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Evaluate f (x + 2) (Vz + 6r)dr (B) Find d"y-e+-4' when I = 1...

Question

Evaluate f (x + 2) (Vz + 6r)dr (B) Find d"y-e+-4' when I = 1

Evaluate f (x + 2) (Vz + 6r)dr (B) Find d"y-e+-4' when I = 1



Answers

Evaluate $f(a), f(a+1),$ and $f\left(\frac{1}{2}\right)$. $$f(x)=-2 x^{2}+1$$

Gives us EPA backs equals negative X square post for and it wants us to evaluate for win access equal to a He wants us to evaluate when X is equal to a plus one. And it wants us to evaluate for when X is equal to 1/2. Good. So in order to do that for the 1st 1 we displayed in A for acts, which just means we're just having a variable change. No, nothing real. The simple fire to change about the problem. For the 2nd 1 we have negative a plus one square replacing the extra, the parentheses this time. Okay, so a plus one squared. We're gonna have negative a squared plus two a plus one. Just doing a binomial expansion. And then post or I was simplifies to Negative Ace where minus two A plus three. Okay. And then plugging in 1/2 we're just gonna have negative and then 1/2 squared. That's store I won't have squared is 1/4 so negative 1/4. And then we can change that to 16 to 16/4, which would become 15/4. Just 16/4, minus the one for Okay, thank you very much.

Is this problem we have F of X is equal to negative two X minus one on the problem once is toe evaluate for when x is equal to A when the X is equal to a plus one and when x is equal to 1/2 case. In order to do that, we're just gonna plug those values in front and put breath of a We just replaced all over access with days. That's all you really have to dio just changing the variable for the 2nd 1 we're going to plug in a plus one for X. So replace X with the parentheses and put a plus one. They were just gonna distribute and combine like terms. So we're gonna have negative to a and then we have negative two minus one, which is negative. Three for minus three. And for the last one playing in 1/2 we have negative two times one count a minus one made 1/2 of negative is negative. One negative. One minus one is negative. Two. Thank you very much.

So here we are given a function, F F x is equal to two X squared plus one. So we need to find out what is F of X plus two minus? Yeah, for effects plus. Okay, so first we need to find out what is F F X plus two. So if F x plus two is equal two into X plus two, the whole square plus one, that is to window X squared plus for X plus four plus one. So it is equal to two x squared plus eight X plus eight plus one, that is nine. So now F of x plus two minus. Therefore fix Plus two is equal to two weeks square plus eight x plus 9 -9 two, x squared plus one plus two. That is two x squared plus a tax plus nine minus two weeks square minus three, which is equal to eight X -6.

Quit the function effort backs equals X squared plus two. And it wants us to find f of three. It wants us to find 1/2 of negative one, and it wants us to find efforts. Hero. So the plug in three was going to three squared. Plus two, just just 11. Next value, Any negative one squared close to negative. One squared is one plus two is three. And then zero. We're gonna have zero squared, which is zero us to which is just equal to two. Well, I went to fix them and mess it up. It's gonna be a 11 on the 1st 1 Okay. Thank you, Very


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