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Question

Te nteanWeuLetl LetercnAenttnn FnrC ehEtcteMaeededeeeneteeelneentn nutcumtan (nstn"drmMceatuioKoluntmntIncnuntematralG#uttin @emrn ilTTeAnenDortu 4utnreunu)tthalnGat

Te nteanWeu Letl Letercn Aenttnn Fnr C ehEtcteMaeededeeeneteeelne entn nutcumtan (nstn "drm Mceatuio KoluntmntIncnuntematralG #uttin @emrn il TTeAnen Dortu 4ut nreunu) tthaln Gat



Answers

Decrypt these messages that were encrypted using the Caesar cipher.
a) EOXH MHDQV
b) WHVW WRGDB
c) HDW GLP VXP

Okay, So for this one, we're told the s some encrypted messages that were encrypted using these cipher P plus 10 mod 26. Now, this was the encryption cipher. So to decrypt it, we need to undo that. Right? So we're going to use the decryption cipher P minus 10 mod 26. All right, so for a are given message is see e be be Oh, eggs an OBE, x y and G. OK, so first we need to convert that into numeric ce, where a call zero equals one Sequels to case of sea is going to ese for 11 14 23 13 14 and one, 23 24 and six. So now we could run it through our algorithm where we take the number. It's a track 10. And then take my 26. Right, So two months, 10 being negative. Eight mon 26 which is really 18. All right, so now well, cover into those numbers. So we get 18. Same thing here in native six month 26. That would be 20. Okay, then we get 17 17 four, 13 3 4 17 13 14 and 22. And then We just need to translate that back into the alphabet. So it's gonna be an S u R r e and D he r n o w spooky. It says surrender now it's probably how some of this homework makes you feel. Okay, So, onto part B here were given the phrase 00 W i p be s oh X. And so first, we want to translate this into the numbers numerals using the equal zero equals one Sequels too. Okay, so we get that Ella's 11. Oh, is 14 w is 22 eyes, eight p is 15 be is one s is 18 0 is 14 x is 23 it is 13 and I we're gonna use our cipher, right. Which recall is I'm going to be p minus 10 March 26. Yes. So when we take 11 minus 10 while 26 is could be the one 14 minus 10 is four 12 b negative. Tuesdays will be 24 five. That's negative. Nines. Women with 17 eighties gonna be 8 14 4 23 is 13 and 13 is three then Now we have to translate it back, and we do that we get Be? Yeah. And why f o r i e and d be my friend a little bit nicer than the last one. All right, so now we have the last one. Here we are, given the phrase d s. I should probably leave more space than this. A d s w Ow p Why be p e x? So again we translate it into the numbers using a zero beak Was one Sequels too? S o D is gonna be three s is 18 w is 22 0 is 14 a. P is 15. Why is 24 b is one? Why is 15 eat is four and X is 23. And then we put a cipher on it, which was P minus 10 mile 26 to get to the next stage. And when we do that. So this would be negative sevens that ends up giving us a 19. This will be an eight 12 four five, 14 1 becomes negative. Nine. That is a 17 five negative six is gonna be 20 and a 13. And then we translated back into letters, so ah, this time we get tea. I e f o r s u n time for fun

Okay, This problem is asking us which of these molecules between all four of these is my m ing going to naturally to tomorrow's into. So let's go ahead and define a couple terms here. First off to Tom Rice or to Tamar Ization is essentially I saw memorization, right? Because whatever we have right here in this case, we have an I mean, the Tomur, the Tanamor is going to be in equilibrium. It exists in equilibrium with my I mean so in order to exist in equilibrium, that means that we're going to have basically the same atoms as we do in this. I mean, but just in a different order, right, we're gonna have different connections. Basically another item, er which is going to be called the totem. Or in this case, so we're looking among all these molecules, Which one has the same atoms just in different connections. So over here we have an oxide. Does this have the same number of atoms in the same type of atoms? The answer is no, because we have an oxygen here that is simply not a cook cook component of Miami. So this is not going to be an option. Next step. We have a hydro zone. Is this considered to be the same atoms as we do in my me? The answer is no. Because we have another nitrogen, right? We have the extra nitrogen. That is not a option. Next up we have this semi carpet zone. This is obviously not the right answer because this one has way too many nitrogen, right? We have one too many. This is not gonna be an option. The last option is my enemy. So does this have the same number of atoms? Same type of atoms and just in different connections? The answer is yes. So it's going to be my enemy. And what is that? Because if we're to simply use a base, for example let's go. You had a user base. My bass is able to Deep protein ate the aesthetic proton associative right here. So this is analogous to my alfa hydrogen usually associated with carbon nails. So I'm gonna take off the hydrogen. Moving the electrons onto this carbon or another way I can show is to move these electrons onto the single bond to create a double bond. As I do that, I'll have to move these electrons up to this nitrogen to produce this intermediate in which I have a nitrogen with a single bond because it has a negative charge. My method group right there and then my double bond right there. Right. So this is very, very similar to my enemy, which I have drawn right here. The only other thing missing is the presence of the hydrogen, which can simply be used over here. We have HB used from the protein nation of be in the previous step that can simply get pregnant by HB to eventually form my enemy shown right here. So this is a Tanamor because this exists in equilibrium, right? It just depends on the reaction conditions. But normally we're going to have my maybe the most stable form that is going to be the one that is present in the greatest excess, right? So enemy and I mean those are taught Immers, and they're going to exist naturally.

Hello and welcome to this video solution of numerous. Here we are given the rules of silver and copper are constantly reducing their scalability in So we have got option A. S case in which is the correct option. Now using the in the Synod process, what we do is okay let's let's try to find out what in what is happening in case of signing process. So let us take the Argentina, which is a G two S. Plus. We have Casey in now for this occasion this gives us a complex of silver. This is okay, ain't you? Him two plus it works now. This compound that is formed is soluble in the solution. He's so little now this is thing for copper also. Thus we can have a quick and select option skc I hope this is clear to you and have a very good thank you.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.


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