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Convet #Ke fstm Cvo(dmaks jategre) 'n (eu} anbvl to cpker Ia) Cu(dinulei Snl CValvalo 4- Fy Jr dxey $s X2+y-' VA-v...

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Convet #Ke fstm Cvo(dmaks jategre) 'n (eu} anbvl to cpker Ia) Cu(dinulei Snl CValvalo 4- Fy Jr dxey $s X2+y-' VA-v

Convet #Ke fstm Cvo(dmaks jategre) 'n (eu} anbvl to cpker Ia) Cu(dinulei Snl CValvalo 4- Fy Jr dxey $s X2+y-' VA-v



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

In this problem we have to find a frequency distribution for the given data of the viewing Audiences and Millions for the Top 20 Television Shows. And here we are going to use the cut point grouping as a data or continuous. So it's given we have to use the first class. Wolf 12 213. Okay. Mhm. So here. Yes. Yeah. Medium season limb. Yeah. Uh huh. Mhm. So the first classes Child 213. Yeah. Okay. Mhm. To the next class is 13 to wonder. 14. This will be 14 two Under. Hmm. So it goes still 20 10 to only 16. Thanks, Jonathan Under 17. Mhm 17 to Mhm Under 18. Mhm 18 to UNDER 19, 19, 2. And I can t So first twin Chill. The 13 will be Mhm. And one. Okay. Three. Next will be 13 to 14 Will be 1, 2. Yeah. 345 Yeah. Yeah. Yeah. 14 to 15 would be 12 12 Beautiful. 15 to 16 will be Mhm. Mhm. 123 in four. 16 to 17 would he run? And 17 Tueting Divine. Mm 18-1921. Year one. If you see the total of the sample size is 20. Now we have to find out later frequency distribution which will be the corresponding frequency divided by the total sample size. Which is 20. So three by 20 will give us 0.15, Extremely five x 20. She's going to be 0.25. It's just full by 20. Just point to Thanks jess one by 20. Yeah, That is .05. Yeah. Right. Yeah. Now facing the daughter, It's going to be one. We have to construct construct instagram. Now here is instagram. Yeah. For the frequency, the top broadcast shows. So if we see 12 UNDER 13, we have taken the classes, cut point grouping glasses along the Yeah, horizontal axis and the frequencies along the vertical axis. So for 1213 It will be three. So it's your 13 and 14. Just five, 14 and 15 before it's going to before the rest will be one each. Now, this is the instagram for the later frequency, which is our option D. So we have taken classes Along the horizontal axis and related frequency along the vertical axis, and the vertical bar presents a corresponding later frequency of the particular class, 12- 13 and 13. The related frequency is .15, which is here for the next class it is .25. For the next two classes, it is point to here And for the next four classes at this point 05 Yeah. Right.

I'm writing the reaction which is really event to the micro's cosmic salt bead aged. So just look at it carefully and I think that taste the relieving reaction, then see, oh, we'll react with anne B or three, then the product form it. Any issue, be all four. And according to the problem, this is the answer. So option B is only got it answer for this problem.

In this problem. We asked our ass to find the center of mass of this two dimensional system with the masses. 2 8 to 1 and four in the positions. Negative three negative. 100 And negative one, too. In order to find the center of mass, we first need to calculate the center mass in the ex direction, which we will do by calculating the moment in the UAE direction divided by the total mass. Once you've done that, we will calculate the, um, center of mass in the wind direction. Just calculate the moment in the ex direction of over the center of mess. Okay, So calculating Expert, um, the moment of wise calculating by multiplying the masses by the X coordinates. So we have eight times negative. Three plus one time, zero plus four times negative. One all over. The total mass, which is given by eight plus one is nine plus four gives us 13 doing some arithmetic. We can find out that eight times negative three is negative. 24 0 minus forgives us negative. 28 over 13. Now, to find the center of mass in the UAE direction, we're going to take the moment of X, which is the masses times there. Why Coordinates? So we're going to have eight times negative. One plus one time, zero plus four times two all over the total mass, which is still 13 here. Only two are particularly. Get negative 80 plus h, which gives us zero over 13 for our center of mass. Explore why BAR is given by the coordinate point. Negative 28 over 13 from a zero.

In this problem, k i and KI 03 odd the service stance used for preparing used for preparing. I would I'D so g i N, The I 03 used for preparing iodized salt so it's an A and B are correct here. The airport option A and D r correct answer for this problem.


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