5

For problem below; assume the population is normally distributed:boltled water association says the mean number of 8-ounce glasses of water American adults drink ea...

Question

For problem below; assume the population is normally distributed:boltled water association says the mean number of 8-ounce glasses of water American adults drink each day is less than 5.0. The number of 8-ounce glasses of water random sample of 24 American adults drank in one day is listed_ Ata = 0.05, there enough evidence to support the association claim?3.64.53.6 3.12.,5 6.05.63.02.627 2.9 Identify the null and alternate hypotheses Also state the level of significance. Find the test statistic

For problem below; assume the population is normally distributed: boltled water association says the mean number of 8-ounce glasses of water American adults drink each day is less than 5.0. The number of 8-ounce glasses of water random sample of 24 American adults drank in one day is listed_ Ata = 0.05, there enough evidence to support the association claim? 3.6 4.5 3.6 3.1 2.,5 6.0 5.6 3.0 2.6 27 2.9 Identify the null and alternate hypotheses Also state the level of significance. Find the test statistic. Find the P-value: Decide whether t0 reject or fail to reject the null hypothesis. Explain vour decision using complete sentences: Use complete sentences to interpret the decision in the context of the original claim.



Answers

Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Use the P-value method unless your instructor specifies otherwise. Use the normal distribution as an approximation to the binomial distribution, as described in Part 1 of this section. In a survey of 3005 adults aged 57 through 85 years, it was found that $81.7 \%$ of them used at least one prescription medication (based on data from "Use of Prescription and Over-the-Counter Medications and Dietary Supplements Among Older Adults in the United States," by Qato et al., Journal of the American Medical Association, Vol. 300, No. 24 ). Use a 0.01 significance level to test the claim that more than $3 / 4$ of adults use at least one prescription medication. Does the rate of prescription use among adults appear to be high?

Let us read this questions. A consumer group claims that the mean annual consumption off charities by the person in the United States is at most £10.3 at most, 10.3. So it means that this is less than or equal to 10.3. This will be my null hypothesis. My alternative will be that mu is greater than 10.3 random sample off 10 people. Sorry. 100 people in the United States has a mean annual cherry cheese consumption of £9.9. So my expert is 9.9. Let me directly right the formula for the statistic It is 9.9 minus 10.3 upon What is this? Population standard deviation 2.1 divided by route hundreds. Okay, this is 2.1 divided by 200 which is nothing but which is going to become tense. So if I use a calculator 9.9 minus 10.3 divided by 2.1 multiplied by 10. So this is minus 1.90 minus 1.90 This is my Z statistic. Alright, what is my Alfa Alfa 0.5 and I can see over here that this is a single table test, right? What is going to be my? Have you made a mistake in the null and the alternative? The null is that mu is less than or equal to 10.3. And the alternative is that Mu is greater than 10.3. Okay, All right. So my Z value is turning out to be minus 1.90 My sense statistic is minus 1.90 So what is going to be my predict? Sorry. What is going to be my p value? My people, if I use a P value calculator, my people, who turns out to be 0.97 20 my p value for this turns out to be zero point. My p value turns out to be 0.9713 9713 This is my P value on. Since this is this was going to be a right tail test. I can see that my said statistic is over here, so definitely I will not be able to reject my hypothesis. I do not reject minor hypothesis, which means that I do not have enough evidence to say that my mu is greater than 10.3, right? I do not have enough evidence to say that my mu is greater than 10.3. Uh, this is going to be my answer.

So we believe that the mean number of ounces is 12 ounces and alternately, it doesn't say anything about trying to find if they're under filling or over filling. So we're going to use the not equal to and do a two tailed test. Now they found that the mean was 12.19 ounce. And we had a standard deviation of 0.11 ounces. And we have a sample size of 36. And so again, we're going to assume that 12 is the center and we're getting 12.19 And since it's a two tailed tests are also going to be finding both of these together will be our P value. So, well now I'm going to do this finding the P value and not doing it with the finding the critical T value. So what's the likelihood of sampling If the mean is actually 12 and getting 12.19 for a mean? Now we want both ends of the tail, so we're going to double that. So we need to convert that to a T. Value and we would have 35 degrees of freedom and we'll take our 12.19 minus 12 and then divided by the standard deviation or the square root of an and when we do that calculation that numerator becomes 0.19 divided by and then 0.11 and that looks like that's divided by six. And that comes out to a test statistic holy moly that test statistic comes out to be uh make sure I didn't type anything in in incorrectly. We get a test statistic of 10.36 and if we find that p value that's going to be approximately zero. So we actually have strong evidence what evidence against the null since this is way less than 5% which is our significance level. And so we would say that the mean the main seems to be different is different. Mhm. From 12 ounces now and again our p value is very very close to zero. It's a little bit bigger than zero. Now, it asked, does this does this end up show evidence in the way they were to the question that does it say that the people are being cheated and no they're not being cheated. Not cheated. Uh It looks like they're actually getting more than 12 ounces. So we didn't do that significance test for more than but it doesn't appear as though they're getting cheated. What?

Let us read this question. A consumer group claims that the mean annual consumption of high fructose considered by a person in the United States is 48.8. So mean is 48 is 48.8. So this is going to be my It's not or my null hypothesis. What is my alternative hypothesis? It is going to be that this is not equal to 48 point it. Okay, a random sample of 1. 20. So let me just directly right the formula. My N is equal to 1. 20. So over here, I'm going to have root off 1 20 route off. 1. 20. Uh, a random sample of 1 20 people in the United States has mean off 49.5. So the mean is 49.5 14 9 0.5 minus. What does my hypothesized mean? 48.8 divided by what is the population standard deviation? It is 3.6. So this is 3.6. Let me use a calculator to find this. So this is 49.5 minus 48.8, divided by 3.6 multiplied by. Excuse me, sir. This is 0.194444 This is going to be multiplied by route off 1 20. So this is 2.13 myself. Statistic is coming out to be 2.13 What is my Alfa level? My Alfa level is 0.0 fight. So this is a two tailed test, my al 50.5 which means in a single tail my area should be 0.25 So if I find a critical value for 0.25 my critical values 1.96 So which means this is minus 1.96 and this is plus 1.96 And since my Z value is beyond 1.96 it falls somewhere in the rejection region. I will reject final hypothesis, So I will reject h not Okay, So I will reject. It's not so what can I say? The consumer group claims that the mean annual consumption is 48 pointed. So I will say that I have in a statistical evidence to say that the claim off the consumer group is false and this is going to be my answer

No. Okay, so we know that the number of patients given sustained care is 198. Among that, 82 0.8%. They're no longer smoking after one month. So 198 times 82.8 percent. Well, give us 163.94 Okay, so we can round that 264. Yeah. Andi making, then Right down. Arnel Hypothesis, which is given that P is 1 80 80% since the test claims that 80% of patients stopped smoking after giving state care and our culture bosses will therefore be P is not equal to your right June at a given level of significance. Which is your prince? Your one. Okay. Me? Yeah. So we will get a Z statistic value off 0.99 on the critical value for the normal area. Table movies equals plus or minus +257 eight A p value. 20 above output is just your 200.32 Sure. Yes. On. Since this is greater than our little of significance, we can include that there's not sufficient evidence to support the rejection of the claim that 80% off patients stop smoking when sustained care. What about


Similar Solved Questions

5 answers
Uco thls equation dedye Mici nene @xniussion J0t 4 100rT0)" CIor H of which the Intcrva bihavuDechl case0,05 andriult In naronecder 'ntatintenal manowcntenaupart (4)?Icten netJi doe'chnq-Neco Helpo?MelteeFicn144,
Uco thls equation dedye Mici nene @xniussion J0t 4 100rT 0)" CIor H of which the Intcrva bihav uDechl case 0,05 and riult In narone cder 'ntat intenal manowc ntenau part (4)? Icten netJi doe' chnq- Neco Helpo? MelteeFicn 144,...
4 answers
(CHzc HzhoElimination Reactions: draw the major product for each reactio A General [email protected] CHBOHB. Exceptions: Give one example each for the three exceptions Wulky bas (clzlz(e
(CHzc Hzho Elimination Reactions: draw the major product for each reactio A General reaction Br [email protected] CHBOH B. Exceptions: Give one example each for the three exceptions Wulky bas (clzlz(e...
5 answers
Consider the dimemenkeiequalion B EV MBM 2Ueing ansnledzhmaradton Method
Consider the dimemenkeiequalion B EV MBM 2 Ueing ansnledzhmaradton Method...
5 answers
Imagine that the Moon is locked into its orbit around the Earth by electrical forces and the gravitational force between the Earth and Moon is somehow "turned off."a. A charge of what magnitude would need to be on each body? Approximate the Moon and the Earth as point particles and assume both have the same magnitude of charge.b. How many moles of electrons would that be?
Imagine that the Moon is locked into its orbit around the Earth by electrical forces and the gravitational force between the Earth and Moon is somehow "turned off." a. A charge of what magnitude would need to be on each body? Approximate the Moon and the Earth as point particles and assume...
5 answers
QUESTION 1: Draw tha most statle carbocation that has the fomul GHs': (5 points)QUESTION 2: Classify each of the folbwing reactions as substitution, elimination . addition. (8 points)H,c CH;HcA,c CH,CH;Two types of reaction:
QUESTION 1: Draw tha most statle carbocation that has the fomul GHs': (5 points) QUESTION 2: Classify each of the folbwing reactions as substitution, elimination . addition. (8 points) H,c CH; Hc A,c CH, CH; Two types of reaction:...
5 answers
In the RCL circuit (free oscillations), suppose the capacitancewere doubled by placing a second capacitor in parallel with thefirst one. In this case, the time constant should beunaffected, doubled, halved, reduced by a factor of sqrt 2, noneof the above.
In the RCL circuit (free oscillations), suppose the capacitance were doubled by placing a second capacitor in parallel with the first one. In this case, the time constant should be unaffected, doubled, halved, reduced by a factor of sqrt 2, none of the above....
1 answers
A 25.0 -m long steel cable with a cross-sectional area of $2.03 \times$ $10^{-3} \mathrm{m}^{2}$ is used to suspend a $3.50 \times 10^{3}-\mathrm{kg}$ container. By how much will the cable stretch once bearing the load?
A 25.0 -m long steel cable with a cross-sectional area of $2.03 \times$ $10^{-3} \mathrm{m}^{2}$ is used to suspend a $3.50 \times 10^{3}-\mathrm{kg}$ container. By how much will the cable stretch once bearing the load?...
5 answers
Apiece of magnesium metal is added to dilute sulfuric acid. The products of the reaction areMgS(s), H2(g), and HZO()MgO(s), so3(g), and H2O()MgSO4laq), and H2(g) MgOlaq) SO2(g), and HZO()
Apiece of magnesium metal is added to dilute sulfuric acid. The products of the reaction are MgS(s), H2(g), and HZO() MgO(s), so3(g), and H2O() MgSO4laq), and H2(g) MgOlaq) SO2(g), and HZO()...
5 answers
If the area to the left of xx in a normal distributionis 0.226, what is the area to the right of xx?Answer: If the area to the right of xx in a normaldistribution is 0.226, what is the area to the left of xx?
If the area to the left of xx in a normal distribution is 0.226, what is the area to the right of xx? Answer: If the area to the right of xx in a normal distribution is 0.226, what is the area to the left of xx?...
5 answers
Given x & y are differentiable functions of time and y3 = sin (Tx)Find the rate of change ofy when x = 0 and x is decreasing at 2 units/sec
Given x & y are differentiable functions of time and y3 = sin (Tx) Find the rate of change ofy when x = 0 and x is decreasing at 2 units/sec...
5 answers
Wire carrying 17,3-A current passes between the poles of strong magnet that is perpendicular to its field and experiences force of 142-N Force on the 5,86-cm of wire the field. What is the average field strength?Answer:Choose;.Check
wire carrying 17,3-A current passes between the poles of strong magnet that is perpendicular to its field and experiences force of 142-N Force on the 5,86-cm of wire the field. What is the average field strength? Answer: Choose;. Check...
5 answers
Last semester In a business fraternity; 3190 ' af the members were on the Dean's List and 18% of tne members were on academic probation_ being on the Dean's List and being on academic probation are mutually exclusive events, fInd the percent of members who wero nolther on tho Dean"s LIst nor on academic probatlon patcont Do NOT us0 the percent sign in the answer box;
Last semester In a business fraternity; 3190 ' af the members were on the Dean's List and 18% of tne members were on academic probation_ being on the Dean's List and being on academic probation are mutually exclusive events, fInd the percent of members who wero nolther on tho Dean&quo...
5 answers
SHOW EACH STEP CLEARLY! WRITE several complete simple sentences about how each series is convergent or divergent including which test is appliedl nth-Term Test for Divergence, Geometric Series Test,p-Series Test, Integral Test, Ratio Test, & Direct Comparison Test (Hypothesis (Criteria), Conclusion (ConvergeDDiverge), & EXACT Test Namel) n+3 1_ Xn-10o Vn+12. En-1oo e 0.2n
SHOW EACH STEP CLEARLY! WRITE several complete simple sentences about how each series is convergent or divergent including which test is appliedl nth-Term Test for Divergence, Geometric Series Test,p-Series Test, Integral Test, Ratio Test, & Direct Comparison Test (Hypothesis (Criteria), Conclus...
5 answers
1Let f(t) = and define F(8) := L{f(t)} Find 1+t L-1 {_4e-4s F(s) + e-4s_ F' (s)}| 6=4
1 Let f(t) = and define F(8) := L{f(t)} Find 1+t L-1 {_4e-4s F(s) + e-4s_ F' (s)}| 6=4...
4 answers
Aree theltullqteinet8joor (Dv marchuanotical Inuucclon}Ua LeeHArJaHott [iaer Pl0} . Bvti Bafore Lmolty0 @re bh-tuns e 0 [Y0} trom tnat ft tT p82doz Qatk (25 Esch {Mrodrt k 2 Ietk) tnut. (ten PIt < H)ntre"ceuctig Fneetlt|Jun_Mltuutt ielll2+1< (+3)1rtoriton #oun llanttdrrd IrortJoon J Neht derumteranon [CreacheQuersinceU+Jte Meale%8Min (otdekakclt%Gace [Tus Duth (he Dtets unt (ho Innxtit #fps AnE LYC7 Fnd; Ing f0 [hc ftiDy MjUfAtuDcMl Eath
Aree theltullqteinet 8joor (Dv marchuanotical Inuucclon} Ua LeeHArJa Hott [iaer Pl0} . Bvti Bafore Lmolty0 @re bh-tuns e 0 [Y0} trom tnat ft tT p 82doz Qatk (25 Esch {Mrodrt k 2 Ietk) tnut. (ten PIt < H)ntre "ceuctig Fneetlt| Jun_Mltuutt ielll 2+1< (+3)1 rtoriton #oun llanttdrrd Irort Joo...

-- 0.020952--