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A/ IMN =dd41Boiling water T =373 K1AThe image shovrs Orocess in tne p-V plane indicated by &nartow tnat changes the terperature Iram Tc 970y fixed volume VO15IO...

Question

A/ IMN =dd41Boiling water T =373 K1AThe image shovrs Orocess in tne p-V plane indicated by &nartow tnat changes the terperature Iram Tc 970y fixed volume VO15IO gas submerged into concainer boiling water,Tne rigtit side oftne imageIne inicial state - process consists af piston containing mole of a monatomic Eas atTc 293 K (roamn temperature' and volume Vo m?that is contact with - heat bath bolinz wate Mderatune 373 The final state of process consists ofthe g4s equilibrium Th with the sa

A/ IMN =d d 41 Boiling water T =373 K 1 A The image shovrs Orocess in tne p-V plane indicated by &nartow tnat changes the terperature Iram Tc 970y fixed volume VO15IO gas submerged into concainer boiling water, Tne rigtit side oftne image Ine inicial state - process consists af piston containing mole of a monatomic Eas atTc 293 K (roamn temperature' and volume Vo m?that is contact with - heat bath bolinz wate Mderatune 373 The final state of process consists ofthe g4s equilibrium Th with the saine volume In tne Irlial sale Calculate the work juop sainol tne gas during this process Da notinclude units vour answer



Answers

Figure (26-E11) shows a cylindrical tube of volume $V$ with adiabatic walls containing an ideal gas. The internal energy of this ideal gas is given by $1 \cdot 5 n R T$. The tube is divided into two equal parts by a fixed diathermic wall. Initially, the pressure and the temperature are $p_{1}, T_{1}$ on the left and $p_{2}, T_{2}$ on the right. The system is left for sufficient time so that the temperature becomes equal on the two sides. (a) How much work has been done by the gas on the left part? (b) Find the final pressures on the two sides. (c) Find the final equilibrium temperature. (d) How much heat has flown from the gas on the right to the gas on theleft?

Hello, friends. This is the problem based on Sai Click Process. So in this problem we have to apply the concept off. Sigh, click process. Here it is, given initial temperature. 300 Calvin, do you two is 600 Calvin. The three is 4. 55 Calvin Number of mood is but it is ideal Guests mono atomic So specific heat at constant volume is three way to work on at constant presidents five by two are for monitor make s B one is given but at must be pressure That is 1.13 and tow 10 to the power five Newton per meter square First part We have to calculate the heat in the process One Toto Cuban toe that we have to find So it will be process 1 to 2 is I saw Barrick Process body image constant O N C v Even minus Tito substitute developed number off knowledge one CB is three by two Are change in temperature? A tu minus Stephen, let me correct it. That is 600 minus 300 substituting the value off art 8.31 in 2, 300 on solving it. You will get 37 39 point five Do no for second part changing internal energy Delta in the process. 1 to 2 amount off he transferred in the process went Toto minus Bergen. In the process went Toto. So he transport. It's 37 39.5 minus and I so correct. Process Baghdad zero. So it is Toby 37 39.52 and see purses. The bargain by the guests in the process 1 to 2 is being to Delta V. It is zero because Delta v zero deeper since process toe process tow to three is idiomatic process, so transfer off heat in the process 2 to 30 Yeah, changing internal energy in the process 2 to 3 will be N C v T three minus Kato three way too into our that is 8.31 changing temperature 4. 55 minus 600. So it is to be minus 18 euro 7.4 to 5 to changing internal energy. According toa first love thermodynamics So Bergen we can find this is zero It is minus 1807 0.42 plus zero plus work done so border in 2 to 3 process will be 1807 point. What to do? Yeah. Amount off heat transferred in the process. 321 N C P even minus t three CPS five by two Into our our is 8131 300 minus 4. 55. So it is Toby minus 3220 0.1252 Etch changing internal energy in the process. 321 and TV even minus t three one in 23 y took 8.31 in two. 300. Minus 4. 55. We will get minus one night. 32.752 worked on in the process. 321 by applying the first law of thermodynamics. 32 to 0.125 minus one night. 32 Find 07 fight. So it is Toby minus 1 to 8 point euro five. She transferred in the cyclic process to cycle. You want to 2 to 3, 3 to 1 in process. Want to transfer off? It is 3739.5 in second Adam Addiction. No transport off it in third. It is three toe. Who? 0.125 So it is to be like Okay, so it is to be five and nine 375 Do total work done in the cycle worked on in the process. Went toe to in 2 to 3 and 2321 Jiro +1807 point 4 to 5 minus 1 to 8 point. You know fights. It is Toby. Yeah. 519 point 3752 My by guessing question. Even even it's called toe NRT. Even so, initial volume you will get and are even upon even one in tow. 8.31 in tow. 300 upon born atmosphere. That is one 0.13 10 to the power five. So volume we will get one Jiro 246 m cube, which is also be too because it is iceberg process. Okay, Yeah. No. And since one Toto process body image constant. So even it's called Toby toe 10246 meter. Cue the pressure you will get and our day to upon veto one in tow. 8.31 in to 600 upon 6000.246 So it is to be 20 to 682 point 93 pass kit. Mhm people is called to PC because it is isil Barrick process So one Jiro Bon three Jiro Jiro Paschal. So be three. You will get an r A three upon P three. 8.314 55 upon one D robin 300 So 3000.0 373 m cube P three is called to heaven because pressure is constant. 101300 Paschal that sort. Thanks for watching it.

In this question, we are given a tree step process from states 12 states to the gas under goal and a diabetic expansion from T one goes to 58 years. Calvin to t two equals two. Tree 89 Calvin. They know that, I guess, is one more one more off one of my atomic guess. Okay. And then from states to the states three the gas and they go on that goes isil. Barrick compression from Tito Tea tree and then from state three to state one. It is an isil correct process, And then the gas returns to t one and t one. Okay, so this question there are four parts in part A. We need to plot PV diagram for these processes, but these processes and then probably even need to find tea tree. I see. We need to find, uh, dealt i e internal and w q um, for each process and also for each for the whole cycle in party. Okay, Basil, for part A. You need to plot down TV diagram properly. Um, there are a few things we need to use. Okay, So, um so certainly the equations that we will be using. Ah, so the idea guess equation PV equals two n i t. You can find you one. Okay, so we want equals two and r t one divided by P one p one is one atmospheric pressure. So we have one more. 8.314 times off 5. 88. Okay, if I buy one atmospheric pressure in Paschal 1.1 tree times 10 to the five. You calculate the volume. We one is 0.0 for its three. Cute. Okay. And then, um, during the i a diabetic expansion. Okay, be using, uh, t one me one to the government. This one is equal to he to be to, uh, to the gamma minus one king. Uh huh. Yeah, because we have we have t one we have t to. We also have the one. And using this equation, we can find me to king so we to is equal to he won t to one. Over To the gap to the power one of work on my next one and then times 31 Okay, So government increase to 53 formal atomic guests. Okay, So you have t one is 5 88 in t two is 3 89 and then one over. Come on, minus one. You get, uh, two or two and then we 100 for three completely. If you get 0.897 need a cube? Okay. Then we can find You can also find P two. Okay, So using p one we want to the gamma is equal to P two into the gamma. Yeah, so p two which sp, uh t y we want over. You too. Did the cover. Okay, so who in the numbers got a nice five tree? And then you get 3.61 times 10 to the four mascot. Okay, So, um and also we know that retreat because we want because I sold curry process. So now, yeah. Now we are ready to talk the PV diagram. So you want me to? Okay, so this is 0.43 0.0 897 We also have our p one and p two. Okay, so you look something like this. Okay? And then this is the pressure in Paschal and P one is one atmospheric pressure. So this is Ah, 1.13 times 10 to the five. And M P two is 3.61 Thanks. 10 to the four. Okay. Okay. So with this, uh, this diagram period diagram we can proceed to find Ah, tea tree, part B. Okay. Okay. So, uh, just now we have, uh, t one we want to The gamma minus one is equal to P two p two to the gamma minus one. Right. And we also have anyone close to retreat. Okay, so, um and from from I saw very process. So pressure is constant, so e to over t to go to retreat over t treat t. So that means, um and since the trees we want So if we want or tea tree as well. Okay. So way have, uh, we two over. Okay, so from here we have we want o b two b equal to he treats or t two k. And then we also have, uh, we want will be, too, to the gamma minus. Juan is equal to t to over t one. So this means that tea tree or t two. Did you come on? My next one? Is he going to Tito T one, Okay. And then tea tree. Is he go to you too. T one one over. Mama is one times t two. Hey, you substitute the numbers. T two is 3 80 91 is 5 88 then Gamma is 5/3 and you get three over to over here. And what if I write to 3 89 when you get to 09 cabin? Okay, so this is the answer for tea tree. Okay. Now, in part C, we need to find, uh, the changing internal energy that work done by the guests. And he it added to the guests for each process. Okay, so this question we, uh, using versus law off, the more dynamics he. So you say that internal? It goes to Q minus w Okay. And then we noticed that for it are very process. Q equals to zero. Right? And then for isil correct process. Uh, the beauty goes to zero. Okay, then, for, uh, you know atomic. Guess any data? I e interna. Is he going to 3/2 and are 30? Okay. Hey, So for process 1 to 2. Can you? So this is it a very process. It are very extension. Okay, so we know that cute goes to zero immediately, and then that I e internal is equal to show it to and are Delta T. So this is equal to show to one more. Thanks. It's 0.314 kinds t to mind the sea one. So t two is Archie 89 minus 5. 58. And you calculate these You get negative two for 80 Jews. Okay. And then, uh, first law think that, uh, that I e internal is equal to minus W. So the view is equal to, uh, minus Delta internal. You get to 40 Jews. Yeah. So this is, uh, 1 to 2 when you have q equals zero, and then this is the TaII internal. And then this is w Okay. Okay. Next we have country process to to treat. Okay. You have I saw very compression. What? So this means that oh, you can find out I e internal for us since you have the temperatures. Okay. Okay, Socio. Two times, One times it's 10.314 My time's tea tree minus t to tea tree is 209 92 is 3 89 inculcated. You get negative. 22 for zero Jew? Yeah, and then walk down. My guess is P Delta V. Okay, So P two Peter is 3.61 times 10 to the four. Then Delta V is between minus 32. So you have 0.0 for each three. Minus 0.897 When you complete days, you get negative one for 90 Jews. Okay, so, um, from first law thermodynamics. Okay, so, Q, is he going to uh huh. That i e internal plus a butte. Okay, so you have minus 2 to 40 minus one for 90 and you get Bangladesh 3730 juice. Okay, so he said this is the data panel. This is star, uh, that view I walk down my guests, and then this is the cute. Okay, so one thing to know is that if you are given the initial and final temperatures, you can always calculator. Uh, I e internal. Okay. Okay, then. Lastly, we have process treats. One. Okay, so we have isil Corey process. So in this case, we know that w is equal to zero because there's no change in volume. And, uh, taii interna is equal to Q is also equal to share with two and our identity. He drinks too. Times one times 8.314 The 30 is 5 88 minus 209 You can create you get for 7 to 0 Jews. Okay, Right. So I'm going to summarize them into a table because once we summarized in the table, you can do probably easily eso we have process, uh, anti internal in Jews, Cute Jews. The view in Jews Think so. We have 1 to 2, 23 321 Okay, so, minus two for each zero. Here we have zero. Here we have, uh, 2480 Okay, then to achieve a negative 2 to 40 Ah, negative. 3730 Negative. 1490 Okay. And then for 321 dot ie internal iss. 47 to 0. Curious. 47 to 0. Okay. And then be with zero. Yeah. Okay, then. Hadi. Okay. For the whole cycle, the psycho we just follow through the table. Uh, internal zero Q is 990 Jews W is 990 Jews. Okay, you just some the numbers in the table, and this is what you get. Okay. All right, so that's all for this question.

In this edition we have Johnston told you Border now stage two in the first of a little stage two 40 degrees Celsius and active the Bulls to one and G is a close to 7.384 He looked Gaspar's and Richie is. It goes to 19.5 instead. One we have beachy man, we have B I Is it one stool your fertility I divided by him which is a post with you, dear and advise it'll 0.1. We do 30 meter que burkino ground which is where we have which is greater than BT so edge to ideal guess from 1 to 2 thousands constant t capital be one of the worst of PCI into VJ divided driving one which is opposed to 7.384 multiply with 19.52 divided by throaty logistic was 4.8 kilo Paschal No Premier Li have veto that is MD toe into the pool. So you want one in tow? 19.52 Do the close to one blanche nine by the window and in the process we have to use it was to think an ideal guest gives block from question beer. Don't do too. I want you to the world to interrogation off one toe the D V. Which was to be evenly one natural off you too. Bye, everyone into the world to 4.8 into keep born fetal into natural over 1.92 Derided by me This gives us do Minus explained one night here too. No small feat is real. Part little zero Once it does it'll $8 people born to life I want to play vit 19 point by even nine. Just seven point 9.76 deals. Right. You We re the postal mp three, but you fetal 0.976 meters. Yeah, no, b is. It was trophy, which is the postal beaching. This gives a walked on there. Don't do three. It was to integration from to me. You, Davey, is it was toe pt We re minus rito, which is? It was toe 7.384 And to play a little foreign to 9 36 1.952 They get their due minus 7.21 kiddo to so total dog Don't do three. You the first. They're too. We get you my want. One night my under 7.21 you pick was to minus 13.4.

So here in this problem were given that there is an insulated piston cylinder device on it Contains air off volume. Initial volume were given US 0.4 medic, You on the mosque Off the air is given us This is M 11.3 kg and temperature t when we're given us or 30 degrees Celsius. Now what is happening is that air is now allowed toe Enter the cylinder from a supply in line on its state were given us the state of the air is the pressure p I is given us 500 Killer Paschal and Temperature t I were given us 70 degrees Celsius. Onda, we have to remind four things in the a part. We have to calculate the final temperature that is Tito inside the question is linear device on In the be part we have to calculate the amount off Moss entered That s m I on in the sea part. We have to calculate the work done by the question So work output on in the deep part we have to calculate the and dropping generation on were also given that at the end of the process the volume double the volume increased by 50% age. So we can say that we toe becomes 1.5 times off of even That is 0.6 m cubed. Because we when we have zero point for me the cube so 1.5 times everyone is way too. That is 0.6 m cube. Onda. Uh, now we're going to solve this problem. So for that will be first calculating the initial pressure inside the cylinder. So for that, really using the oil gas situation, that is P vehicles to MRT, So P one will be called toe M r t one divide by. We won. Now we were getting some import data. Is the value off are on the value off CPI and CPI. So are for air. We have 0.287 That is the gas constant killer Jewell over kg Kelvin and the value off CPI. We have ah, 1.5 collegial over cagey Kelvin and the Valley off. See, we we have 0.718 kg jewell over kg, Kelvin, So I'm gonna put the value of r and all the required data toe calculate the value off P one. So and when we're given us 1.3 kg times are we have 0.287 kill a Paschal made a cube over K g. Kelvin. This is all the unit off our times, even we have 30 degrees Celsius. But we have to convert this thing into Kelvin. So we'll get 303 Calvin divided by the volume At ST one, we have a 0.4 So it is 0.40 matter Cube. So after solving this will get the value off P one us to 82.6. Killer Paschal No. Next we can easily calculated the value off a mass at ST to inside the cylinder that is m two. Same. Using the idea situations empty will be p to veto divide by our Tito So we don't have the value off Tito. But all other things we have So p two we have ah, we are taking the pressure to be constant up even And Peter will be same here. So to 82.6 killer paschal times we do We have 0.6 m cubed divide by our we have zero point 287 Kill a Paschal made a cube over kg kelvin times Tito. We don't have the value of Tito that we have to calculate also. So from here we'll get the value off em to ask 5 90 0.8 divide by Tito So this is the value of M two. Now we can do one thing. We can apply the mosque balance situation on our system which is a pistol similar arrangement. So am I over against the mast end minus moss Out Is he calls to change in mouse of the system Soma's and we have am I here and mass out This zero on it will be m two minus m one. So from here and I will be called toe MTV have obtained as 5 90.8 divide by Tito minus this one we have trained. We have given us 1.3 kg. Now next will be calculating though the work output See, see, part will be calibrating first. Then we'll come with a part So work output as equals to pay times v tu minus. We won. So be We have to 82.6 killer Paschal times we do? We have 0.6 m Q minus 0.4 m cubed. So after solving this will get the value as 56.52 Killer Jewell. So the work output we have obtained US 56.5 to kill a jewel. Now, next, this is 15 to kilo jewels. Next will be applying the mosque energy balance situation on our system to calculate the value of Tito. So we have energy in minus energy. Out is equals to change in energy of the system. So energy. And we have ah, am I e j minus energy out we have the work output. So this will be m two you two minus m one. You won because her changing energy system will be called so changing internal energy of the system. So we're going toe expand his expression So this one will become a m i c p times d A minus. This one is the work output we have already calculated on. This will become M two cv de tu minus m one c v T. One. So we will be using this expression. So find the value off Taito. So expression off my we have obtained us 5 90.8 Divide by Tito minus 1.3. See before air we have 1.5 times T I were given us 70 degrees Celsius. But we have to convert this. Taken to Calvin for that, we're toe add to 70 to do it minus the work output We have already calculated Onda. Its value is 56.5 on it will be calls. Tow em too. So empty. We have obtained us 5 90.8 and divide Burti too Times See, we we have Ah 0.718 times to to So this d two and d d will cancel out minus this is M one so And when we have 1.3 see, we We have 0.718 times. Stephen, we have to 20 degrees Celsius. That means 303 Kelvin. So from here we can easily calculate the value off Tito. So Tito here comes out to be s 315 point three Kelvin. So this is the final temperature inside the cylinder. So, Tito, we have obtained us 315 point three Kelvin. Next we can easily calculate the value off. Am I? So, um, I will be am to minus and one. So, um, em too. We have 5 90 divide by 5. 90.8. Divide by It was to do so. Twitter is 315.3 minus. And when we have one 0.3 soft, resolving this will get the value s 0.5742 kg. So this is the value off. Am I? This is 0.57 photo the next D parties left. That is the entropy generation. So for that will be applying there and dropping well inn situation on the system that is and dropping in minus and dropping out. Plus two entropy generation as equals, toe changing entropy of the system. So and drop it. And we have ah, and my essay and and dropping out. It is zero since there is no heat lost. So in dropping generation as equals to change in and dropping of the system, that means am two ways to minus and one s one. So from here and drop a generation can mitt in us am to s to minus and one s one minus m I s I m i s I we know it is m two minus m one times sc So going to rearrange the terms, Onda, we'll get the expression for and dropping generation us M two times is to minus s I minus and one times s one minus essay. So this is the expression for entropic generation. So I'm going to use this expression to calculate the and drop a generation, so it will be called to M two times CP Ah, it is natural lock t to divide by t one minus are natural law be to divide by be a on it is in brackets And do we have taken a common minus m one again? It's common s one minus s I it will be CP Natural log. Do you even divide wet T I minus our natural lock p one divide by P A. So we have all the values. We can plug it in this expression to calculate the and dropping generation. So m two, we have a 1.874 k g c p. We have 1.5 collegial over k g Calvin Times Natural lock Tito, We have 315.3 Kelvin Divide by 3. 43 Kelvin Minus are We have 0.287 Natural lock Petri divide by pi. Even so, p two, we have ah to 82.6. Killer Paschal divide by 500. Killer Paschal minus M once and when we have over 1.3 kg times CPI, we have 1.5 natural log t I. We have Ah, the one we have 303 Kelvin divide ability. I We have 3 43 Kelvin. Minus are We have 0.287 Collegial over K G Calvin Times natural log P I. We have to 82.6. Divide by 500. So we're going to solve this by using our calculator and we'll get the entropy generation as nearly zero point 09714 kill a jewel over Kelvin. So this is the and drop a generation for the given process. So this one part day we have obtained us zero point 0914 Killer Jewell over Kelvin. So I hope you got a problem. Thank you


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