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Solve for Z: 1+={[(z 2) ^2] ^2}Your answerFind the fourth term in the expansion of (2x 3 3y2)*5Your answerIf 888" p=1, what is the value of p/999?Your answer...

Question

Solve for Z: 1+={[(z 2) ^2] ^2}Your answerFind the fourth term in the expansion of (2x 3 3y2)*5Your answerIf 888" p=1, what is the value of p/999?Your answer

Solve for Z: 1+={[(z 2) ^2] ^2} Your answer Find the fourth term in the expansion of (2x 3 3y2)*5 Your answer If 888" p=1, what is the value of p/999? Your answer



Answers

Solve equation. $\frac{z+4}{z^{2}+z}-\frac{z+1}{z^{2}+2 z}=\frac{8}{z^{2}+3 z+2}$

Okay. So little to solve the fallen frizzy. So our first job here is to isolate this power to here. So I'm gonna ask you to both sides. I get four times to Z plus three to regard. Teoh is equal to one. Now I'll divide by four on both sides to solve fourth me to isolate this power to so I can take the square root now to get rid of this power. So I get to Z Plus today is equal to a close to minus 1/2. Also track three on both sides and then you get to Z is equal to a degree plus one is what happened. And then we'll divide by two. Because all for the to be how that's Z is equal to negative three plus 1/2 over to So what's negative? Three plus 1/2. I get a negative five over to you and says all too. So I get together 5/4 and I also have the is equal to, um negative three minus the 1/2 over to. So I get a negative 7/2 all over too. Which is equal to negative 7/4

This is problem number 56 we are given the following equation and are tasked with finding all real solutions. So to begin, we can notice that we have the quadratic form A. Z. The two N plus B. Z. To the end plus C equals zero. So we can make our substitution, namely we will have you equal to Z to the minus one half. Making the substitution. We have the following two U squared minus three. You plus two equals zero. This quadratic equation has no real roots, so we conclude that the entire equation as a whole has no real solutions.

We have to solve the linear equation, said Multiplied with said Squared Plus, one is equal to three plus, said Q. So we'll use the distributive property on the left hand side, so we'll get Zack. You plus set is equal to three plus sec. You in the next step will rearrange the terms and bring them together on one side. So Zack U minus that you Plus said, is equal to three, which means said is equal to three. So therefore, the solution is that equals three.

We're with the soul of this equation here. So to do that, we need to distribute on the left hand side. Well, let's do that first. That is going to me, too. That's square plus, and that is going to be equal to the right side, which we're just going to copy down. So now we can subtract to that squared on both sides That's canceled, canceled, and then we can also subtract all sudden from both sides and Flo canceled. So now there's nothing left on the left side. So that is just a zero and the right side. We still have negative. So we end up with zero is equal to negative eight, which we know is false, so this means there are no solutions to this equation.


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