In this question. First of all, be able to fall our differential equation that is one minus x. Y. To the power minus to B X plus Y squared plus access. We're into one minus x Y to the power minus two. The white was 20 That's all week. First of all. And it is also provided when X equals to do what? It was 21 Now this is in the form of I can say that I am of the X plus and of Dy it was +20 Okay. And its solution is given by the formula that is integration of MDX less integration of N D Y. It was two costed while you are integrating them with respect to X. You have to do it here. Why is constant? Okay and in this integration here to take the terms there they are independent or tax. Okay. Now you see that we have to integrate here um that is one of only one minus x. Y. Holy square, Okay. D x And we have to take Y. S constant and the area to integrate the terms often that are independent of X and that is your only Y square. So we are to simply integrate Y squared Ok no we are going to solve this integration in the first integration. Your rotate, why is constant? So its integration should be minus one of 11 minus x Y 10 to minus one upon why plus integration of Y square is like you buy three who was to constant. So finally I can say that I get the value that is, it was too one upon. Why do I do it by one minus X. Y. That's why I Q by three equals to see. Now the condition is given to that is actually close to do and why it was 21 So I have to put it here that is X equals to two and why it goes to one. So if you want this condition here we can that the value of constant. I have to put weight was 21 so one of them one and 21 minus two. Bless one by three. Was to say these changes into seek was 21 by three and one minus four is minus one. So we got here minus one that is minus two by three. Okay, so finally I put this value up, see in this solution? So I got the solution of the question here. Okay, and the solution is one of one went into one minus X way less. Like you by three equals two minus two by three. Okay, this is the solution for the first question here and now you're brussels. The second question. Okay, so this was a solution for the first part and indeed seven part. We have to solve another differential equation and this differential equation I can say that is given to us. That is it was too well dx minus x. Dy it was too wide square the way. Okay, what is all this differential equations? I can say that first of all I am going to right here dividing by D Y. Then we got here. Why D X Y b y minus X. It was two Y squared. Ok, Now I divided by Y. So I get the X Y D y minus X by Y. It was too wide here. Now this is a linear differential equation. And to solve it we have to find first of all the integrating character. So the integrating factories, you do the power integration of the minus one of my own Y. Okay. Because this is in the form of the X. Y, dy less fever. It was two Q here. Okay, sorry the exit was took your so I take the values of P and Q. Here and after that I'm going to find the integrating factor. So integrating factories integration of he told the power to dx and here it is minus one of one Y. And its integration is to devour Eleanor, y minus Ln of Y. Now these changes into minus one of one way. Now I'm going to find the solution for this differential equation. The formula for solution is the solution comes out to be that is exciting here equals to integration. All you are you need explicit see okay, so you're delayed in the sea now I have to put the value of integrating factor that is minus one upon why it was the integration of Q. Q. His wife, so why into minus one upon right here. Okay and let's see now we have to integrate here. You can see that your way and one of one white cancellation and your minus X by Y. It was the integration of minus one with respect to leave. I should be minus wife. Let's see. So I got the solution for the second question. Okay this is a solution of the second question. Now we have to find the solution for the third part and the third question says that it is, it was too X into D Y by dx minus y minus five X to the power. Four minus three. Next cube sorry access square the last two weeks equals to zero. Okay now this can be lieutenant, divide by dx minus y by x equals two pilot skill and blessed three x minus two. Now to solo again we are to find the integrating sector here integrating factory. The integration of it to be about minus one of one years. So it should be into the bar minus one minus at the next hand after the installation of L m v D. You got your minus one of the annex. Okay now we have to find a solution for this differential equation and the formula for solution is why into a integrating sector. It was the integration of Q integrating sector. The explicit, see why do I face minus one of on it? It was too Q. Here is that is five X cubed last three x minus two. And your kiwis sorry I faced minus one of our necks B X. Let's see. Okay now we are solving this so we can say that this changes into minus y by x equals two. We divide all the times by minus X. So we get here minus five access were minus three. Listo by X. Okay, now I integrate all the time so I get minus Y by X. It was true minus five. Next killed by three minus three X. And plus to Elena affects. Let's see. Okay, this is the solution for the good question. Thank you.