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(1 point) Consider the function f(z) absolute minimum value equal to32.2 + 7,3 < € < 9 This function has anand an absolute maximum value equal /...

Question

(1 point) Consider the function f(z) absolute minimum value equal to32.2 + 7,3 < € < 9 This function has anand an absolute maximum value equal /

(1 point) Consider the function f(z) absolute minimum value equal to 32.2 + 7, 3 < € < 9 This function has an and an absolute maximum value equal /



Answers

Find the absolute maximum value and the absolute minimum value, if any, of each function. $$f(x)=9 x-\frac{1}{x} \text { on }[1,3]$$

The function affects it is given that minus of X squared minus 66 past nine. So if that's acceptable because to minus of two x minus up six, that is the cost of zero. So it will be minus three. This is the critical number, and double six will be minus to their this negative. So that means function has maxing at point minus three. So we will put that is the question nine minus six into monastery plus nine. So it will be minus nine plus 18 plus nine. So maximum a former monastery that is equal to 18. And it has no minima, no minimum. Okay, this is dance and I hope you on a short thank you.

Yeah. For the following problem, we want to provide a graph of a continuous function with the given properties. That's going to be a domain from 0-8. An absolute maximum and zero an absolute minimum at three And a local minimum at seven. So what this is going to look like is if we want the absolute minimum to be at three, but that tells us is um since we have a local minimum and an absolute minimum at three and seven, we know that when we take the derivatives, The zero and 3 or seven and 3 mm uh next my next seven these are both going to be um points in our function that we have. As for the derivative graph, we're going to have this. Then we also know that there's an absolute maximum in zero. So we could have something like this perhaps where this is the derivative though. So we have to keep that in mind. Um so in terms of the actual function itself, we wanted to have an absolute maximum. We wanted to come down, reach an absolute minimum. Which could also be a local minimum at three. We wanted to come up and then reach a local minimum at seven And then come up to eight. And that will be the final answer

Hello. The function affects has given Xs Carmona six X plus seven. Okay, so now and interval is given your routine. So now we will do NSX. So it is two X minus six. That is the question. Seriously cost 23 This is a critical number. Now we will evaluate the function at the critical point and the end point. So I have zero there. Did you close to seven Have have three directly questioned. Nine months. Six into three plus seven The education nine minutes 18 plus seven minus nine plus seven. There is a custom minus two half of 10. This will be cause to 160 plus seven. That is 47. So right maximum at have at extra cost of 10. That is up 10. That is close to 47 and minimum value will be a pack of three. That is because to manage to this is the answer. I hope you understood. Thank you

For the given problem, we see that um The graph, we're just specifically looking on the interval from 0-9, we want to find the absolute minimum in the absolute maximum is the absolute minimum is going to be obviously zero. And that's because that's the lowest point on the entire graph and it's included in this interval that we're looking at and then the absolute maximum, mhm absolute maximum when we're looking at it. Um this absolute maximum, we want to look more specifically at where it goes up to nine. We see that it's at nine, it's the highest that it will be on the graph. It's also the same as when X equals three. So at that point we see that the value of the function is nine, so that's our final answer.


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