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Question 9 (1 point) How many electrons are needed(+) or released (-) to convert Sulfate to Sullfite?01) +202 -403) +104+40s) +2...

Question

Question 9 (1 point) How many electrons are needed(+) or released (-) to convert Sulfate to Sullfite?01) +202 -403) +104+40s) +2

Question 9 (1 point) How many electrons are needed(+) or released (-) to convert Sulfate to Sullfite? 01) +2 02 -4 03) +1 04+4 0s) +2



Answers

How many moles of electrons are required to (a) reduce $0.20 \mathrm{~mol} \mathrm{Fe}^{2+}$ to Fe? (b) Oxidize $0.70 \mathrm{~mol} \mathrm{Cl}$ to $\mathrm{Cl}_{2} ?$ (c) Reduce $1.50 \mathrm{~mol} \mathrm{Cr}^{3+}$ to $\mathrm{Cr}$ ? (d) Oxidize $1.0 \times 10^{-2}$ $\mathrm{mol} \mathrm{Mn}^{2+}$ to $\mathrm{MnO}_{4} ?$

Hi everyone. So in this question, we're asking an item, a very um, how many electrons style A. L is equal to zero. B M. L. equal to one. So in very America in very um, Magda eighth to an electron's hell, 12 electrons. How how Yell is equal to zero that be where electrons have to an electron's hell M L is equal to What? Thanks?

Question is FEH two whole 5 as far as paramedics. So a three x 2 on five then as for four. Right? So in this molecule, island is present in the that's what is stupid an A plus one has so far managed to. Right. So it will be three D 6 Forest one. So could have an electron. There are multiple americans. The FBI has 300 electron. Yes, correct. Of some people it.

When solving for the oxidation state of the oxidation number on sulfur in tetra cyanide, Wait, S. Four oh six to minus, you'll find that it is a peculiar oxidation number or oxidation stage. Let me show you. So, as you recall, the oxidation numbers need to sum up to the charge. So the total oxidation number for all four suffers plus all six oxygen's need to equal minus two, oxygen is going to be minus two. So, for we don't know there are four of them. We'll add that to negative two times the six that are provided for oxygen, and that should equal negative too. So algebraic lee, when we solve for X will get four, x equals 10. Got ar minus two. Here, we've got ar minus 12. We bring that over as positive 12. So we get positive 10, Then X is going to be equal to 2, 5. So, we end up with this fractional oxidation number, I really can't have fractional oxidation numbers. So it's likely that half of the Sulfur Czar, three And half of the Sulfur Czar, to giving us an average of 2.5

So here's the electron configuration of uh copper, abbreviated in terms of the previous noble guests. And if we make copper plus, the electron configuration is going to have lost one electron. The electron that it loses is in its valence shell, so the outermost energy level, which in this case is the four S. So we just have the same exact configuration except for this. So this electron is lost in the four S. Level. We want the quantum numbers of that. Um That means end is going to be equal to for angular momentum. Quantum number for an S. Um sub shell is zero and then the only possible sfl value associated with equal zero is also zero. And then M sub S. Could be positive one half or negative one half for this given electric.


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