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60Elbow position 0 flexExternal Torque30" flex50 N90 flex...

Question

60Elbow position 0 flexExternal Torque30" flex50 N90 flex

60 Elbow position 0 flex External Torque 30" flex 50 N 90 flex



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Muscle forms of adult human body. (a) $30-40 \%$ (b) $40-50 \%$ (c) $50-60 \%$ (d) $60-70 \%$

Can we have a position and a force, so a position to a particle and then the force acting on the particle. And we want to know what the talk on the particle about the origin in your veteran rotation and the angle between the directions after R. And F. Okay so we can figure out what the torque is. That's just R. Cross F. And so we can go through that. We have I cross eyes so that gives us nothing. And then we have 18. I cross with Jay. Um and then we have -32 J. Crossword I. And then um 24 J. Cross with J. So that's zero. Um Then we can basically J Cross with I. Is minus K. This is K. So we get 50 um Kay newton meters. So 50 newton meters in the Z. Direction is our torp. Now there's obviously lots of ways we could figure out the angle between these two vectors. We could look at the we could look at the well the co sign of the um dot product of their unit vectors. Okay, so that would be co sign data equals R. Um dotted with F. Divided by magnitude of our times the magnitude of F. To use that. But we can go back to our basically our torque formula here. Um I know that the talk is the magnitude of the torque is the magnitude of the position times the magnitude of the force times the sine of the angle between them and so on. This equation we know we can figure out the magnitude of R. And F. And we can get the magnitude of T. Um so that we can get um um sign. And so what we see here is this thing is 50 and this is a 345 triangle. So that means the magnitude of our is five and then this is a 56 10 triangle, so the magnitude of f is 10. So this is also 50 so this is one. And so that means the angle between these two is um is 90 90 degrees. And we can actually see that just by looking at that, that the dot product of these two things is zero. Um And yeah, so that we know that then that the that they must be, yet they must be perpendicular to each other.

Writes. This problem asks us if we have a 100 pound force and its 1000.3 meters from a point of rotation was the torque on that? So would say we have some some rotating object here and we're exerting a force right here on that force is gonna be 100 Newtons. So that's 100 doings. Don't say the point of rotation is right here. That point of rotation, it's gonna rotate around that and then that distance there, um, this 0.3 meters, this problem. So basically, we have the equation. Um, torque is that That's the force times. This is right. So force is the 100 Nunes in the distance from the point of rotation. That's the 0.3 meters. In this case, um, you know, 100 times 1000.3 would be 30. We're gonna be careful of the units. We have a force times the distance, uh, Newton's tens meters, and that's definitively what we call Jules. It's a unit of energy. Won't work

Hello and welcome to this video solution of numerous here we have a particular mass. M is moving in a circular fashion making an angle theta with vertical rate. So you have to tell the angle between the network and the angular momentum of the point. Right, Okay. So first of all let's consider the the direction of the network. Okay, torque tax. How long the direction of velocity that is as shown. Okay. Next we have the angular momentum. Yeah. Is given by mass times our cross v. Right? That means angular velocity momentum is actually acting perpendicular to velocity to velocity. Right. That means angular momentum and torque. Both will be perpendicular to each other. Right? Because one is along the direction of velocity and another is perpendicular to the velocity rate. So we select options. See is the correct one. That is 90°. I hope this is clear to you and have a very good rest of the day. Thank you.

Higher. For this question we have to to force is 18. This is on 100 newtons After the angle of 60° Rita. So we can draw each newton's here, man. 100 newtons, I'll go 10 years 60°. So it's actually assumed that is 100 newtons is at the horizontal. So let's regret. And so this We like this. We have 18 years in jail. 100 attempts. They're busy vertical Y axis next exist And there are 60° so we can resolve The 88 in force. And to its origins are vertical component. So for the horizontal decide would be 80 signed 16. Surely that is the vertical Because it's because 16 vertical Jt So I'm 16. And For the 100 incidents in the horizontal. So this would be 100 militants and this would be zero. So I don't know all of these. Your agent also, it'll be 1 14 years since. And vertical total would be 40 or three newtons. So for the resultant, if isn't the pythagorean theorem square to 1 40 square was 40 route the 20. This is the culture 1 56. I went to Yeah, it sounds. And now for the direction reason data is of course a ton of us of the vertical. Whatever horizontal, which is fortunately what about all function And this is equal to 26 point three decrease. So since we set the 100 incidents as the horizontal exists. This means that our forces is a resultant. This is for a horizontal, it is 156. Continue buttons from at 6.3° from the 100 incidents force. You can also express it as in the direction from the 1884. So just Do 60- This and I'll be from the Internet and forced not for B. The equally brand force is exactly the same magnitude as the result of what the opposite direction. So I didn't want you to to this direction. So this 1 36 to Newton's at when I suppose this would be to 06.3° from Do 100 years on the force.


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