And this question. We were asked to draw the major products from the reaction of one equivalent of HBR witchy with each of these compounds and then to indicate the kinetic and thermodynamic products. So these are both going to give us 12 and 14 addition products, since both of these compounds are dying's, And so to figure out what those air gonna look like, we're going to start by numbering the dying. So numbering just the four carbons that are participating in those double bonds. Um, and we're gonna number them to get the most stable carbo cat lions on each side. So we can either go. 1234 or 1234 Our car broke a tie ins will always be on carbons two and four, So we'll take a look at what those would be. So if we went from the left on this top one here, that would be, uh, a secondary four, number two and tertiary for number four. If we went from the top, it would be tertiary for number two and tertiary for number four. So we're gonna go with the way that gives us to tertiary carbo cat Ryan's still number like this. And the first stop is always to take that one to double bond and grab the hydrogen with it and kick that bro me in a way. And that gives us a carbo cat. I an intermediate. So that will look like this for this structure. So the three and four double bond hasn't moved. We have a carbo cat, I and a number two since that's the Elik position. And that hydrogen went on the carbon one to make it to give it that fourth bottom that it needed. And then we have a broom ing nuclear file leftover. Now, this also has a resident structure to tell me it to the 14 product. So we move this double bond like this, we get a second residence contributor for that carpet, can I? And it looks like this. So now the double bond is their car broke. Iodine is there. So then we'll get to products here. Um, on those occurred just from the brahmi nuclear file attacking each of the carbo cat ions. So from that first car broke out, Ryan that I drew will get the 12 products and that will look like this. So this double bond is still here, and our bro Ming is on that carbon. And then from the second one that I drew, um, we'll get the bro mean over here. Um and so that will be our product there. So this is our 12 witnesses are 14 and then as far as kinetic and thermodynamic products, the kinetic product is always the one to products. This is kinetic, and that's because of the proximity effect to me effect. So the proximity effect just means that if we're under kinetic conditions, we don't have a whole lot of energy to spend. Um, the Carbo catalon is right there when the bro mean is detached from the Kardashian. So when the broken becomes that nuclear file, that carbo Catalan is right there ready to be attacked. So it was just the closest thing. So just due to proximity, as it's named for, that will be that product left the kinetic product. And then the thermodynamic product is always just the most stable double bond on DSO here. We're gonna look for the double bond that is the most substituted. Now here we have three substitution on each side, which means that the double bonds are pretty much the same stability. Um And so, um, for here we can't determine which one is the thermodynamic products because they're the same stability. We don't have anything else to go off of, um, to figure that so we don't know what's around, and I'm a product is here, or they're both of their mother. Never brought it. Um, more likely. If you're under thermodynamic conditions, you'll get equal amounts of both Bronx and then for part B will do the same thing. So well, number our carbon. So if we were to go from the left here, um, we would get tertiary for carbon to and primary for Harvard four if we went the other direction. We get secondary for two and tertiary for force. That's what we're gonna do. 1234 We'll use that one to bond a grappa, hydrogen and kicked the Bruning off. Leave us with a nuclear file, and then we'll get our first, um, carbo cat on intermediate bond number two and we can resonate that to get a car broke out. I in on number four as well so I would look like this. And then we'll get our two products from those intermediates by just attacking them with Ebro mean? So this would be the first one. This is the one to product, and then the 14 product would be this one. So then, like I said before, the kinetic product is always the one to product because of the proximity effect. And the thermodynamic product is which everyone has the more stable double bond, a k a. The more substituted out king. And so here that is going to be the one to product as well. Since one of substituted on all four sides, this one is only on three sides. So this will also be the thermal products because the al peen is more stability more stable, So that is part B.