5

(15) Show the mechanism for ONE of the reactions below. (Cross out the one not graded)CH;CH,NHCHIloH,o...

Question

(15) Show the mechanism for ONE of the reactions below. (Cross out the one not graded)CH;CH,NHCHIloH,o

(15) Show the mechanism for ONE of the reactions below. (Cross out the one not graded) CH;CH,NHCH Ilo H,o



Answers

Propose a mechanism for the reaction shown below:

This is the answer to Chapter 11. Problem number 67 Fromthe Smith Organic chemistry textbook. Ah, and here were asked to draw a stepwise mechanism or about this intra molecular reaction. So we're going from one ring, 22 rings. Ah, and we have an AL kind and an alcohol on a double bond inside the ring on the double bun inside the ring actually isn't isn't going to do anything. Ah, and so this is gonna be a reaction featuring the alcohol in the alkaline. And so we have former gas it here. Ah, and the first step in this reaction is going to be form a gas it protein aiding this alcohol that's gonna look like this. So we now have the pro donated alcohol here. Okay. Uh, and so, uh, this carbon oxygen bond can break, and, uh, the H 20 here can leave as water. Oops. And so we now have a corporal cat eye on here. Um, and the electrons in the al kind can, uh, act as nuclear file. These electrons can a shift over here to the carbo cat eye on. And so that's gonna be how we form our second five members ring here, so we now have Ah, a fused by cyclic ring system. So these two rings, uh, so have our double bond there. Ah, And now have this here. Okay. And we'll have a corporal cat eye on on this Corben. Um, and so there's water in this system, uh, in the water is going to add to that carbo cat eye on. So this, um, So now, after that, we have this product, so there's a positive charge and only one lone pair, uh, on the oxygen here, Um, and so we can, um, use that form a tie on from the first step. Uh, so this guy's still floating around. Ah. Native charge there can come and grab a proton. And, uh, after that happens, we will be, um, in an eternal form. I'm actually gonna move this a little bit. Okay? So, as I said, we'll have Ah, the eternal here. And so from the e. No, um, we can, uh, essentially just talk to memorize. Um, but the actual mechanism for that is gonna look like this. So we have former gas it again. Uh, the electrons of this double bond will grab proton comm protein ated. And so we will be here with a carbo cat eye on here. And thes electrons can go here to form the new carbon oxygen double bond. Oops. That was wrong. Okay, carbon oxygen, double bond. The oxygen is gonna have a positive charge. And one lone pair. Uh, and so now all that has to happen is, uh we could say water. Or we could say, Ah, the con ticket base, Um, of that former gas it. So the form a tie on again, um, can come grab this proton use electrons can go like that. Ah, and then that's it. That gets us to our final product here. Okay, s so there. There it is. That's the stepwise mechanism for this reaction. Um, yeah. So it's ah, a pro nation water leaving, uh, the al kind acting as a nuclear fire on adding that carbo cat eye on to form a second ring. Ah, and then, um, water adding to carbon. Ah, that's that's the new location of the car boot cat eye on, uh, that added waters D protein ated. Um, and that's basically the eagle on. Then we just talked to him a rise from the eternal to the key tone. And that's the answer. And that's the answer to Chapter 11. Problem number six.

Here the cushion is draw a stepwise detail mechanism for the following and drum molecular evolution. So first come on this given and inter molecule That means within the same molecules reaction is taking place and by that the authorities front. So here the the action is taking place in presence of the stress of food. So for structure is what is given and in this structure first step is you should have proved on which is given by it's just so it is It s a D oak season and high treason This one get done there Pointing bear is cumin do here and through this hydrogen and this is the road on It is I won't. So here wasn't a charge appears at dis government This is partially car booga Dine disdained immediately just formed rearrangement off this tertiary Carl Hooker time We're making it in such a way so that we can get the product easily. So lead by rearrangement really getting this thirst structure And in the final compound for Mission Roden is lost from the toxic benzene group. And that too from this better position. So you know this hiders and is present here already and it is lost and forming the born between this carbon and this girl. And by that, this carbon carbon bond is formed and hydrogen is lost as photo. So finally, we're getting this final product. Bye, Indra. Monica Alert. Hey!

This is the answer to Chapter 27. Problem number 52 from the Smith Organic Chemistry textbook on this problem is asking us to draw Ah, stepwise mechanism for the transformation that I've drawn at the top of the screen here. Um and so the very first thing that's going to happen is this ether molecule is going thio pick up a proton from the acid. Um, and so it'll have a carbo cat eye on Ah, and a lone pair on this, uh, alcohol, the oxygen. And this alcohol is going to come and attack that carbo cat eye on. And so once that happens, we will get to, uh, this intermediate. Um, sorry s o. We will. Right. So we'll end up with this intermediate here where this oxygen has three bonds, and so it has a positive charge on it. Um, and we can imagine, um, there will be a base of some kind in here or some something that can they can pick up a proton. Um, so we'll just use the generic be it will come and pick that proton up. Those oxygen hydrogen bond electrons will revert to the oxygen to relieve that charge. And so, um, important May. And so Well, then get to, uh, this intermediate. Oops. So Well, then get to this intermediate where the charge on that oxygen has been relieved just like that. And so from there, um, alone pair on the oxygen that started as an either we'll pick up Ah, a proton floating in the solution that's going to get us to this intermediate where this oxygen now has, uh, three bonds and so will have a positive charge on it. Um, and, um, because of that positive charge, because that oxygen has three bonds, it can actually that bond can break are the way that I've drawn it there, and it can end up leaving as ethanol. And so I'm going to continue this on a next page here, OK? And so Mmm. And so, um, we're here like this. Uh, there is a carbo cat eye on here from the oxygen that left, um, and now again will call on our, uh, friend the generic base to come, uh, and pluck that hydrogen. These electrons will revert two there. Um, and so that will relieve that positive charge. So once that happens, we are here. Okay. And so from there, we're actually going Thio be able to undergo a Perry cyclic reaction. Um, Justus, we've been talking about old chapter and so that it's going to look like this. Oops. Drew the arrow to the wrong spot there. So that's going to look like this. And so what we end up with after that parasite Quick reaction. Oops, that's huge is the product of the reaction or desired product there. Go. Our Method group has not changed. Our double bond is situated over there now, and we have our Eldad uh and so that's the product that we were asked to make. That is thestreet wise mechanism for this reaction. And that is the answer to Chapter 27. Problem number 52.

This is the answer to Chapter 27. Problem number 55 from the Smith Organic Chemistry textbook. All right, in this problem, we're giving a reaction and asked to draw a stepwise detailed mechanism for it. Okay. And so what we have here is basically ah, four plus two cycle audition, and then intra molecular Imean formation. Um, and so the first step is gonna be that four plus to Psychlo addition on, so that is gonna look like this. Okay, um, and so that's gonna form our 2nd 6 member dring. Okay, s o, uh, there's the product of the four close to Psychlo Addition. Um, and so the next thing that's gonna happen, as I said, is gonna be an intra molecular Imean formation. And that is going to go like this s of the Knights General actors nuclear file and attack this carbon carbon. Um, the electrons of one of these bonds will go up to the oxygen, and then from from this point, it's pretty much just a just a standard Emmy in formation. So hopefully everybody recalls that, um, from previous chapters. Okay, um and so this nitrogen is gonna have to hydrogen zahn It's still the oxygen is gonna have three lone pairs. So have a natively charged oxygen and a positively charged nitrogen here, Um, and so we can just call the transfer off, um, one of the hydrogen from the nitrogen to the oxygen. We can just say proton transfer, so that will get us to hear. Okay, um and so we are told there is some mild acid, uh, you know, in the reaction conditions for this reaction on dso this oxygen, um, is gonna be pro nated by that mild acid. That's little Grab this proton. Okay, uh, and so now this oxygen's been pro donated, so it's gonna have a positive charge. Uhm. And so the nitrogen, um, the lone pair on the nitrogen can add in here and simultaneously. Uh, this oxygen with its to Hodgins can take off as a water. Um, and rather than try to cram stuff and below this, I'm just gonna put the last, um, couple pictures on a couple couple molecules on the next page s o the water that I was going to take off the night surgeons loan. Paris gonna add in? As I said. Ah. And so that is gonna get us to hear. Okay, Um and so from here, the only other thing that has to happen, um, is gonna be deep pro nation of that nitrogen. So let me move all of this down, okay? It's a deep pro nation of the nitrogen, the mean, um, and that can be accomplished by water. So no surgeon's gonna have positive charge here, since it has four bonds. Um, but there is water floating around in here. Ah, and so the final step is just gonna be this deep protein nation, and that is going to get us to our final product. Okay. Um, so, uh, yeah, Here's the last step again. Here's the rest of the mechanism on the first page. So it's ah, it's a four plus to Psychlo addition, followed by intra molecular Imean formation on. And that is theano, sir, to Chapter 27. Problem number 55


Similar Solved Questions

5 answers
6J5 xvx 1 5 dx0
6 J5 xvx 1 5 dx 0...
5 answers
D.carboxyli€ H,Co04? 4Li 0 SOCI;OH(CH;CH)CuL.i
D. carboxyli€ H,Co04? 4Li 0 SOCI; OH (CH;CH)CuL.i...
5 answers
Problem #7: A sample of tritium-3 decayed to 839 of its original amount after 5 years. How long would it take the sample (in years) to decay to 129 of its original amount?
Problem #7: A sample of tritium-3 decayed to 839 of its original amount after 5 years. How long would it take the sample (in years) to decay to 129 of its original amount?...
5 answers
Question 3Not yet answeredMarked out of 6Flag questionFour charged rings placed as in the figure below. Given that all rings have the same charge 43.8 nC and radius a=0.10 m, find the electric field (in units of kN/C) at point p.Select one:A. 35.74B. 18.22C.26.98D. 62.02E. 48.88
Question 3 Not yet answered Marked out of 6 Flag question Four charged rings placed as in the figure below. Given that all rings have the same charge 43.8 nC and radius a=0.10 m, find the electric field (in units of kN/C) at point p. Select one: A. 35.74 B. 18.22 C.26.98 D. 62.02 E. 48.88...
5 answers
Graph iho dafa l0 produce sbalghi (ina. Be suje i0 include: (3 marks)Labels ior iha % end 3583, Incding conect uniis and IudcUba Gno paah in detennie %e Iocal kengih 6? %ha conter kens (18rs}
Graph iho dafa l0 produce sbalghi (ina. Be suje i0 include: (3 marks) Labels ior iha % end 3583, Incding conect uniis and Iudc Uba Gno paah in detennie %e Iocal kengih 6? %ha conter kens (18rs}...
5 answers
A) Find the center-radius form of the equation of the circle with center (0,0) and radius 14. b) Graph the circle_a) The center-radius form of the equation of the circle is (Type an equation.)
a) Find the center-radius form of the equation of the circle with center (0,0) and radius 14. b) Graph the circle_ a) The center-radius form of the equation of the circle is (Type an equation.)...
5 answers
Based on formal charge considerations, which of the following would likely be the correct arrangement of atoms in sulfur dioxide: OSO or SOO?
Based on formal charge considerations, which of the following would likely be the correct arrangement of atoms in sulfur dioxide: OSO or SOO?...
4 answers
Ahz n boiling-point change for 4 soluuon coatzning 0 625 mol of ninhthakne 0bq-d noliolaulc DCMouLuIn? compcindh) bavrne? (Kt =2 5J9C m btnrnccaSelect one:1oqusruor405 0-1SS1 %63seC
ahz n boiling-point change for 4 soluuon coatzning 0 625 mol of ninhthakne 0bq-d noliolaulc DCMouLuIn? compcindh) bavrne? (Kt =2 5J9C m btnrnc ca Select one: 1oqusruor 405 0- 1SS1 % 63seC...
5 answers
1 73 1 @ J L 1 8 1
1 73 1 @ J L 1 8 1...
5 answers
Express each of the following rates as a ratio with the given units.Gallons/Minute A 225-gallon drum is filled in 3 minutes. What is the rate in gallons per minute?
Express each of the following rates as a ratio with the given units. Gallons/Minute A 225-gallon drum is filled in 3 minutes. What is the rate in gallons per minute?...
5 answers
Point) If f is integrable on [a,b] , thenf(x)dx = lim f(xi)Ax; n-0 i=lb-a and xi = a + iAx.where AxUse this definition of the intergral to evaluate JS x 4x2 dx_ First of all, we haveJ' x _ 4x? dx = lim > m-0 i=1Evaluating the sum givesJ x _ 4x? dx = lim "-0Evaluating the limit givesJ8 x _ 4x? dx
point) If f is integrable on [a,b] , then f(x)dx = lim f(xi)Ax; n-0 i=l b-a and xi = a + iAx. where Ax Use this definition of the intergral to evaluate JS x 4x2 dx_ First of all, we have J' x _ 4x? dx = lim > m-0 i=1 Evaluating the sum gives J x _ 4x? dx = lim "-0 Evaluating the limit g...
5 answers
Find an equation for each graph.IMAGE CANNOT COPY!
Find an equation for each graph. IMAGE CANNOT COPY!...
2 answers
One mole of a diatomic, ideal gas at initial pressureP0 and volume V0expands to 2V0 along the path P=Poexp[(V/Vo)- 1]. Find a) ΔE for the gas, and b) ΔS for theenvironment.
One mole of a diatomic, ideal gas at initial pressure P0 and volume V0 expands to 2V0 along the path P =Poexp[(V/Vo)- 1]. Find a) ΔE for the gas, and b) ΔS for the environment....
5 answers
CH3-CHjCHscIUPAC name isOCHZCH]OCH,CH;[UPAC name is
CH3 -CHj CHs c IUPAC name is OCHZCH] OCH,CH; [UPAC name is...
5 answers
GraphEquationZeros (solutions)FactorsGraphEquationZeros (solutions)X= 0 and X =-6FactorsGraph 6EquationZeros (solutions)Factors(~X - 8)(x + 2)
Graph Equation Zeros (solutions) Factors Graph Equation Zeros (solutions) X= 0 and X =-6 Factors Graph 6 Equation Zeros (solutions) Factors (~X - 8)(x + 2)...
5 answers
JpountSCal ETe 4002 [3799173]Find thc u0ca the rcglon thut boundeothe QIyen curvc #ndcntcined *rtorcos(0) ,8 0 $ 5/6
Jpount SCal ETe 4002 [3799173] Find thc u0ca the rcglon thut boundeo the QIyen curvc #ndc ntcined *rtor cos(0) , 8 0 $ 5/6...

-- 0.021935--