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Order these chemical species by increasing pH Of an 0.1 aqueous solution of each- That is_ imagine making an 0.1M solution of each species Select next to the specie...

Question

Order these chemical species by increasing pH Of an 0.1 aqueous solution of each- That is_ imagine making an 0.1M solution of each species Select next to the species that makes the solution with the lowest pl: Select next to the species that makes the solution with the next higher pll; and so on_ Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH Of pure water to the pll of the other solutions

Order these chemical species by increasing pH Of an 0.1 aqueous solution of each- That is_ imagine making an 0.1M solution of each species Select next to the species that makes the solution with the lowest pl: Select next to the species that makes the solution with the next higher pll; and so on_ Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular case, just compare the pH Of pure water to the pll of the other solutions Note for advanced students: for all charged species _ you may assume the necessary counterions act as neither acids nor bases_ relative pH ot queo solution Tprcice HNO , H,FO . HIO, (Choozc onai 0,o [lowest H,o (Choate onlt) H,Fo (Chcoce OnL) (Chooce One)



Answers

Predict which solution in each pair below will have the lower pH. a. $2.56 \times 10^{-2} \mathrm{M} \mathrm{HCl}$ or $4.09 \times 10^{-2} \mathrm{MHBr}$ b. $1.00 \times 10^{-5} M$ acctic acid $\left(K_{\mathrm{a}}=1.76 \times 10^{-5}\right)$ or $1.00 \times 10^{-5} M$ formic acid $\left(K_{a}=1.77 \times 10^{-4}\right)$ c. $22 \mathrm{mM} \mathrm{CH}_{3} \mathrm{NH}_{2}\left(\mathrm{p} K_{\mathrm{b}}=3.36\right)$ or $22 \mathrm{mM}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\left(K_{\mathrm{b}}=5.9 \times 10^{-4}\right)$ d. $158 \mathrm{mM} \mathrm{NH}_{3}\left(\mathrm{p} K_{\mathrm{b}}=4.75\right)$ or $158 \mathrm{m} M$ acetic acid $\left(p K_{a}=4.75\right)$ e. $0.00395 M \mathrm{HNO}_{3}$ or $0.00145 M \mathrm{HClO}_{4}$ f. $2.05 \times 10^{-1} M$ propionic acid $\left(K_{2}=1.4 \times 10^{-5}\right)$ or $2.05 \times 10^{-1} M$ fluoroacetic acid $\left(K_{2}=2.6 \times 10^{-3}\right)$ g. 375 m $M$ pyridine $\left(p K_{b}=8.77\right)$ or $375 \mathrm{mM}$ aniline $\left(\mathrm{p} K_{\mathrm{b}}=9.40\right)$ h. $0.555 M \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\left(K_{2}=3 \times 10^{-3}\right)$ or $0.355 M \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}\left(K_{2}=1 \times 10^{-4}\right)$

For a let's right the chemical equation to the self dissociation reaction Uh, d m s o, which is a dime Ethel. So, Fox side, um, which will be our each So has a structure that is this year. And so the self association of, um But the, um, each soul or the d m s o would be this equation here, Uh, you have? Yes. Double o teach three ch three plus s a bond. Oh, ch three three. And this being equilibrium with C H three to S o h positive I in plus C h three step upon. Oh, ch two minus. Therefore, the K w, which is equal to, um one times 10 to the negative 35 is given the expression C H three to s. Okay, plus C h three s bond O C. H two minus. And there's our equilibrium Expression No, for b uh, were asked to find the equilibrium concentration of beach to Seoul. Plus So the chemical equation here is each c n plus each. So in equilibrium with C and minus Equus and gage to Seoul, plus equi ast's. So, uh, CN minus, um, is assault so we can get rid of the, um the, um any soc and minus a quickest plus each so liquid in equilibrium with each CNN and saw minus. And this would work actors a base. So we're told that this is 0.1 um, more where? Windsor 10 molars. Any CNOOC and minus, uh, this would be 00 It's completely iced. Tea will here for this week based minus X plus X plus Dex points your 10 minus x X and X. This is represented by a K B. Which will be H c N s o minus CN minus. We need to solve for the K B, which is equally K w over K s. Let's go ahead and solve for that K w 1.0 times 10 to the negative. 35 UK is 1.3 times 10 to the negative 13 for the congregate there. For the KGB, value works up to 7.69 times 10 to the negative. 23. Let's plug that in over here variable x and X and the numerator 0.10 my ex and his nominator solving for X. Now we're going to assume that this is 0.10 X is gonna be very small. So solving this for X Putin will yield i e 0.77 times 10 to the negative 13 of that sequel, Teoh the polarity of the each CN which is also equal to be saw minus. So we also know K W is equal to Gage to so plus and so minus We know that from, uh, part a so k w 1.0 times 10 to the negative 35 is equal to each to so plus and this is 8.77 times 10 to the negative 13 Solving this for the minority of each to so Plus, we find that this is equal to 1.14 times 10 to the negative 23 Moeller.

Let's calculate the concentration of all saw it species in each of the following acids air bases and we'll have to apply the 5% rule to see if the assumptions we make are valid for a we have a weak acid. A 0.92 Moeller hcl Oh, we're told that is a weak acid. We can look up. It's K a value which is 35 times 10 to the negative eight at the the concentration of all species. First by starting to rate, Brown said. Lower equilibrium for a weak acid initial polarity pleader race table. No assumption here We're gonna assume that 0.9 to minus X is approximately equal. The 0.92 and a K expression Que is 3.5. It was 10 of the negative. Eat Yeah, solving for X. I get 1.8 times 10 to the negative five. Let's verify your assumption. Okay, so assumption here 5% of 0092 is equal to 4.6 times 10 to the negative four. So X, which is 1.8 times 10 to the negative five, is less than 46 times 10 to the negative four. Therefore, since it is less according to the 5% wrote, the assumption is valid. And now we can report the concentration of all species the concentration of H 30 plus sequel of the concentration of ceelo minus one. Whereas table this was X which is equal to 1.8 times 10 to the negative five Mueller on the concentration of HCL Oh is equal the 0.92 molars. Our assumption is valid for be We have zero 78 four Moeller C six h five and h two and we're told that it is a weak base for the week base. Well, look up the K B value, which is equal to 4.6 times 10 to the minus 10. Let's calculate the concentration of all species. That's right. The equation for the week base initial polarity is 0.784 Peter a stable here K b expression way. No, the baby values We're gonna assume here E didn't write the assumption here, but we will squeeze it in here. We're gonna assume that 0.784 minus X is approximately equal 2.784 will include that in our expression here, the K B, we found out, was 4.6 times 10 to the negative 10 from the appendix people that x x and our assumption here is 0.784 solving for X. Here we find that X is equal the 6.0 times 10 to the negative six. Let's were this above here. Uh, let's look at our assumption here. 5% of 0.784 is equal to 39 times 10 to the negative three. Therefore, X, which is 6.0 times 10 to the negative six, is less than 39 times 10 to the negative three. Therefore, the assumption is valid concentration of C six, h five and H three plus Z equal to the concentration of O H minus and their ice table. That's they're both equal. The X of these were both equal to 6.0 times 10 to the negative six Mohler and the majority of the C six h five and H two is equal to 2.0 784 Moeller. There would be the concentration of all species proceed, we have weak acid. 0.0 810 Moeller h c n We can look up the value for H C N, which is equal to 40 times 10 to the negative 10. It's Richard Brown said Lowry. Equation for h c n initial polarity. That's your 810 minus x x and x. We're going to assume here the 0.810 minus X is approximately 0810 que c h 30 plus C and minus over eight c N Katie value 4.0 times 10 to the minus 10. Take the x x Clinton 0810 X is equal to 5.7 times 10 to the negative. Six. Let's look at our assumption for the assumption to be valid will apply the 5% rule of 5% of 50.810 and that would be equal to 4.1 times 10 to the negative three. Therefore, X, which is 5.7 times 10 to the negative six, is less than 4.1 times 10 to the negative three, and therefore the assumption is valid, and the mill arat e of the H 30 plus sequel of the military of the CN minus, which is equal to X. These air equal to you 5.7 times 10 to the negative. Six. Smaller The morality of the H. C N equal the 0.810 Moeller for D. We have a weak base. 0.11 Moeller C. H. 33 and we can look up the K B value for this week base and find that the baby value is equal to 7.4 times 10 to the negative. Five. Start by writing a bronze that Lowery equilibrium here over Get ch 33 and each plus and which minus I C e 0.11 Peter writes table one minus x x and X, and we could make our assumption here. Assume that 10.11 minus X is approximately 0.11 K B is equal to C H 33 n h plus Oh H minus over C h that again ch 33 and and our Kate value was 74 times 10 to the negative five Sequel to you x x 0.11 solving for X here with the assumption. We find that it's equal to 2.9 times 10 to the negative three. And let's verify your assumption. With the 5% rule, 5% of 0.11 would be equal to 5.5 times 10 to the negative three. So X, which is 2.9 times 10 to the negative three, is less than 5.5 comes 10 to the negative three. Therefore, the assumption is valid, and the concentration of CH 33 n H plus is equal to the concentration of O H minus, which is equal to X. According to Reis Table. These are both equal to 2.9 times 10 to the negative three Mueller on the concentration of ch 33 and is equal 2.11 Moeller for eat. We have a weak acid 0.1 to 0 Mueller F E. H. 206 to plus and were given its K in the question. It's equal to 1.6 times 10 to the negative seven. It's greater once, said Lowry. Equation here for a weak acid h 30 plus at f E. H. 20 five o. H. And this would be a, um plus one a que? Yes, that would be correct. Initial change Equilibrium. This is 0.1 to 0 00 minus x plus X plus x went 1 to 0 minus x x and x que expression here would be h 30 plus over f e h 205 oh h plus over f e h 20 six two plus on the K A. Here is 16 times 10 to the negative seven sequel. The X x on, um, make our assumption here. We're gonna assume that 0.1 to 0 minus X is approximately 00.1 to 0. So 0.1 to 0 in the denominator. Here, solving for X here will get X equal toe 1.4 times 10 to the negative four, and we'll verify your assumption. Here. 5% of 0.1 to 0 is equal to 6.0 times 10 to the negative three. So X, which is 1.4 times 10 to the negative four, is less than the 5% 6.0 times 10 to the negative three. Therefore, the assumption is valid and the malaria t of the H 30 plus is equal to the majority of the F D H 205 oh h plus just these air body called X 14 times 10 to the negative four Moeller and the morality of the F E H 206 to plus through the this would be equal to 0.1 to 0 Mueller.

Inclusion. Corned and, uh, bi ATCH for Miller were ankle June minus love off the concentration on the hair a gene and in the question were given concentration here in court. June, uh, 10. Berman is far. Therefore, we should get when we go to the minus long based 10. Here off the 10th round. One is far anyway. Exactly. Ico Judah for here.

Answer for the question. I'll do it all. And causing and cruising pH Oh, the given solution, right? The order is here. Did you look for anyone? Well, h I had hydrogen. You died Less than 0.5 months is to Is to is a four and then this is less than 0.5 More clarity. C two. It's C two h two cl or two less, then 0.5 months. Inch C two is three or to less than 0.5. Similarity. NH four cl lesson One more validity and they we are and NPR listing 0.5 more clarity. K C two is three or two, less than 0.5 majority in his tree, less than 0.6 More clarity in the village. Less than 0.5 modernity variant hydro site. So this is the audit of increasing page after given solution


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