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UnansweredAccuracy of Measurement Pre-Lab Question 2 Homework UnansweredHow many significant figures in the following numbers? a.1030.0 b. 02.6 c. 0.0 so0oooa.5b...

Question

UnansweredAccuracy of Measurement Pre-Lab Question 2 Homework UnansweredHow many significant figures in the following numbers? a.1030.0 b. 02.6 c. 0.0 so0oooa.5b

Unanswered Accuracy of Measurement Pre-Lab Question 2 Homework Unanswered How many significant figures in the following numbers? a.1030.0 b. 02.6 c. 0.0 so0ooo a.5 b



Answers

Express your answers to problems in this section to the correct number of significant figures and proper units. State how many significant figures are proper in the results of the following calculations: (a) $(106.7)(98.2) /(46.210)(1.01)$ (b) $(18.7)^{2}(\mathrm{c})$ $\left(1.60 \times 10^{-19}\right)(3712)$

In this problem of scientific measurement we have to perform the following arithmetic and we have to round off the answer to the correct number of significant figure and also we have to include the correct unit for the answer. So first we have given 3.58, this is 3.58g, Divided with one 739 millimeter. Then we have given 4.02 mm. This is 4.02 mm Plus 0.001 mm. And then we have given 22.4. This is 22.4 g -8.3 g. And this is divided with Here 1.142 millilitres 0 to 0.002 ml. And then we have party that is 1.345. This is 1.345 grams. Bless 0.022 22 g. And this is divided with 13 point 36 millimeter minus Miller, later -8.4155. This is 8.4115 and this is milliliters. And now we have another one that age 74.335. This is 74.335. This is meter minus 74.332 With 74 points 332 meter And this is divided with 4.75 seconds. This is 4.75 seconds -1.114. This is 1.114, this is second. And now we have to solve it. So in the nominator we have two significant three significant figures and in the denominator we have three significant figures. So We have to keep only the minimum minimum one. That is three significant figure in the answer. And now we have to do the solution that is 3.58 Is divided with 1.7 39 So when we solve it, we get to point this is 2.5 86 86 And this is gram per milliliters. So this gram per milliliter. And now we have to keep only three significant figures. So for this, here we have after 5123, we have eight. So that means we have to increase by one. So for this This will be the right answer, that there's 2.06 graham per millimeter. And now here we have given 4.02 plus millimeter plus 0.1 millimeter. So this is equal to four point 0- one and this will be mutilated. And now we have to see the significant figure. Here, we have three significant figures. And here we have four significant figures. That means we have to keep only three significant figures. So this would be equals two, 4.02. So this is 4.02 mm. And now Here we have 22 Point this is 22.4 minus 83 So this is 14.1, so this is equal to 14.1. Here we have Three significant figures in here we have two significant figures. So this will be only 14. And in the denominator we have here one point 142 -0.002. So this is equal to 0.14. This is 0.14. And now here we have four significant figure and here we have one significant figures. So this would be eliminated and we have So this is equal to 1.14. So this would be equals to 1.14. And now we have to do the division. So this would be equal to 14.1. This is 14.1 is divided with 1.14 is equal to 12.3684. So this is 12.36, But we have to give only three significant figure. So this would be equals two. Only three significant figures. That means 123 That means we have to upgrade three by one unit. So this will be equals to four and the unit is grams per milliliters. So this would be 12.4 g per milliliter. And now we have given another one. That is one 345 plus zero point 0 to 2 is equal to, this is equal to 1.36736 or seven. And this is Graham. Now this is divided with 13.36 Millimeter -8.4 115. So this is equals two four point this is 4.94859485. And this is a millimeter. So here we have Four significant figure in the nominator and three significant figure in the denominator. So this will be divided with, we get 0.2762. This is a zero 2762 45. This is 45. And this age gram per milliliters. This is graham per milliliters. So we have to keep four significant figure here. So this would be 0.2762. This is 2762. This will be gram per millimeter. And now we have to solve party party, we have given 74.335 -74.33 two. So this is equal to zero. this is 0.003. And this is emitters divided with 4.75 2nd -1.114. So this is equal to 3.636 3.636. And this is second and now we have one significant figure in the numerator and four significant figures in the denominator. So answer would have only one significant figure. So now we have to They were 0.003 with The 3.636. So this is equal to This is equal to zero 00 zero, this is 8-5, this is 8-5 and this will be meter per second. So this would be here. This sign is multiplication sign, so we have to multiply it first. So this is multiplication and now we have to do the calculation. So this is equals two. Now this is equals two. 4.75 is multiplied with 1.114, so this is equal to 5.29. This is 5.2915. And now we have to solve it. So this is 0.00 three is divided with The 5.2915, so this is equal to 0.00 0566 66 And now we have to give only one significant figures. So that means we have to upgrade five by you and one unit. So this will be equals to six. So this is 0.0006 and this will be meter per second square. So this is here secondly square. So this is a meter per second squared. And now this is the answer for a. This is the answer for me. This is the answer for C. This is answer for D. And hear the answer for E.

All right, So our question wants us to find the number of significant figures in each of the following numbers listed here is a through G. And I wrote the numbers. We want to find the significant figures for in Red, and I will write the amount of significant fingers that they have in black. So our first number for part is 214 sort of three numbers. They're all numbers are important numbers, so there are gonna be three significant figures. Okay, Our 2nd 1 is 81.60 Now there is a zero, but that zero is to the right of the decimal place tacked on at the end. So that number is still significant. So there are four significant figures in this scenario here, 7.3 We can't get rid of any of the numbers. They're all important. So there are three significant figures here for Part D. Well, we have 0.3 but we could move that decimal place over and write that as three times 10 to the minus two. So there is on ly one significant figure in this scenario because all the zeros are to the left of our number. Here again, All the zeros to the left of the digits of the numbers that aren't zero are irrelevant. We could move that over, and we have eight and six that are too significant numbers. So there are two significant digits here in party for part F. Again, we have four. All four are important. So we have four significant digits for part F. And then lastly for part G, we have a CE 87. I'm sorry. 716,700. Well, we could move the decimal place over here, which is written to the right of the zero. We could move it over to one two, and we have 87. We could write that as 87 times 10 to the too. So we have two significant figures there. The eight in the Senate. So there we are,

Hello. So today we are going to find the significant figures, the amount of significant figures in a certain values. So let's start with a and A We have zero point for zero zero for and milliliters. So? So, in order to find this guy figures we have to count. How many significant did you start? Well, we know that all non zero numbers are significant. So four and all zeros in between two announcing that the numbers are all significant. So therefore we get four significant figures for next question we have we have 6000 grams. So we see that all these that there's one significant figure right here. But then there is the zeros afterwards, not followed by decimal place. No, not followed by anything. Good numbers. So the zeros are not significant. They they're not. They don't have any significance. So really, we only have one significant numbers here. Next we have we have one point and we have zero zero zero three zero kilometers. So this is a little bit of ah confusing. But we know that every non zero number as significance. So we have that now between two significant numbers, all zeros are significant. So we have three more right there. Now, after the decimal place, any zero that shows up after a number is a placeholder and is therefore significance a significant figure, A swell. So we have a 123456 So this is we have six significant figures here. Actually, not five. This zero is significant, which is very important. Next we have question D in de we're given the number 400 but we can't forget the decimal place That's at the end Nanometers. So now this this decimal place is very important because without it we would only have one significant figure, right, cause all not zero's air, but because there's a decimal place. Now all numbers in between this nonsense the significant number and the decimal place are significant as well. So know this. In this last problem, we have three significant figures

Good problem. 60. No, we have a Well, if I boy 3 to 54 time 90 A boy, 00 205 So they should be. How many's if it one number should be just six. If it so we have for 034 boy 05 disease six afecta So that's good. May we see all we see? 70740 Only 36 ft. So you can we can not. This result we have to round up, become 334 Anesi or 95 7 and you see one get only 56 weeks of the numbers of the FISA. That de this number only faucet is a letter resulting for


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