and sketch a graph of the revenue function using these points. Choose millions for the units on the horizontal and vertical axes

So for the given problem, we want to use the price demand function. P of X equals 2000 minus 60 X. And we want to write the company's revenue function and indicate the domain. So we know that the revenue function is equal to the price demand function times X. So really our revenue function just going to be 2000 acts minus 60 X squared. This ends up resulting in this graph right here that we see, but it's very tall. So we're going to rely on our calculator to find these different values. So if we have the X equals one in thousands, we're going to get the 1940 1000 that we have $1000 that we expected. We can also do five. We'll get this can 15, 20 and 25 that would be our final result.

Yeah. You want to use the function D. Of t equals three times the square root of t squared plus one minus 2.75 T. We want to find the rate of change. The average rate of change from t equals one until the end of the first quarter where one represents january 1st. We'll divide months in by four and you get the end of March which is March 31st. That actually come out to the 92nd day of the month. So our second time value is 92. That's again, March 31st. Right, so the average rate of change would be defined as the output of our second input. D of 92 minus. You know the difference of our outputs. So D F 92 majesty of one over those exact values those inputs. So what is D of 92? D of 92 would be three times the square root of 92 squared plus one. Last 2.75 time is 92. Yeah. Yeah. D of one is three times the square root of one squared plus one minus 2.75 times one. Yes. Going to a calculator here when we subtract these in the numerator you're going to get. Um Well I would set up that way. I'll just tell you here that once all of this goes into a calculator and we have three times the square root of 92 squared plus one minus 2.75 times 92 minus three times the square to one square plus one minus 2.75 times one over 91. Because that's 92 minus one, you get about two point approximately 0.236 Or an approximate rate of 236 units over the first quarter.

For problem 69 were given data were us a calculator Standard deviation using a calculator will computer. So if you had to do this manually you used this formula. My numerator represents the squared deviations. So ex miners you would be My deviation takes on my distances And you is my mean off the distances Onda ex miners, You are the deviations. So you scare the deviations and you send them all up. And then you divide them by n which is trainee whose end represents the number of observations. Then you take the square root of this entire fraction. It would give us standard deviation off 34.5. Thank you.

Okay, so we're given the following equation where X is the number of years. So for part A, we want to find, um, the cells. During years old threats us applied at X is equal to girl. That gives us 1000 minus 800 times one. So that gives us 200. And now, for part B, we want to find tell me years it details will reach 500 units. So that is S A T is equal to 500. And that's equal to our equation. And we want to solve for X, which is our number of years. So we'll subject when that was the number of sites. Okay, and now, dividing by 800 or negative eight on your on both sides, we get 5/8 is equal to eat a negative. X will take the natural law global sides to bring down that negative X So we have Ellen of 5/8 is equal to negative X so X is equal to negative. Ellen of 5/8 and thats approximately zero points 47 years and l for part c. We want to find the same thing. But for 1000 units so that 1000 is equal to 1000 minus 800 U to the power of negative X. So what's the track? That one. The other number of sides, so that zero is equal to have fallen. Dividing by, um, 800 on both sides, we get zero is equal to eat a crab Negative X and, well, we know that e to the negative X is never equal to zero. So that means that are function as some tea will never reach 1000 units and now reports d wants to see if there's a limit on the sales for our products. So we see if we read our our our equation, we see that if X gets really large than eating the negative axe, what that's equal to Dio and in that several times 800. So we see that we have a upper bound, and that's at 1000


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