5

Evaluate_5 2 ffwys dx dy...

Question

Evaluate_5 2 ffwys dx dy

Evaluate_ 5 2 ffwys dx dy



Answers

Evaluate dy/dx at the given points. $$2 y+5-x^{2}-y^{3}=0 ; \quad(2,-1)$$

Into this lesson in this lesson performance implicit differentiation question at the point five and one. So let's start with the differentiation. Mhm. Mhm. Mhm. Yeah. Mhm. So here we have three on 2 then we we reduce the power by one so we have half. Then we differentiate what we have in a bracket. So this becomes y minus X, divide Yepes minus two. I you I. D. X. Then go to the left hand side is the constant. So we have 10. Why do ideas at this point we can put in the values because a lot of expansion. All right yeah so we put in 54 X. Than one. For why? Yeah mm. What? Oh mm. Yeah wow. Yeah Okay so at this point you have three on two that is 4 -1. Uh 5 -1 sort of those four Square root of four than one. So here we have five oh mhm. Five minus two. And that gives us -7 do I? The X. This is equal to 10 d. y. e. Okay so at this point we have this to goes there so we have three out one minus seven Y. Dx. Yeah. Mhm. And that is a call to 10 do i. x. So you multiply up three when it's 21 Y. Dx. Does she called to? Okay. 10 wide yaks. Then we have three. That is she called to? Yeah. 10. The last 21 do I. D. X. So this becomes three is according to 31 do i. d. x. And this is equal to dy dx? That is equal to 3/31. Okay so the ideas at five one is given to us this way. All right. Thanks for the time. This is the end of the lesson.

Welcome to this lesson and this lesson will perform. And place the differentiation all we have here. So we write it in another film. Yeah. So we take the mhm french show on both sides. Oh yeah so would have six then X plus Y. You differentiate what we have in a bracket? So that is one. The last dy the X. Then -2 Y. X. To the bar negative one. Do I. D. X. We now hold Y squared. So this becomes positive. Mhm. Actually a pretty negative too. So why is quiet this is equal to zero. Because if you differentiate a constant zero. So here we have six X. Last y squared. The last six again X plus Y squared Y. D. X minus two. So this is to okay what? Yes the last X score 20 At this point we would group the divide yet. So there we have six X plus Y. To the power to minus two. Yeah in one bracket And all the others at one side. So this becomes negative, it goes to the other side. Okay, so here we can make the new ideas are subject so that is negative out. We have six. Mhm mm hmm. Uh huh. Yeah. Yeah. Fuck it out. The okay. Okay. Oh, negative. All right. So at this point we can put in the values of X and Y. So at four a negative too. Mhm. Of the -6. So this is 4 -2 squared the last four. Mhm. Mhm. Yeah. Yeah. Thank you. Okay. Yeah. So that is negative. Mm. Okay. Mhm. Okay. Oh. Uh huh. Yeah. Yeah. Oh, okay. Yeah. Yeah. Yeah. Oh, okay. So this is the end of the lesson. Thanks for your time. Yeah.

Into this lesson in this lesson would do an implicit differentiation And the value that three and -2. So let's begin. Yeah. Mhm. Taking the differential of both sides with respect to X. Okay, So this is 20 y. to the Bathory no word yet. Lazo Friendship Constant zero. And here we have four x. The path 3 -3 dy dx. So if you differentiate by we have new ideas at the end because the function is in X. And its respective of Why? All right. So at this point we have 20 Y. To the path three. Do I. D. X. We would add 30 ideas to both sides. So but yeah we can have four As the path three and this one is gone right? I respond we factor how do I. D. X. And this is 20 y. to the Bathory last three. That is equal to four x. To the past three. At this point we can divide by 20 Why? To the Path 3? Oh that Uh huh. Yeah mm. So this cross yourself that we have. Mhm. Dy dx that is equal to four X. The Bathory all about 20 Y. To the bathroom of the last three. So at sorry negative too. Yeah. Mhm. Would have four. Yeah. Yeah. Mhm. Yeah. Yeah. So this keeps us four times 27. All of the -160 last three. So do I yet. Okay. Mhm. Mhm. At the point we have specified it's called to I get tip 108 all over 15 somebody. Okay so fans of the time this is the end of the last

Question. Question 49. We need to differentiate this implicitly to get the value of the well with the X step to Let's differentiate this. Both sides we have D o d X off X rays to the par minus two was D over DX off virus to the ball minus two different station of constant as a zero. Using the powers rule, this comes out as minus two X rays to the par minus three plus minus. Two. Wire is to the par minus treaty by over the X using the change rule. This is equal to zero, dividing both sides by minus two. This will cancel out. We're left with X X rays to the ball minus tree can better than us one over. Execute on X rays to the virus to the ball ministry is one over Y cube. Devour D X is equal to zero if you subtract. If we take this over to the right, we have diva or D X Times one or y cube as negative one. Work X Cuba. And if you multiply both sides by Y Cube, we have diva or D excess, minus off. Why Cuba excuse. So this is the final expression


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