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A wire 6.00 m long with diameter of 2.15 mm has resistance of 0.0320 nYou may want to review (Pages 597 602)Part AFor related problem-solving tips and strategies, y...

Question

A wire 6.00 m long with diameter of 2.15 mm has resistance of 0.0320 nYou may want to review (Pages 597 602)Part AFor related problem-solving tips and strategies, you may want t0 view a Video Tutor Solution of Resistance in your stereo system_Find the resistivity of the material of the wire.Azd0 - mSubmitRequest Answer

A wire 6.00 m long with diameter of 2.15 mm has resistance of 0.0320 n You may want to review (Pages 597 602) Part A For related problem-solving tips and strategies, you may want t0 view a Video Tutor Solution of Resistance in your stereo system_ Find the resistivity of the material of the wire. Azd 0 - m Submit Request Answer



Answers

Find the cross-sectional area of copper wire at $20^{\circ} \mathrm{C}$ that is $60.0 \mathrm{~m}$ long and has resistivity $\rho=1.72 \times 10^{-6} \Omega \mathrm{cm}$ and resistance $0.788 \Omega$.

All right, so in this problem Ah, So for the copper wire, we already know that the lengths of the copper wire is, uh ah equal 20 meters into the diameter de equal 2.5 free may bitters And you can look up the value of the resistive ity for copper on the internet All in the sing the textbook and the very iPhone Ihsaa row equal. Ah, 1.75 times 10 to the negative Eighth er, holmes Time meter. Okay. And the you can utilize the relation between the resistance and the resist of resistive ity. So are equal road times a ll over s. So how is the lens of off the copper wire and essays the cross section so you can re express the s s role? Um, hi times, half d swit. Okay. And you need to plug in the values t this expression. And he would say the value is 1.16 homes right?

Our question says that we have a wire that his four meters long. So I write that era's L and six millimeters in diameter. So I convert millimeters two meters. So that is the diameter D is six times 10 to the minus three meters and it says this wire has a resistance are of 15 millones, which is 15 tempting the minus three homes and a potential difference of 23 volts or voltage V. Here is 23 volts, which is applied across the across the wire and each end, and it wants us to figure out for part A with the current in the wire is for part B what the magnitude of the current density is for Part C wants us to calculate the resisted ity of the wire material and then using the information of the resistance of the resistance of the wire material, we can use Table 26-1 to that identify the material part D. Okay, so we have all our information written down here, so let's go ahead. Start with part A. Calculating the current well, to get the current, we can just simply use almost law. So I current is equal to voltage over resistance. So you simply plug into values love for voltage resistance. This comes out to be blamed. 0.53 times tended 1/3 amperes. Come, come box. That inter solution to a for party way can calculate the current density, which is Jenny. That's equal to the current over the area. Well, we need to find the area. The area is simply pi r squared. Where are is half the diameter. So this is equal to 1/4 because 1/2 squared is 1/4 pi times the diameter squared. Okay, so now we complete this back into our expression for J. Jay is equal to four cause the 1/4 dividing by 1/4 his Samos multiplying by four. So it's four I divided by Piety square. Okay, so we can plug in all of our values above and value that we calculated for I impart a miss comes out the 5.41 times 10 to the Senate and piers per meter square. Okay, we can box it in as our solution for B now, Part C wants us to find resisted ity of the wires. Let's go ahead and get a new page going here. Okay, so this is part. See, the resisted Vitti, which we're gonna do note his robe is equal to the resistance in the area divided by the length. Well, we just had previously found the, uh, the relationship for the area. So this is 1/4 piety squared. He squared, the four goes on the bottom. Multiply that by the length l So we played in the values for our indeed and l into this expression. It comes out to be 10.6 times 10 to the minus eight in the unit ear are owns Tang's meters, the game box. And it is your solution for part C and using the solution, we can look at the table 26-1 to figure out what material we're dealing with. And according to that table, this material is platinum. Right here. Plug when you can simply box set in their solution for a party

The length of a silly world. Where is political too? 65 nine millimeter under di Meeting outside the wire physical toe zero point seven mine Millimeter riches you called to remind 79 millimeter multiply one meter and in one meter Dirar chosen millimeters So we can sell millimeter than a millimeter and we get diameter is you can do zero point 79 Multiply into the power minus tree Mita and the hell you are. Role is it called tau one point 59 Multiply 10 to the power minus and oh hyung meter. This is a value our Just do it to you for silver Now we want to complete But it is since off What? Ask me how the relation, for instance that are physical toe resist. Ooh tee times lend upon a ah cross station off conductor which is a call to restore t land upon Yeah, a position that is by this good a bomb, for from here we get re since is in control four times resists 30 times lend upon why knee took her noble defend well, lose the gat for multiply row, which is one find 59 I want to fly tend to the bar minus end. Ho ho meter Much play lent off the wire that is 6.9 meter dried by bye. Multiply diameter off the way That is your point 79 months July into the bar, My last three meter. So by computing all these ways we get there is a sense of where musical, too. They want Gugu three. Well, their sponsor.

In this problem, we have a wire. The hands the length of 5.9 m and a diameter of 0.49 millimeters and millimeters is simply times 10 to the minus three. So we have 30.49 times 10 to the minus three meters, the damage of this wire, and we want to find its resistance. To do this problem, we need to know the equation for resistance, which is the resistive itty of the wire. That's a constant value. Yeah, times its length divided by this area here. The area is pie R squared but were given diameter and so diameter is two times the radius. So solving for the radius, we get diameter over two. But we're dealing with our square. So we really have is r squared equals D squared over floor some plugging this in for the resistance we get resistance equals the sensitivity of the wire and its length divided by pi. We have won over our square, so we take the reciprocal of what we found. So we get four over d squared and this is the equation for the resistance in the wire. And so all we need to do it's just plug in our values. So plug in our values, we get our equals. The resistive itty of this wire is 1.59 times 10 to the minus eight at times length, which is 5.9. What's the matter by pi Times four divided by the diameter and diameters 0.49 times, 10 to the minus three and the damn very squared. So plugging this into the calculator we get the resistance of this wire is 0.49 Holmes.


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