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Tina distributon Inu numdul ciholm [ha fardom or the Db LJIE 9 ollpuc2ln Spend dora nen use t7o lble Mrnni C tne #on Mer Ihu pic chart Mecthy Sludy HolahonnSma montkr Eo+ hoDatoFimt conatnud Lha Ircalant HenbbcnCierFrequoncy;UFieeetratertnic maeIc |4no(15 prue" TeotonnnAmel4Jr4 Venpa Dani EeeJE-1020-24Entor vou Insworadicaldean Ihen clcCiujr 4JumainnqReflect In ePortialio

Tina distributon Inu numdul ciholm [ha fardom or the Db LJIE 9 ollpuc2ln Spend dora nen use t7o lble Mrnni C tne #on Mer Ihu pic chart Mecthy Sludy Hola hon nSma montkr Eo+ ho Dato Fimt conatnud Lha Ircalant Henbbcn Cier Frequoncy; UFieeet ratertnic mae Ic |4no(15 prue" Teotonnn Amel4 Jr4 Venpa Dani Eee JE-10 20-24 Entor vou Inswor adicaldean Ihen clc Ciujr 4 Jumainnq Reflect In ePortialio



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A ccrrain pale grocn subsrancc, (A) becomes dark brown on axkting $\mathrm{NaNO}_{2}$ in prcscncc of dil. $11, \mathrm{SO}_{4}$ irs aqucous solurion gives prccipitarcs wirh (1) $\mathrm{BaCl}_{2}$ and (II) $\mathrm{NaO}] 1$ The larrer NaO1 I in scparare resrs. The larter prccipitare (B), gradually changcs colour from grcen ro brown, on cxposure to air. Whar is A? (a) NiSO $_{1}$ (b) $\mathrm{FeSO}_{+}$ (c) CuSO $_{4}$ (d) $\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$

Tina is three years old and knows her account explained how you would show Tina that three plus two is five. So if Tina is three years old right now, that means that next year Tina will be four years old and in two years Tina will be five years old. Thus, we have added two years to Tina's current age of three. The three plus two is equal to five.

Okay. Multiple choice Question that two people build in the area for their dogs. It's nice of them. Original person has an area of 60 feet, and then it says their second person, they have a bigger pen, and each side is 1.5 times longer. Then queues, he said. Okay, so what is Tina's area? So since bold sides got multiplied by 1.5 and we remember from this whole chapter that if a the scale factor is 1.5, then the area is gonna change. A rate of 1.5 square area always changes a scale factor square. So a 7.5 a squared is 1.52 which is 2.25 And then if we want to find the new area, we would just take the original area and then multiply it by that factor. 7/3 in a calculator here. I wasn't feeling too confident. My mental math skills we get 60 times 2.25 is 135 square feats. So that is answer C 135 square and there you go

This is the answer to chapter 20 to problem number 47 fromthe Smith Organic chemistry textbook. Ah, this problem asks us to draw the product formed when fennel acetic acid is treated with the tree agent. And we're told that with summary agents, no reaction occurs. Ah, and there are 12 of these. So I'm just gonna go ahead and get started because this is gonna take a little bit of time. Okay. S o for a Ah, we have sodium bicarbonate. Uh, that's gonna act as base. Um, and we have a car back so weak acid that we're starting with. Oh, and I drew fennel acetic acid at the top of the screen here. Rather than redraw the aromatic ring 12 times, I'm just gonna use a pH to abbreviate it. Since the ring itself is not participating in any of these reactions. Okay, s O sodium bicarb here is gonna act as a base. And so we're gonna get an asset base reaction and will de protein, eight hour carb oxalic acid. Ah, and we'll get the sodium ion as the counter I on here. Okay, s so that's a for be, um, again be Is a base. Ah, and so the exact same thing is gonna happen as in a we will de protein eight. Ah, and we'll have the sodium ion as our counter ion. Okay. Ah, see, we're using signing chloride. Remember, signing chloride, um, takes a carb oxalic acid to the acid chlorides, and so we'll have an acid chloride for a product there. And C D is just salt table salt. There's gonna be no reaction here. Okay, s so then e um and actually, let me move these up a little bit. Okay? So in e our using one equivalent of ammonia. Ah, and so that is going to just act as a base. And so again, we're gonna get D prone nation. Ah, and no further reaction. So Deep Throat Nation, and then we'll have the ammonia my eye on as the counter ion. Okay. Ah, for F. We're using ammonia, followed by heat. Um, and so that is actually going to drive this reaction. And so, rather than just a pro nation here, we're actually going to make the A mite. Okay, so there we go. There's f moving on to the next page here. Fergie were using methanol and then sulfuric acid. Um, and so we're going to get the Esther product here on DSO Since we're using methanol will get the methyl ester for H. We're gonna try to do the same thing, but instead of using acid, we're gonna use base. Um, and so that's not going to work. Ah, and so we will end up just deep resonating. Okay. For I AA were using sodium hydroxide, um, followed by on acid chloride. And so, uh, this is going to create the mixed and hydride. So we d pro Nate. Ah, and then our deep throat nated oxygen is able to act as nuclear file Ah, and kick out the chlorine. Um, in the acid chloride that were using is the second re agent in this sequence. And so we end up making the next anhydride. So then, for j r. Using Mesilla mean ah, in D c c. And remember D c. C. Is gonna act as a dehydrating agent here, and so that is going to allow us to form the A mine. Instance for using meth will mean our product is going to be metal. A my okay for kay, we're gonna use. Sign your chloride. Um, and then we're gonna use problem meid. Um and so the final chloride is gonna make the acid chloride. Um, And then, uh, the pro chloride is going to, um, add to that. And so we end up with the A mine. So 123 Okay. Ah, and s o l is going to be similar. Um, but we're not using a mean, so we're not gonna get in a mine. Ah, we're using an alcohol. And so we'll get an Esther. So the Esther will be the Pro Bowl. Esther. Okay, so there we go. Um, yeah. So that's all of the products to these reactions. Ah, and that's the answer to chapter 20 to problem number 47.

In this question we've been given some shorthand notations and we've been asked to determine the full nuclear reactions. So say we've got shorthand in the form A. B. C. D. And why what this is telling us is we've got a parent nuclear it that is being converted. Good combat mint practical. And we've got emitted particle and we've got the daughter the daughter nuclear. So what this is telling us is we've got a parent nuclear X. That is being bombarded by particle C. To emit particles D. Forming a daughter nucleus of of. Why? So this is what we have. We have been given the short information and we've been asked to determine the full reaction. So the reaction in this form will be X. A. B. Plus C. To emit D. Plus why why could be in the form of E. F. Okay so okay looking at this, let's try it. A more generalized form where we've got a B. X. Class Y. C. D. To form Z. E. F. So what we have here we've got X. That is being bombarded by why? To form that? So for this reaction to be called a balanced and a proper nuclear reaction, the atomic atomic and mass numbers should balance what we mean by balance. We're saying the mass and the atomic numbers of the reactions should be equal to those of the products. What women were saying. He should be equal to a plus C. And F. Should be equal to B plus D. This is a balanced nuclear reaction. Now, going back to what we've been given for the first part we've been given if N. A. That is being provided by an alpha particle emitting gamma particle. And we've been asked to determine the daughter of. So if we are to write this with 20 n.e. 10 plus an alpha particle after particle is helium to form a gamma particle comma. That has no charge, no atomic. This is more of energy or array. So remember we said the atomic and the mass numbers should be the same. Mhm. Yeah. So if we are to look at this for the ratings, we've got 10-plus two to make 12. This side we've got zero. So this should be 12. Then at the top you've got two plus four to make 24. This should be 24. And if we are to look from the periodic table, an element that has these properties, they should be MGm. So moving on mm we've been given 15 and serving that is being bombarded by approach on to emit an alpha particle. So applying the same principle, we've got seven plus one to make eight, decide we've got to. So we are short of eight minus two which is six. Looking here, we've got 15 plus One, which is 16 here, we've already four. So we are short of 16 -4. This is to make 12. And if we look from the periodic table element that has these properties, the mass and the atomic numbers of 12 and six is carbon. So moving on to the final hour. Yeah. And this one has been given B 10 7 mm hmm. That is being bombarded by in neutral to form an alpha particle HE 4. 2 are playing the same principle. You've got seven. You've got to. So we are now shut off. Fine. Then here we've got 11. This is 11. You already have four. So we are not short of 11 miners. Sure this is seven and this is A. L. I. Yeah.


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