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CHE411012017. Semarte 2Pat 207sConsider the folotng reacton MO-9) 2NOx9)A0.085 mol sampke & NOz ialoted @ cote pequibnum Wth MO-ma0.50L container &1 25 ...

Question

CHE411012017. Semarte 2Pat 207sConsider the folotng reacton MO-9) 2NOx9)A0.085 mol sampke & NOz ialoted @ cote pequibnum Wth MO-ma0.50L container &1 25 'CCakuale Ie amont (n mel & NOz and MOt Dresent & equllibnum Shom wokig K =461r10 'at 25 'C 0) or5

CHE41101 2017. Semarte 2 Pat 207s Consider the folotng reacton MO-9) 2NOx9) A0.085 mol sampke & NOz ialoted @ cote pequibnum Wth MO-ma0.50L container &1 25 'CCakuale Ie amont (n mel & NOz and MOt Dresent & equllibnum Shom wokig K =461r10 'at 25 'C 0) or5



Answers

Evaluate $\Delta S^{0}$ at $25^{\circ} \mathrm{C}$ and $1 \mathrm{~atm}$ for the reaction: $$ \begin{array}{llcl}
& \mathrm{SiH}_{4}(\mathrm{~g})+2 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow & \mathrm{SiO}_{2}(\mathrm{~s})+2 \mathrm{H}_{2} \mathrm{O}(\ell) \\ \mathrm{S}^{0}, \mathrm{~J} / \mathrm{mol} \cdot \mathrm{K}: & 204.5 & 205.0 & 41.84 & 69.91 \end{array} $$

Defend the reaction off a decomposition or spcl five year Spcl three and also CEO too. And also we keep in the, uh, equally in constant and ah liberal mo's off spcl fee and sell to what would be the yearly Be amenable. More off off the porta and reactive. Okay, first of four, we're going to convert Ah lumber most to ah concentration And then we compulsive coagulation. So we just divide the number one most by ah, volume will be ASUs 2.5. So we have so point when one to motor. And also we have ah so ploy. See your 64 motor? Okay, let's step. You're going to establish your eye stable so we have no spc If I just start riff and then we have zero point, we want you and we're still going to see 164 So from here, because we have, we have First of all, you killed IBM. But we don't have any spcl five So you should have You should have spcl free and I'll say it to reality Shoulder that being consumed will get spcl five So we have my sex, my sex and also we have sex. So we have x zero point where and when to Wessex. And then we're still going to see it was 64 my six. Okay, so the Lexx, sadly, we're going to extend British Doug E. Coli berry expression because you see a point when went to you my six times see off 1064 miles, six over X And this expression, you would be close to 2.5 time tendon. That too. We're going, Teoh. Um, way we're going to self the court tactic equation. Okay, so, um okay, so you can sell for that, And then we should be able to find eggs. Ah, you see, cruise to Syria 0.464 more So this will be who Sue aches. So we are going to plugging extruded Westhoff. Our, um I stable. So first of all, for Corinne, it should be equals to see off on a serial 176 moaner. And they were gonna move by that by, um, 2.5 litre to fight the lumber. Mostly correspondents of syrup or 040 Most Okay, so I'm well funds you low sp CEO Phooey! So we have our Siripong went to my soup or so forces for and then we would have 0.656 Motor is Coy's pointing to 0.16 full mole. And that's when all these were half hour Spcl five very close to see upon so 464 motor and you will be chorus pointing to su a porn 116 most and those that they're a month off spcl if I spcl free and also sales here at E. Coli.

First of all. Let's have a look for tall is given in a problem. Given it moles of nitrogen equals to end malls. Yeah. And for argon, the number of moles. 0.5 molds. Yeah, Yeah. And preacher is given us 27°C.. And pleasure has given us 1 80 M and volume is given us volume has given us six liters. Know what we are supposed to find out. We have to find the number of moles of nitrogen that is n value. We have to find out solution. We can directly apply ideal gas situation here. We know that PV equals to energy Pressure is one volume and six and you know, end plus 0.05 value of R 0.08-1 and temperature is 300. So from here we can find out the value Often It will be nothing but six divided by 0.08-1 and two, equals two and plus 0.5 So this value will come around 0.247 Equals to end plus 0.05 Now, and will be equals to 0.24, -0.05. Does the value of, and comes out to be approximately equal to 0.20. Hence the correct option is option B.

This oneness. Two part question. So let's go to you part A furs. The total pressure would be simply adding on Audie partial pressure. So the total pressure s equals two 0.32 unless 115 plus or in 42 equal. So it would be close to point a night 18. So Flora, part B. If you want to find out the volume we have to use this equation, people won't be one divided by t. One equals two p two v two divided by t to you. Okay, let's break it down. So the first pressure would be this 0.898 So p one with the equal student initial total pressure. So p two well equals two because it's set and nitrogen gas is removed. So man, remove coin 32 there so it would equals two from 13 plus 1 40 So which is sequence too? Or in 55? No, Sorry that that there was a mistake. I misread it by my ugly handwriting is to be porn 57 But a correction and initial volume is 2.5 litre and the initial temperature would be 15 plus 2 73 lead size to you. 80 a Kalfin and T to the final temperature would be to 73 because it set is at STP. Okay, so you have all the information you have and pluck it back into the equation. So you will do 0.89 Multiply by the volume 2.5 divided by the temperature to a d a. You close to par show? No, I was the pressure to multiplied by V two and divided by to 73. So if you do the calculation v two, we're equals to one point for leader and this is your answer.

Problem. 67 says to rationalize the lattice energy values of each of these four compounds and discuss why they make sense relative to each other. So once we've discussed in previous problems, um, two aspects of an ionic compound that makes them relatively x author, Miss X if emmerich and regard to lattice energy our, um, e a charge on the ions and the size of the ions so hire charge usually leads to a more x a thermic Gladys energy. And a smaller size also leads to a higher, um, Gladys Energy. So in this case, um, first of all, it makes sense that, uh, the compounds containing calcium have a more x a thermic ah lattice energy, because calcium has a positive to charge and selenium and Tillery, um, have a negative to charge. This is a comparison to sodium, which has a positive one charge. So for each of these compounds, the higher charge on calcium leads toothy kind, greater lattice energy. Um, and then, with respect, thio um, the compounds containing selenium versus terrarium um uh, selenium iss smaller, then delirium. And in general, like I said, smaller ions tend to have larger lattice energy because two ions can, um can basically get closer together, and their attraction is much higher. So for that reason, it also makes sense that the lattice energy on compounds containing selenium versus Hillary um is higher. Um, And so in that case, um, it does make sense that the order of lattice energy is that calcium, um bound to selenium is the highest because it has the largest charge and the smallest ions, followed by calcium pounded Towler M and then sodium in that order.


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