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Question 7 (5 points) The following reaction can lead to a mixture of 4 aldol condensation products. Draw the products, and circle the one you would expeci to be th...

Question

Question 7 (5 points) The following reaction can lead to a mixture of 4 aldol condensation products. Draw the products, and circle the one you would expeci to be the major productNaOH heatQuestion 8 (5 points) Draw the mechanism for the following reaction:NaOEt 2) Hjo

Question 7 (5 points) The following reaction can lead to a mixture of 4 aldol condensation products. Draw the products, and circle the one you would expeci to be the major product NaOH heat Question 8 (5 points) Draw the mechanism for the following reaction: NaOEt 2) Hjo



Answers

Draw the product (including stereochemistry) formed from each pair of reactants in a thermal [4 + 2] cycloaddition reaction.

Okay, so you get the products with falling reactions. In the first one, we have purple dark acid with ammonia and just don't heat. Okay, so the car bostock acid has a lower P. K. The pneumonia, it's gonna behave the worst acid. And ammonia is then going to. Do you need a pair of electrons to form bomb the hydrogen of permanent acid? And this is really the only hydrogen can grab. You can't get any from over here the lecture and go back to the oxygen and be as much negative. So we need the structure, I'm guessing NH four as well. So, in the presence of heat and around 200 yourself, 200 degrees Celsius, we're actually gonna get a carbonic acid. I mean, he um didn't came out. So if we drop the oxygen and just add this NH two group, we have a loss of water as well. See too hard regions from um and H four than the auction from the Canada based permanent acid X one. Is this imode with water and heat. Do you have a four carbon Ahmad. So we can t minus C. O N H R C O. N. Function group that she could be attached to to hide regions or some are groups. But um the mean is more basic than water. It's going to impersonate water really. A NH three. What is a weak base. So it's got the bigger but we're also going to get hydroxide too strong base. And what's that? A curse going to attack the carbonell carbon. And once we get the cox that I on, it's got to reform the double bond the oxygen to expel ammonia because again, it's a weak base. It's good leaving group. So the addition of so each group that and will Catalonia, this is side products. X one is a before carbon Esther with sitting hydroxide heat. Okay, so city metro oxide is a strong base. It's going to attack the carbon or carbon directly with their cocks an eye on and it's going to reform to expel the um the proceeds through the proceeds through your burger addition of a witch and then a fox side. I am Okay so the methotrexate on stronger base than permanent acid as a result is going to grabbed parents on from permanent acid and we're gonna get the structure. So the negative charge the oxygen is going to pair it with the stadium from sitting my drug side and the salt. So we're gonna get methanol side products one smith oxide departments the hydrogen of permanent acid.

Okay, and we're going over. Question number 42. We talked about rain and then inclusion. Further action has given, and your reaction is sodium hydroxide. First I drove for my passage sodium hydroxide plus e control. I own it baskets and set up on space manure in English to your I think it goes to your wage So you have any which is a plus. Hi. Which is the minus. When you look at the table, it's a quiz pressed H o h, which is wonder I'm saying liquid, Then you do it by my own. So in plus plus o h minus plus each plus plus I my news pressed to any plus plus I minus plus water No. Then speculations and I and our on the same side and the same pain source so shortly. Um mm e, which names you with h plus equals the story minus in Queens This race to wonder. Not so they could

And this question. We were asked to draw the major products from the reaction of one equivalent of HBR witchy with each of these compounds and then to indicate the kinetic and thermodynamic products. So these are both going to give us 12 and 14 addition products, since both of these compounds are dying's, And so to figure out what those air gonna look like, we're going to start by numbering the dying. So numbering just the four carbons that are participating in those double bonds. Um, and we're gonna number them to get the most stable carbo cat lions on each side. So we can either go. 1234 or 1234 Our car broke a tie ins will always be on carbons two and four, So we'll take a look at what those would be. So if we went from the left on this top one here, that would be, uh, a secondary four, number two and tertiary for number four. If we went from the top, it would be tertiary for number two and tertiary for number four. So we're gonna go with the way that gives us to tertiary carbo cat Ryan's still number like this. And the first stop is always to take that one to double bond and grab the hydrogen with it and kick that bro me in a way. And that gives us a carbo cat. I an intermediate. So that will look like this for this structure. So the three and four double bond hasn't moved. We have a carbo cat, I and a number two since that's the Elik position. And that hydrogen went on the carbon one to make it to give it that fourth bottom that it needed. And then we have a broom ing nuclear file leftover. Now, this also has a resident structure to tell me it to the 14 product. So we move this double bond like this, we get a second residence contributor for that carpet, can I? And it looks like this. So now the double bond is their car broke. Iodine is there. So then we'll get to products here. Um, on those occurred just from the brahmi nuclear file attacking each of the carbo cat ions. So from that first car broke out, Ryan that I drew will get the 12 products and that will look like this. So this double bond is still here, and our bro Ming is on that carbon. And then from the second one that I drew, um, we'll get the bro mean over here. Um and so that will be our product there. So this is our 12 witnesses are 14 and then as far as kinetic and thermodynamic products, the kinetic product is always the one to products. This is kinetic, and that's because of the proximity effect to me effect. So the proximity effect just means that if we're under kinetic conditions, we don't have a whole lot of energy to spend. Um, the Carbo catalon is right there when the bro mean is detached from the Kardashian. So when the broken becomes that nuclear file, that carbo Catalan is right there ready to be attacked. So it was just the closest thing. So just due to proximity, as it's named for, that will be that product left the kinetic product. And then the thermodynamic product is always just the most stable double bond on DSO here. We're gonna look for the double bond that is the most substituted. Now here we have three substitution on each side, which means that the double bonds are pretty much the same stability. Um And so, um, for here we can't determine which one is the thermodynamic products because they're the same stability. We don't have anything else to go off of, um, to figure that so we don't know what's around, and I'm a product is here, or they're both of their mother. Never brought it. Um, more likely. If you're under thermodynamic conditions, you'll get equal amounts of both Bronx and then for part B will do the same thing. So well, number our carbon. So if we were to go from the left here, um, we would get tertiary for carbon to and primary for Harvard four if we went the other direction. We get secondary for two and tertiary for force. That's what we're gonna do. 1234 We'll use that one to bond a grappa, hydrogen and kicked the Bruning off. Leave us with a nuclear file, and then we'll get our first, um, carbo cat on intermediate bond number two and we can resonate that to get a car broke out. I in on number four as well so I would look like this. And then we'll get our two products from those intermediates by just attacking them with Ebro mean? So this would be the first one. This is the one to product, and then the 14 product would be this one. So then, like I said before, the kinetic product is always the one to product because of the proximity effect. And the thermodynamic product is which everyone has the more stable double bond, a k a. The more substituted out king. And so here that is going to be the one to product as well. Since one of substituted on all four sides, this one is only on three sides. So this will also be the thermal products because the al peen is more stability more stable, So that is part B.

So we re estimate the products of the following reactions. Yes, First one is perfect. Yes, with hydrogen gas ever palladium. And this isn't it is high hydrogenation and producers in Aachen, And this occurs with Sin Edition meeting ads on both sides. The second one is two beautiful. So sulfuric acid is used to promote elimination over substitution. Just the one. And this reaction is an example of a substitution. So if we react this with HBR, the the first step is the same. In both cases, it's going grab. Ha Jin. We now have a good leader group, but deeper means get attack from the back and kick this out. And this would be it could occur in one step, mhm, resulting in this or marriage all that. Yeah, such a being version of stereo chemistry. So if this were in the front, this would be in the back because the bird made it be a much better nuclear file than sulfuric acid. So sulfuric acid is used to favor anyone over lesson two. But in this case with sulfuric acid, we have the stuff worms and then leaves Yeah, the secondary carbon head. On the next step is for water to attack. And yeah, water can grab this hydrogen or this one. But this one is favored because it will create an internal Al Keen or a Di substituted. All keen, so demanding, too and substituting. Meaning that we have two of apples and internal Elkins are always more stable than secondary. I mean, Primerica, Algerians. And this is the e confirmation. Yeah.


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