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There is no reaction under these conditions or the correct product is not listed here....

Question

There is no reaction under these conditions or the correct product is not listed here.

There is no reaction under these conditions or the correct product is not listed here.



Answers

Identify the reactions which yield the product shown under the given conditions

So in this podcast we're considering Markov Nico's rule eso when the reacting at R C to position the carbon already has a definite groups about the asymmetric carbon, so the configuration would not change when the compound reacts with HCL. The product with the changed configuration at C two does not form as the product. So what we have here is ch three on. We have several different substitue INTs, somehow logins as our final product.

Hi everyone. So in this case, option abc are correct. Option Oh, A B and see are correct. In all these options on this option not given is correct. Throw it out. Given is correct. Cool. Thanks.

Okay. This problem saying that these reactions will not produce a product in a particularly high yield. So first up, we have my overhead, and that is going to undergo erection with key tone with a sodium oxide base. Okay, so it is saying that the product will look something like this. Don't you have Carbonell and my alcohol there? Okay, so even those look, this looks to be the Aldo reaction. It is actually going to condensate even further because I have my either sodium hydroxide. Or I could even have my building starting with oxide, which I have this compound that is just going to D protein, ate my state of hydrogen and then move the electrons on that single about making a double bond and kicking out that, um, alcohol. So I should end up with the conversation product instead. Okay, Next up, I have this reaction in which I have my cycle heck, sane carbon on top and a metal group in the bait acquisition, and that I am reconnect with a alphabet on saturated system and same things before that is in a sodium heath oxide base. Okay, So what is going to occur? It is saying that this is my product in which I have virtually the same product, except they're just connected that. Okay. So even though this looks to be approximately correct where we would have this as my ending product, this would actually even go a further reaction called Robinson English. Because right right here, I've made my Michael addition these air the Regency for Michael Addition. But then because if I ended up with sort of beef oxide, that sort of meath oxide is going to D protein ate my acidic hydrogen, which could potentially be this one right here on my awful carbon. If I d prone at the alpha carbon and move the elections off, the carbon would end up with the impairs their that could potentially go under, undergo a, um, al conversation in which I move the electrons onto this carbon, resulting in a 123456 member drain. Okay, so this would undergo a further action to produce a Robinson and Elation products. Okay, so next up, we have this one in which we have a key tone. So dyke ito, okay. And what is gonna happen with this? This is going to undergo erection with Children. He thought side and it will produce this product in which we have a cycle beauty mean with key tone and then my method group. Okay, so why is this not the desired product, even though this is technically correct and it's not gonna get undergo a further action, the formation of the cycle butane is not favorable because cycle beating has bond angles of approximately 90 degrees. And we would much rather have a bond angle of 109.5 just because of the SP three hybridization of those carbons. So we would not want to have something with so much English rain, it wouldn't be very favorable to make that occur.

Here for the solution for the party two Brahma beauty undergoes elimination with rotation start built oxide and gives to product in which one is measured and the other is minor. Therefore, the reaction undergoes elimination but not substitution. Has the reaction for this that to promote beauty undergoes and gives built one in and the beauty to win beauty one in which is minor and a built to in which is major Now for the part B flooring is a bad living group, so it does not undergoes a substitution reaction. Therefore the reaction undergoes the elimination reaction. So has the reaction that Flora cyclo Hazan which gives cyclo hexane by the elimination now for the Parsi one metal cyclo hexane all is a tertiary alcohol, so it does not undergo as into reaction. Therefore, the reaction undergoes E two elimination and form one metal cyclo hags One in as you can see the direction it forms in the presence of fire lines. A base that one metal cyclo, hexane, one aid. So this is the solution. Please go through this. Thank you


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