Hi. In the given problem, first of all, there are coordinate taxes which are given us here. This is why this is that. And this is X axis. There is a cube whose ages are along these according it access in that cube. This is the bottom most. This is the back walls. Place the backward face off this cube. Then the front most face is this. This one is the front most face, then the top most and the bottom most face. So these are the six faces which are named As for the left site. This is S one for the right side. This is s three for the top most face. This is as to for the bottom most face This is S four for this front face. This is s five. And for the back face. This is s six. The electric fields in better form has been given S E is equal to minus 5100 Newton Park Coolum into Meter X into icap Yes, 3.0 Newton Park Coolum meter into the set cake. So it is clear that these components off the electric field are along X axis and alone. Negative X axis. So this is represented like this. This is the component off electric field along negative X axis and another component off electric field is along positive that axis like this. So these are the two components off electric fields and their values are given us for e X. This is minus 5.0 X newton for column into meter. So it is variable with the distance along X axis and for is that this has given us 3.0 Newton into Zet, Newton for Coolum into meter again. This is also variable Peter distance alongside access. Now we will find the electric flux dream through all these surfaces in the first part of the problem. So for as one first will follow as both the components off electric field are parallel to the surface is s one and s three. So no flux will be linked through it. So as e x and E vai is at both are parallel toe s one, so we can say flux linked through this F five flux linked through this s one means five as one is zero. Now it will look for as to here. This is as to the top most part, and the component E Zet is going out off it, so there will be flux. Lean through it five. As to which is given by the product off electric field means 3.0 Zet Newton per column into meter, multiplied by the distance in place of desert. This little distance off this surface from the origin or and that distance will be equal to the length of this cube, which is 0.3 m. So here, in place off this that we will put the value off this distance and which is zero point three meter so Newton or column into meter. This meter will be canceled. So this is the net value of electric field at this surface as to multiplied by the area, an area off each face off. This cube is the square off 0.3 means 0.9 m square, so the multiplied by 0.9 m square, so this electric flux linked through the surface as to comes out Toby 0.81 Newton need to re square for Fulham now for a street again. The flux linked through this will come out to be zero, as we have discussed earlier. Uh, electric field components. Both the components are parallel toe this surface, also as three. Also, So no flux will be linked through it now, for as for this surface is the bottom. Most surface and electric field line means this Zet component off electric field is entering into it, so it will be taken as a negative. But then we look for that distance. Zed, off this surface from the origin, this is zero. So as zero is zero, so the electric field here will be zero. So the flux five s four will come out to be zero, then for as five, this surface s five is the front most surface. This one whose distance from the origin again becomes equals to 0.3, and the electric field is entering into it, so it will be taken as negative. So here it it will become five as five is equal toe minus fight 0.0 into the distance. 0.3 into the area, 0.9 So finally, this electric flux passing through the surface s five comes out Toby minus five point minus 0.135 Newton Meters square for column at last For surface as six. Here, this is the S six office, the bar, the backward surface And as the distance off, this s six is also zero along the X axis, so x zero for this surface so e x will come out to be zero. Hence, we can say five s six will be zero. So finally, the total flux linked through the skill will become five as one plus five as to plus five as three plus five as four plus five as five and five as six. So when we put all these values, we get a net value as minus 5.4 in tow. 10 dish part minus two Newton meters square per column. And this becomes the answer for the first part off the problem. No. For the second part of the problem, we have to find the total charge and closed within this cube, for which we use the concept that the total flux linked through our close surfaces, given by one upon excellent, no times that charge and closed. So from here, discharge comes out to be absolute. No times that total flux. So it is given by 8.854 in tow. 10 Dish par minus 12 Colon square for Newton into meters were multiplied by the flux, which waas minus 5.4 into 10. Dish bar, minus two Newton meters square per Poland. So finally, discharge comes out. Toby minus 4.78 into 10. Dish par minus 13 Gulen. And this becomes the answer for the second part off the problem. Thank you.