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Equations: Kp = Kc(RT)An Write equilibrium constant expressions for each of the following reactions (2.5 pts each)2 HzS(g) = 2 Hzg) Szlg) CHalg) + 2 HzS(g) = CSxg) ...

Question

Equations: Kp = Kc(RT)An Write equilibrium constant expressions for each of the following reactions (2.5 pts each)2 HzS(g) = 2 Hzg) Szlg) CHalg) + 2 HzS(g) = CSxg) - Hilg)

Equations: Kp = Kc(RT)An Write equilibrium constant expressions for each of the following reactions (2.5 pts each) 2 HzS(g) = 2 Hzg) Szlg) CHalg) + 2 HzS(g) = CSxg) - Hilg)



Answers

Calculate the equilibrium constant at $25^{\circ} \mathrm{C}$ for each reaction in Problem 17.39 .

To determine okay for the following two reactions in which number a carried me, um, react with s n two plus forming silly to bliss and Essen is reduced. So in this reaction, Caribbean oxidizes And to see the two pless releasing two electrons e oxidation off the Caribbean is 0.40 world, while the, on the other hand, isn't too plus again, the electron reduces in tow. Sn So the e reduction off the essence is equal toe 0.15 fold, adding the two have cell potential. So we will get in art off the cell which is equal to zero point 55 world for a reaction be in which hello mini ums react with three Caribbean islands forming toe three plus and three Serie And this reaction the L A mini among oxidizes in tow. A three plus releasing a total of six electrons e oxidation off the aluminum is 1.66 world, while the cadmium mines reduces take six electrons from karimi. Um so e reduction for the premium is zero point 40 worked with negative. Your sign adding the two have cell potential so we'll get in art off the cell, which is equal toe, 1.66 minus 0.40 So this is equal to 1.26 words as we know that he, not off the silly, is equal to 0.592 Divide by n and toe Log up. Okay, we can also write that K is equal Tow, anti log up and rearranging the equation. Anti log up in art end to end the world by 0.592 Here also K is equal toe anti log he not and to end divide by 0.592 Putting the value empty log up in art is equal to zero point double five fold we're not in is the number of electrons last and again, which is to divide by 0.592 calculating the value and then taking the anti log. So we will get the value of K, which is equal toe 3.8 and tow 10 rest power 18. We're here putting the values so anti log up in art is 1.26 old multiplied by and is the number of electrons which is six divided by 0.592 So calculating the values and then taking anti log, we get the value that is equal toe one and 10 rest power 1 27.7. This is the required value. Up came for both part off the questions.

So for this problem, we've been actually write down the expression for KP for all these cases. In the first case, we have, um all three terms are gases, so all of them will be included in the KP occasion field and no, to the bar to, um he parks was not been to on prosecution of oxygen. In the second case, you have any two or four, um, disassociating to two motives and not two. And both of them are gases. So the most appear in the KP equation and Cape Easy goes to the part of Russia and to square divided by the pressure pressure of mental four. Uh, in the third case, all of these are gases. So all of these will make an appearance in the final equation. The pasha pressure roaming que posh Russia PCL three square Bartra pressure, PVR tree square and partial pressure seal too cute. And I think I skipped one. So in the third part again, all of these are gases. All of these will feature and KP. We have partial pressure of silicon chloride hydrogen. The part too, um, to the can hide right and turning to the part, too. Um, as according to the band, it's kind of deliberation

Reaction of sulfur dioxide and oxygen gas reacting to forms sulfur try oxide. So in order to find the equilibrium constant, which is our KP, we need to use the equation that are standard free energy of reaction is equal to the negative of the universal gas. Constant times the temperature that this reaction has run out times the natural log of our equilibrium constant. So let's go ahead and do some algebra here because we're solving for art. Okay, so the first thing that we can do is we can divide both sides by the negative are times t and that will give us that Delta G standard negative doctor to standard over our times T is equal to the natural log of Okay, so we can raise both sides to the E to allow this natural log to cancel and we're left with okay is equal to e to the negative Delta G standard divided by our times t. So let's go ahead and plug in some numbers. We know that mm to the negative and then from the previous problem, we know that our delta G standard of reaction is negative. 141 0.8 killer jewels divided by are but his 0.0 8314 Jules Permal Calvin Times 298. Calvin, there we go. Okay, then we can go ahead and put that in our calculators, and we find that our K of this reaction is equal to 7.1 times 10 to the 24th power. All right, so okay does not have any units because it is a constant and a couple of tips and tricks for solving these types of problems. It's always good to make sure you keep track of your negative signs here. So you see that our delta G standard of reaction here is negative, but this entire term is also negative. So make sure not to lose your negative signs here. And then you could easily plug this into your calculator and get an answer for your KP

And for the synthesis of Yuria from ammonia and carbon dioxide. So in order to find our K value here, R k value we need to recall our Gibbs free Energy equation. Here we have our delta Gee, standard is equal to the negative. Universal gas, constant times, temperature times the natural log of our equilibrium constant. This is gonna be a K p. Here. So what we're going to do first is we want to solve this equation for our okay, because that's what we're trying to find. So what we're going to do first is divide this side by the negative Universal gas, constant and temperature divide both sides by that. So after some algebra here we have that are standard energy of reaction over universal gas. Constant temperature is equal to the natural log of okay. And then we can go ahead and raise both sides thio e to cancel out that natural log. So we get that e to the negative delta G standard over universal gas. Constant temperature is equal to K. So in the problem, we were given that our delta G standard value is equal to negative 13.6 killed goals. Permal our our value. We know since we're using killed jewels going to be 0.8314 killed joules per mole. Kelvin R T value is going to be equal to 298 Calvin, because we're at standard temperature. And so we have our G. We have our and we have our tea. Let's go ahead and sell four k. So here we're going to dio e to the negative negative. 13.6 kg per mole. Divided by 0.8314 times 298 Calvin. A better zero there and not from equals. Okay, so when you put this into our calculators, we get a K value of 242.1. There's no unit on K because it is a equilibrium constant, but we get 242.1


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