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Run regression analysis on the following data set with Y as the response variable10.4 126.3 51.6 7.1 30.3 101.9 46.2 "1.7 18.3 61.9 43.2 84.3 137.9 19.3 8.5 10...

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Run regression analysis on the following data set with Y as the response variable10.4 126.3 51.6 7.1 30.3 101.9 46.2 "1.7 18.3 61.9 43.2 84.3 137.9 19.3 8.5 104.8 59.2 -18.3What is the predicted value of the response variable when the explanatory variable has value 28.2? 66.3 Round to decimal place_Question Help:VideoSubmit Question

Run regression analysis on the following data set with Y as the response variable 10.4 126.3 51.6 7.1 30.3 101.9 46.2 "1.7 18.3 61.9 43.2 84.3 137.9 19.3 8.5 104.8 59.2 -18.3 What is the predicted value of the response variable when the explanatory variable has value 28.2? 66.3 Round to decimal place_ Question Help: Video Submit Question



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Let the predictor variable $x$ be the first variable given. Use the given data to find the regression equation and the best predicted value of the response variable. Be sure to follow the prediction procedure summarized in Figure $10-5$ on page $493 .$ Use a 0.05 significance level. For 30 recent Academy Award ceremonies, ages of Best Supporting Actors $(x)$ and ages of Best Supporting Actresses $(y)$ are recorded. The 30 paired ages yield $\bar{x}=52.1$ years, $\bar{y}=37.3$ years, $r=0.076, P$ -value $=0.691,$ and $\hat{y}=34.4+0.0547 x .$ Find the best predicted value of $\hat{y}$ (age of Best Supporting Actress) in 1982, when the age of the Best Supporting Actor $(x)$ was 46 years.

So decision or version number 3 27 We have the extra news and my real use. So in our ta ta trickle builder or ever got nominated 20 extra juice and pour a little contaminated booty. My release. My missing Enter. We have the video there. That is 1.82. And the body will be That is now Indu seven point or do you fight? And the correlation coefficient are that is here. Oh, my doubling for now. As you know, the equation off line that is X plus Be now here he's 1.82 weeks less. Be 90 77 point 35. Well, this is a regression of regulation line, and this is our or listen, coefficient are Thank you.

Is there a question about your during December for the given data? You want to find the equation of regression line so far in our T 83 girls? In order for that one call all ready to enter the X Men use and poor I Tokelo, we need you and dirty. Why the news? By pressing enter, we have the radio off A. That is 1.82. The value will be that he's so into selling 0.45 And the correlation coefficient are originally called 0.4. Now it's been a digression off line that is expressed me right here. Value your faith That is 1.82 x in here Bee's 77 point or device, right? This is already questionable Revision length. Thank you.

So this is our question number 237 here with their expertise. And why will use so in t 83 calculator for every one column you need to enter the X values. And for a two column you need to enter the old wiring loose. My resting enter we have is it will do minus. You're a point, man. 01 Next, then be easy. Goto 26 point Therefore now, as you know, the equation of lion is wise equal to express me. Okay, Now put the value and B here. East negative. 0.90 Onyx and hear the east 26 points. 04 So this is your questionable least red line. Okay, Now, in our computer, we got our square is equal to your 0.937 Okay, now taking square root word sites. So here we have our is equal to negative 0.968 It is Our correlation coefficient are okay. Thank you.

For this problem, we want to find a linear regression model. So looking at the data points we have, we get our X column is going to be 0 10 30 40 uh 10 2030 40. And then ry column is going to be 3 50 5 70 9, 29 15, 13 and 24 54. So we want to use regression model and we wanted to determine its gonna be exponential regression model. So when we plot this we'll do inserting of a chart. So with this regression model we wanted to include the points. We end up getting this right here so we can add a trend line um through these points. And when we add the trend line we end up getting that. Its model as an exponential is going to be given to us right here as 3 50 E. To the 0.48 X. We could get different models depending on what we're using. But this would be our regression model and it has a very high r squared value so we know it's accurate


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