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Apnltonnol daucer Maparan' arn dotnn tt tnien ATFLLAz = Qicef Ocra 0f Ine Oorl Inua Iona 6 #ard 4 tndrd duybn 0/ seico MCorA 4 Troun447ie d IJ foets lualho l...

Question

Apnltonnol daucer Maparan' arn dotnn tt tnien ATFLLAz = Qicef Ocra 0f Ine Oorl Inua Iona 6 #ard 4 tndrd duybn 0/ seico MCorA 4 Troun447ie d IJ foets lualho ln lul Iltmeanl lnu lurtruonHH

Apnltonnol daucer Maparan' arn dotnn tt tnien ATFLLAz = Qicef Ocra 0f Ine Oorl Inua Iona 6 #ard 4 tndrd duybn 0/ seico MCorA 4 Troun447ie d IJ foets lualho ln lul Iltmeanl lnu lurtruon HH



Answers

From the fungal cross arg- $6 \cdot a l-2 \times$ arg$-6^{+} \cdot$ al- $2^{+},$ what will the spore genotypes be in unordered tetrads that are (a) parental ditypes? (b) tetratypes? (c) nonparental ditypes?

Question is the option yet Seattle plus See S. Res one. They this is not a lot of condensation so we can get here to see it. Woods. CST Hard guys. Right. So every chance to as second is cycle depending on and S Seattle for beaver tends to psychlo pending on have this company because the actual attack on that carbon and carbon and that's the molecule to molecule of S. C. H. Plus at Seattle. So we will get cycle a pendant by all mm. And they tend to bristol. We will get okay.

In this problem, I can write the reaction edge. Just look at it carefully, see http CH two C o NH two. It is in pageants of X. X is equal to and I in at food. This is X. It is in pageants of this will give the product ID see http CH two CH two manage to. Therefore, according to the given option, option B eight, option B e. D, correct and said for this problem, Option B is correct. Answer for this problem. I hope you understand the solution of this problem.

They were given some venoms ends. We have to catch Grissom. So have table one in the textbook shows us various openly. These fans on their way could use first work out what we have here. So the 1st 1 we have two copies of each. Except we're missing one. Call your game. So this is for two in minus one model something the second. We have two copies of each except que When we had three. That's price stomach I finally lost. When we have four caucus speech, it's a test for toys.

All right, So we're gonna pick up from the last question and look at that last combination of genes the tall gene or the height gene with the nose gene. So if you remember from the last question at the very end, we came up with the recombination frequencies and then theological differences for those. So for our height and antenna jeans, we determined that those were 12 math units of heart, the antenna and knows jeans who determined or five units apart. So we're gonna basically do the same thing that we did in the last question determining the l e lik or the recombination frequency and using that to get Delia like distance. And then we're also going to try to map these genes in order based on those a little distances that we get for all of them. So for this one, we're looking at a test cross with a hetero zegas email or height and nose. So being a tall female with an upturned snout crossed with the male, which has the dwarfism and a downturn snout, and these are the offspring that we get so again we see majorities on the parent types and then the re competence have much less. So let's first calculate the recombination frequency. And so you're gonna add up eight plus eight. For those were competence, get 16, and then this again totals out to 100. So 16 divided by 100 secret, 0.16 or 16%. And again, this we just turn it into whole number, corresponds to the map You. So now we know that the height and knows jeans are 16 math units apart, right? So with that, we can see that these two genes heightened knows are the furthest apart with heightened antenna coming second, an antenna and nose coming as being the closest together. So on my little line here, we're just gonna put in. We'll say So what? These being the farthest apart, we know that there we're gonna have to drop right from the farthest apart and then we know Antenna is going to be in the middle. We're gonna put hype over here on to this one mount over 16. 123 nos. And then I'm gonna choose Use a smaller one to make it a little bit easier. Meant five units from the nose and 12 from the heights. That should be good antenna, right? And you can see how they don't add together perfectly. So you'd expect that the five map units and 12 map units that these two would add Thio being exactly the distance here. But because we are working with a living system like maybe a fictional system but a living system, sometimes you don't get exact numbers that you need to make these exact Plus 100 offspring really is a small number. So being on Lee off one map unit from the totals of these all told of these two to this one is pretty good overall.


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