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Draw the transitive closure of this relation. (Omit the reflexive and symmetric closures:)On the right, above, compute the inverse of 9 (mod 11). Show your work!...

Question

Draw the transitive closure of this relation. (Omit the reflexive and symmetric closures:)On the right, above, compute the inverse of 9 (mod 11). Show your work!

Draw the transitive closure of this relation. (Omit the reflexive and symmetric closures:) On the right, above, compute the inverse of 9 (mod 11). Show your work!



Answers

Use the given property to complete the statement.
Reflexive Property of Congruence (Theorem 2.1) ________ $\cong \overline{\mathrm{SE}}$

In this problem of religion infants. And we have to show that the religion are in the set set is which has the elements 1, 2 and three. So and the relation is given us given by relation is given by this is only two other pair, one and two, and the second one is two and one. So this is the Under repair which have only two pairs that it went 1-1. And we have to show that this relation is symmetric but neither reflexive nor transitive. So first we would So for reflective. So relation is said to be reflexive if ordered pair A and a part of our so ordered pair. Eh and S say when we are putting one, So this should be 11 When we are putting too. They should be too. And when we are putting three, the should be 33 And this will be true for every values of A. Which belongs to the given set A. So here we have three elements 123 but there is no such pair. So we can say our is not reflexive. And now we have to check for here symmetric relation. A relation is said to be symmetric if ordered pair even and a two which is already in relation are which implies that 8 to even should be prison there for every values of even and 82 which belongs to the given, said A. So here we have the give and take 812 and this is a pair. 12 so 12 is in relational. This implies that to anyone should also be present there and this is also present there. So we can see that this relation is a symmetric relation. So R. S symmetric relation are asymmetric. And now we have to check for transitive. So again, if ordered pair X. Y. Which belongs from are they want to? And another order pair. Why end Said which belongs to here. I say this is two and 1. This implies that the ordered pair X. NZ should be also presented there. So that means there should be one and one pair, since this is not present there. So we can say that our is not transitive, so are is not transitive. So hence we can say that we have proved that R. L symmetric, but neither reflexive, not transitive. Hence odd is symmetric, but neither reflexive. Yes, neither reflexive, not the north transitive. So this is the proof.

In this problem refunding the list closure under the measure, closure over the relation arm with the given set continued given point. No, first recall that a reflective ah relations will have the point. A full all aid and our set. So based on what we're given, then we should see the 0.0 one There 11 give me to to on 33 in our set. Okay? No, we have we have these two in the middle, so basically, we're adding this. That points to our set given set. So final answer would look like this. And wine one. Me too. Pharaoh to bring zero When we finally 33 symmetric closure. Recall the definition right here for each point. Maybe we should have the curse pondering point B A. So based on or given points, they're symmetric closure. Well, look, someone like me 01 because I have 20 and 30 I all including the ads. They were to hang 03 because I have 2.1 and was also asked 10 one warn 12 because we have the 0.12 We also need to have the point 21 Yeah, To to my morning, honey Nero. I also forgot to put in my 0.20 No, 0.2 there should have been here.

The transitive property of segment. Congrats states that if e f core leads to P Q and P. Q correlates to u V then we know that e f correlates to u V.

You're being asked, protested Metric property of congruence. So you conserve with I couldn't give in. So if you know Edmund A B is congressional segment C. D. Because it's given to you, your job is to prove that the back that CD is also congruent to B to a B, and this looks something like It is obvious when you still need to prove it. So if you know that that is given, you know that aid be. This equals just CD. And that's because that's what Grant meets. So its definition definition of concord in segments again, If you know that they are granted, then they must be equal the first step three. You're just proving that C. D. Is equal a B, and that's because of the symmetric property of equality. And then, for your final step, you organ tohave CD segments et It's Congressional Segment A B, which is what you were trying to pearl. And again you're gonna use to see us Step number two. That's what congrats These grant means


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