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Tube and ContentsMolalityMilliosmolality1.) 10g/100ml NaCl2.) 3.Sg/100ml NaCl3.) 0. 85g/100ml NaCl4.) 0.45g/100ml NaCl5.0.2g/100ml NaCl...

Question

Tube and ContentsMolalityMilliosmolality1.) 10g/100ml NaCl2.) 3.Sg/100ml NaCl3.) 0. 85g/100ml NaCl4.) 0.45g/100ml NaCl5.0.2g/100ml NaCl

Tube and Contents Molality Milliosmolality 1.) 10g/100ml NaCl 2.) 3.Sg/100ml NaCl 3.) 0. 85g/100ml NaCl 4.) 0.45g/100ml NaCl 5.0.2g/100ml NaCl



Answers

What is the molality of $\mathrm{NaCl}$ in a solution that is $3.000 \mathrm{M}$ $\mathrm{NaCl}$, with a density of $1.07 \mathrm{~g} \mathrm{~mL}^{-1}$ ?

So here we have a question where we've been asked to translate from mass percent to mull ality, and so any time a problem gives you a in goal, it's really important to kind of understand how the in goal is put together. So our angle here is Mulally until it's refresh right quick on our formula for morality, define morality. You need to have the moles of Saul Ute in the numerator and the kilograms of Solve it and the denominator. And so we'll need to have both parts of the equation before we confined the final morality of the solution. Now the starting information that they give us is that our solution is 3.50% sodium chloride by mass, and so percentages are taken out of, ah, 100. So this is a mass percent. What this translates to is if we assume 100 grams, that means that 3.50 grams of the solution would be sodium chloride, which is our saw. You. Then, if we subtract from 100 that tells us that the other 96.50 grand's would be do tow water, which is our assault mint. And so this is going to provide the basis of giving us what we need to find morality. So let's go ahead and take care of the saw it first for the morality formula. Are Saul you? It needs to be in moles instead of grams, so let's go ahead and convert from grand. So moles using the Moler maths so good our periodic table and we'll look up sodium, which has a mass of 22.99. And add to that chlorine, which has a massive 35.45. This gives us a total of 58.44 grams per mold. We can then solve this in earth calculator by doing 3.5, divided by 58.44. That tells us that they're a total of 0.599 bowls of sodium chloride that will become the numerator of our overall morality formula. Now we need to take the grams of water and convert it to kilograms know grams or 1000 times smaller than a kilogram. So there are 1000 grams within one kilogram. So do this conversion will be dividing by 1000. This tells us that we have 0.0 965 kilograms. Our solvent, which is water. We'll put that into the denominator of our fraction. And then we'll divide to find our final outing that comes out to be 0.62 One more, allow that little emits just coming to symbol.

To calculate morality, we need to know the moles of the solute per kilogram of solvent. If we're given a mass percent of 19.5, then that means for every 19.5 g of sodium chloride, we have 100 g of the entire solution. So to get morality, we need to convert the 19.5 g that we have in 100 g of solution to moles by divided by the molar mass of sodium chloride, and then we divide that by the kilograms of just the solvent. However, this is the amount that is in 100 g of the entire solution. So we need to subtract off the mass that is the salute to just get the solvent. Then we'll convert the g of just the Solvent two kg. By dividing by 1000 Then we will have moles of solute per kilogram of solvent, which is morality. And we get 4.1 formal al sodium chloride.

To get the bahnhof factor, we first need to determine the morality. Morality can be calculated from mass percent. By converting the mass percent in grams of the salute into molds salute by dividing by the molar mass. If it's .5 mass percent potassium chloride than 100 g sample would have .5 g potassium chloride. 100 g sample would also have 99.5 g of water, which we can convert two kg. Then we have moles per kilogram solvent And that's morality .0674. Morale bahnhof factor can then be calculated by taking the freezing point depression, setting it equal to I multiplied by the freezing point constant of water and morality And I is 1.87 for this potassium chloride solution. Next we have a one mask per cent sulfuric acid solution. So 100 g sample will have one g of sulfuric acid which will convert to moles and 99 g of water which will convert two kg and we get 20.103 mil al sulfuric acid. Well then use the freezing point depression equation. As we did appear to solve her, I will take the freezing point temperature set it equal to I multiplied by the freezing point constant and morality And I is 2-1

So now we'll work on problem. 109 from Chapter 13 in this problem were asked to calculate the morality and Ben Hall factor for two operas. Solutions. In the first case, we have a 0.5% K c l solution, and we're told that the freezing point is a negative zero 0.243 degree Celsius 234 Excuse me. So, first of all, we have a percent mass concentration so we can convert that morality by calculating moles of Casey. Oh, So since we have 0.5% case, yeah, we can assume that we have 0.0 05 kilograms of K CEO her one kilogram of water. If you calculate the percentage using those two values, you'll get 5% or 0.5%. So 0.5 kilograms is five grams, and we can convert that to moles by dividing by the molar mass of que CEO, which is 74.55 and that gives us a value of 0.0 671 moles. Since we set our value of water at one kilogram, that means our value for morality is the same as what we have for the moles. So what we need to find out is the morality which we just calculated. And then we need to find out the Band Hall factor. So we know DT DT has given in the problem as naked of 01234 And so we just calculated morality. Um, so we can plug this into our equation and we know the freezing point constant for water is 1.86 degrees Celsius per morality. So from this, we can calculate our value for high by simply dividing both sides by this term here. And when we do that, we get a value of I as 1.87 So it's close to two, as we would expect. But it's not completely too, because it's not ideal behaviour. So for Part B, we have a second situation which is 1% massive severe gas and H two s 04 So that's and we also have a value of negative 0.423 as our freezing point. So again we can assume Ah, a certain mass. So we have 0.1 kilograms, uh, for one kilogram of water. So we have twice the mass we did in the previous exit. Then we did in the previous example, because we have twice the mess percent. So again we convert from this moles this grams two kilograms, so 0.1 kilograms since 10 grams. And then we can convert that to moles by dividing by the molar mass, which is 98.79 It gives a value of 0.102 moles, which, because we have said, are, um, concentration is per one kilogram of water. We can directly convert to reality. So that's the first answer then who are given DT in this problem as, uh, negative 0.4 to 3. This is equal to I negative. I The Morality times the freezing point constant, which is 1 28 6 And so we calculate our high value by dividing both sides by the morality and constant. To be 2.23 it's above two because it's us. So for us, a diaper to Cassidy. So, um, both of these hydrogen have a chance to go into solution


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