How many four-digit odd numbers less than 6000 can be formed using the digits 2,3,5,6,7, and 8?...

How many four-digit odd numbers less than 6000 can be formed using the digits 2, 4, 6, 7, 8, and 9?

So the first digit can be selected in two ways. Uh, either do what for? So therefore it will have. So it will have to on the the last three digits can be in six. I replied with six deployed with six. So therefore if their total and these are forced in the last. So we have two multiplied with six, then six. So it will have only to repair with six to the power off que which is 400 32.

In this problem, the digits that are given to us are 0, 1, 2, 3, 4, 5 and six. Now we want to make a 4-digit number using digit only once. So we want to make for dessert number for the first position. We have choices from 1-6, we cannot put a zero because then the number will become a three digit number. So we have six choices here. For the second position We have against six choices. Because out of the seven numbers there's only one number which is already occupied for the first space and zero is included in the second space. So again we have six choices here. We have only five choices because two numbers are occupied by the first and the second position. And here we have four choices. So the number of ways to get A four digit number is six into 6 into 5 to 4. This is nothing more 36 into 20 which is 7 20. Let's look at the second part. We want the numbers such that they are odd. We have four positions. No in here in the last position we will one Number like 1, 3 or five. So we have three choices. Well the number two we odd now start filling the spaces from the first position. One of the number is already occupied. So the number of options that we have for the first position is five because zero is not included and one of the numbers has already come at the last positions. We have five choices. Similarly at Inhale we have again, five choices because zero comes into picture. So two numbers are occupied by the first and the last position. So again we have five charges here here for so number of ways to get our number is 5-5 and two four into three which is nothing but 15, 515 and 2004 20. This comes as 300, that's all

Hi. So this is question number 64. And it says that how many four digit odd numbers can be formed using the video? 02356 H. And eight. Video should operate only ones. So. So yeah. First of all the important thing is that how to identify voters in our our number. So and our number ends with an odd number Or did it? Which means that it will end with like digits like 3571 and nine and one more thing that it requires a four year number. And here you can see we have zero in the possible lists updated. So you should be mindful of the fact that your numbers should not start with zero. Mhm. You're gonna want the thing you should be uh careful about. So here this is my four digit number 123 and four. And if I see the possible number of the possibilities for the last digit Is that my last year can have three all 53 and five minutes. My large you can have uh my large it can be can be three or five. Which means that there are two possibilities. And my first aid kit has how many possibilities. It will not have zero. And it can have 26, 8 or N one of them odd numbers. Which means my first aid kit will have four possibilities. And my second digit will also have four communities. Because now I can include zero into my second digit Possibilities. Then three possibilities. So if I do if like if I calculated four and 24 and 23 and 2 to 60 F 16 into 6 17 96 which is option for of the possible answer possible right answers. So I hope this nation was still unclear. Thank you for your time.

The question here basically asked us, um, if we have three digit odd numbers that could be formed using the digits 124 and six It essentially asked us how maney, um, different three digit numbers can be formed using our particular, um, scenario here. So in this particular case, if we have three, um, if we have this, we want to figure out how we can utilize these numbers. So if we just start off with any of these, we have 1 to 4 here. We can have 1 to 6. We can also have 246 here. We can have 146 here, and we can swap some orders around so we can have 416426 and pretty much after that, we can also have six for two here. However, this again cannot be it, as we're gonna have a repetition of digits here. Um, so in this case, we can also have 6 to 4. However, that again cannot be it. So just based on our knowledge of this, any single repetition is not gonna be allowed. So in total, there are going to be six different ways. Um, by which we can answer this particular question