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The meter is defined as the length of the path light travels in a vacuum during the time interval of $1 / 299,792,458$ of a second. It is recommended that a helium-neon laser is used for defining the meter. The light from the laser has a wavelength of $632.99139822 \mathrm{nm}$. What is the frequency of this light, in hertz?

Okay, so we have the laser light has a wavelength Lambda off 1000 and 62 nanometers. Okay. And the post last for 10 t. Easy. Going to 30. It go seconds. He s Yeah. And you know that nanometers means gender. The bar minus trill meters on Dhe started minus nine meters. I was thinking about people when I wrote this minus nine meters on decoys 38 into 10 to the power minus throughout seconds. So the question is asking how many weapons are found within the leave your pulse. So you know the what is the frequency frequency that is according to see by Lambda Dismissed the frequencies that are in one second to see by Lambda. The frequency means that see by lander wave Linds in one second. Like so, what we need is the number of weapons interviewed people seconds. So in 38 because seconds the number off weapons will be seen by Lambda into into 10 to the power by Mr Just. It is a matter off the unitary metal. Right? So this is a call to see Is three entered into the power eight Landa is given. That is 1062 into 10 to the power minus nine into 38. Inter 10 to the power minus two in weapons in party ate pekoe seconds. So this is our answer is well, one Gerald 73 full point 46 Weapons on here in be eight equal seconds. Right. Okay, Now the second question is asking how brief with the boss needs to be to fit only one weather. So again, just begin from here. So for 1 11 for one lived in take land off a CV lander to the other way off their side in 1,000,000,000 becomes lambda by sea seconds. Simple, right? Just limited unique letter. So there is a call to So now Landa is one general 62 Inter 10 to the power minus nine upon no, C is three into 10 to the power a seconds. So this is a call to 3.54 into 10 to the power minus 15 seconds. All right, so we are done with the solution to this problem

This problem covers the concept of uh the interference of faith and for maximum the part difference. The hell must be Cuban into the integral multiple of the wavelength center. Or we can say the apartment must be equivalent to the integral multiple M times survey violent. That is one m or the parts and must be equivalent to them. That said this is the question. Now take a point be on the X axis. Okay let's say this is the point P which is at a distance X from S from. Okay. Yeah. So the apartment from S 22 P is given by square. Odo foursquare plus X square Or the partisans to hell is a Cuban. two square it off 16 plus x minus X. 16 plus X squared. And that's where Okay now this part defense is the cuba into em. Okay or we can create squared off 16 plus X squared equals M plus X. Listen to the question. Okay now for m equals zero. So for um equals uh one we can buy it 16 plus x squared under squirrel Is equivalent to one plus x. Now take spire on the both sides. So the situation becomes 16 plus X squared equals one plus X squared plus two. X. Are the position corresponding to the maximum for M equals one is 7.5 m. Now if we take em equals two then our equation becomes 16 plus X squared Under square. Oh equals to plastics. Now take square on the both sides. We get 16 plus X squared equals four plus X squared plus four X. Or from this we get the position X for m equals two is three m. Now, if you take em equals three then we get squared off 16 plus x squared equals three plus six. Take square on the both sides. So they get 16 plus X. Where equals mindless X squared plus six X. And the position X corresponding to the maximum for m equals threes 1.17 m. Okay, so for the solution of the party, the maximum goes at x equals 1.17 m three m and 7.5 m from the source as well. Okay, no party since the intensity um is inverse invested proportional to the square of the distance from the source and the intensity Uh the way from S one and S two are not equal. So at the minimum uh the net intensity will not be because to see, so we can say the intensity i is inversely proportional to the square of the distance and from From the source as one and as to the distance are not the same From S one and S two. The distance uh is the sense of the minima is not the same. So the answer for this part at minima, the The intensity of the minimum will not be equal to zero

Hello. I'm going to be doing problem 19 from chapter 22 Section three. In the book Physics Principles with applications, he goes as follows. Pulse lasers used for science and medicine produced very brief bursts of electromagnetic energy. If the laser light wavelength is 1062 nanometers and the polls last for 34 PICO seconds, How many wavelengths air found within the laser pulse? How brief with the post need to be to fate. Only one wavelength. So the first thing I like to do is figure out what I have. I have the wavelength, which is 1000 62 nanometers, and I have the length of time of the pulse, which is 34 PICO seconds. Okay, so, by the way, nano meters would be 1062 times 10 to the negative nine meters and then PICO seconds would be 34 times 10 to the negative. 12 seconds. Okay, Then I would draw picture to help me visualize. So we have a length of time, which is 34 PICO seconds, and then we need to figure out how many waves, which is 1062 Nana meters feet. There Okay, So the equation we're gonna use is the wave speed equation, which is speed is wavelength times frequency. Since this is this is an electromagnetic wave, we're going to be using the speed of light. And since we do not know the frequency we're gonna rearrange it to be to solve for the frequency, I'm going to erase my little picture room. Then we can proceed. So now I'm going to use my speed equation and the numbers I have. So our speed of light is three times 10 to the eighth, divided by our wavelength, which is one of six to times 10 to the negative, not nine. When I divide that I get the frequency equals 2.8 times 10 to 14 hurts. If you remember, hurts is the same as one over seconds. But I mean, if we get the reciprocal that we will have the time. So the time would be three point five times 10 with negative 15. So this is going to be our second answer. So how brief with pools need to be fit? Only one wave. That would be the time. Okay, so now we will go back. Keep that here. That's our second answer. We will go back and make a ratio of that with our original time that they gave us to figure out how many wavelengths fit. So we will do the original Number three 34 Sorry times. 10 to the negative 12. It's divided by three point tie times 10 negative 15 and the number of weight links equals 9.7 times 10 to third or, UH, 9700 kilometers.

For in good and waves. That daughter in density becomes the some off that too intense it is. I want and I do. In this particular case, they're asking that intensity of the first wave is nine. I not and the 2nd 1 is 16 I not. Which means that the auto industry will become $16. 90 quest 25 I not because the