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Question 4What is the best description of the relation between the two monosaccharides below? Aldosel ketose, anomers, epimers, or Dl L sugars? Give one-sentence ex...

Question

Question 4What is the best description of the relation between the two monosaccharides below? Aldosel ketose, anomers, epimers, or Dl L sugars? Give one-sentence explanation for each pair: marks)CHO HO-+HCH,OHC=0 HOHHO-HHO- H CHOHHO-~H CH,OHCHO Hl- OHCHO OHHO ~andOHH= OH CHJOHOH CIOHCHO M- OHCHO HO L~HHO- FandOHH OHHO FHO F" CH,OlIOHI CHOH

Question 4 What is the best description of the relation between the two monosaccharides below? Aldosel ketose, anomers, epimers, or Dl L sugars? Give one-sentence explanation for each pair: marks) CHO HO-+H CH,OH C=0 HOH HO-H HO- H CHOH HO-~H CH,OH CHO Hl- OH CHO OH HO ~ and OH H= OH CHJOH OH CIOH CHO M- OH CHO HO L~H HO- F and OH H OH HO F HO F" CH,OlI OHI CHOH



Answers

Identify the monosaccharides and their linkages in the following disaccharide.

Hello, everybody. Today we are working with Question 44 out of the Okin textbook. This section of the text book deals with carbohydrates The question asked you to identify molecule a molecule B which are redrawn for you here. Using these terms in part A and part B asks you to redraw these molecules in there a cyclical form, which means they're non circular form. So this questions actually, in my opinion, easier to dio by starting with part B. So for the time being, we're going to ignore these terms up here and get on with breaking some buns. So to the ring, these two molecules are going to start by breaking this bond in this pond here. So you're going to take the electron out of this bomb that belongs to this oxygen and put it here into this bond which will make a double bond. With this carbon, they could get out same on the other side. That will result in kicking a hydrogen off of this carbon. And now that you have taken electron of this bond, you have one that's just sitting there so you will re bond with that electron to form a full bonds by adding back another hydrogen. So now you have to all the hide groups which is a carbon double bonded to this oxygen connected back to a carbon group at this carbon here and this carbon here and you can go ahead and label those. Harbin's is carbon one and that's where we'll start our a cyclical format from. So these are two Aldo high groups he and go ahead and write those down and then moving we'll start with molecule a moving along. You have a hydroxide group facing down hydrogen group facing up so dry down to the right and up to the left. The next is flipped from that so hydroxide group here hydrogen group here the next carbon is once again flipped in orientation. So back to hydroxide on the right, hydrogen on the left and then we come to our double hydrogen and hydroxide group bonded to this carbon. Then we have that here, so onto good b you have your carbon here that is your all the hide group moving on. You have your hydroxide down, hydrogen up so high drunk cited that right hydrogen to the left. Your next one is flipped so hydroxide to the left, hydrogen to the right. The next one is once again flipped so hydroxide to the right understands the left on. Then you're to hydrogen and hydroxide group carbon down here at the bottom. So it stays in the question that these are although Pintos, which means that there's five carbons in the soup Christian and Aldo for there being an AL the hype group on the end. So if you go to Page 11 07 in your textbook, you'll see that there's a chart off. All of the different Alberto Santos is that you can have, and the one that takes on this form if you match it up, is a D silos. Now there are two differences between these two molecules that you'll have to no Tate, And you'll notice that on this carbon, which is referenced as your, um, Hemi acetyl carbon, you're hydroxide group is up on this, which makes it a beta anima, and on this one it's facing down, which makes it an alfa animal. So this is beta de zyla us, and this is Alfa de violence, So these are your a cyclical forms of the two molecules and these air there, two names now backed up for a So you have these turns here asked you if it's an up armor and animal and Ananta Mert, a Dia stereo more or and a reducing sugar. So what? Apple Mur is a dia Stermer that contains one carol center that differ. There's an absolute configuration, so we'll redraw just a little bit, these two so we can better see. So if you'll look here, the hydroxide group is down, so we'll draw it to the left, plus your to hide regions. And here you're hydroxide Group is up, will draw here and your two hydrogen. So you'll notice that between these two, they match it every Kyle center except this one. So they are a plumber's. An animal is an up armor that differs at the he meals Hemi acetyl carbon in a sickle cyclic sack ride. So because these two are the he meet acetyl carbons and they're the only two that differ. They're also animals, and in an Timur is a stereo. I simmer that are mirror images of each other. So if we draw a line between these two, and if you were to flip this directly over the bond. You would notice that they wouldn't be the same because this hydrogen would end up being over here. So they're not in an Timmers diced area. MIRs are stare I summers that are not mere images. So because these are not mere images, but they do have the same chemical format, the are dice Terry MERS. Reducing sugars are capable of being a reducing agent because it has a free all the hide group or freaky tone group, and a note here in your textbook hits. You know, What's that all monos I crowds are reducing sugars. So, yes, these are reducing sugars because they have those two al the head groups. That's a bit just about it. So thank you so much for following along.

Hi. Everyone in a force structure they provided is see Double Wando. Yes, Yeah. Search storage In between there are three inch of inch. Yeah, which grades? It's orange Eso This structure is beer. I boats deep that I waas so no ho to classified. You know, dear, I was consist of how many carbon? 1234 and five carbon So it is a pen does then it consist up a lead group and red So it is Although pen does is although bentos is no real is the second one Second one is CS two friends then see double Want old ch storage The hair needs for a change, right? Next h age. Okay, next and it's irons. Next again edge wage. So if this is De said all indeed said Oh help pillows help the lawns. So if we count in a more of carbon atoms Okay, number off carbon atoms 1234567 So it is helped us Now it consist Topic Itani group and that So it is Keto helped Does is keep the hell Does is keep told. Help those then the last structure the provider Okay, see double guano ends, but ch two age This is my age edge the next age ads next edge or age next. Mhm H h Now this is called Demon knows indeed my nose. It consists of six carbon on there. So it is. Hey, exhaust. Now, since it consist of a late function grow it is I know Hazel's and therefore be recognizes and low penthouses than these. Sort of have to lose. You don't have noses on D minus again. I'll know Hague sources alone. Things was that.

What type of glucose civic bonds links alpha glucose and beta frutos in sucrose. And very helpfully, the textbook has given us a picture of sucrose. So if I just narrowed down to be important region, here is the bonds between the two. Here you go and their labels. This is carbon one. This is coming to. So this is the glucose, and this is fructose, so we can see that this is a one to bonds. And because the glucose is alpha glucose, it's an alpha one to like acidic bonds. So Alpha 12 like a civic bonds, and you can also call it an alpha beta want to like acidic bonds because of the beta fructose as well.

All right. No problem. Number 26. It is asking us to classify these mono sack rides given. So there's really just two things that we need to, um, do in order to classify sugars. One is to see if either it has it has another heart or a key tone. And second is just counting the number of carbons and the backbone or in the main chain, as you will Michaud, we'll see more of that as we go through the problem. So let's go and start with party. So, looking at the structure of Bart a does it have a key? Don't or another height. So right here, Right here. We see, um, that need has and all the hide, right? So whenever we have never we have a sugar with and all the hard we start with the prefix. Although I'll do okay, stands for for all those or all the hide as well. Um, so next is just counting counting the number of garbage. So we got one two, three for five. Okay, So since we have five, we used to perfect right? Five and then, um, post right here o s e as just the suspects that we use for naming sugars. Okay, so part a would be although, pantos, um, moving on wood part beat so again, do we have they have another hide or a key? So looking at this oxygen right here, we see that we have a key tone. Right? So this one, since it has a key tone, we started with the prefix skeeto heat. Okay. And next is recount the number of carbons that we have. One, two, three. And that's pretty much we have three. So for, um, for three, we use the prefix try try, right. And, um, again three finished out with O S e. Um, that's just ah, the self X that we used for naming sugar. So Part B is a key toe triumph. Finally, we have a party right here again asked, We gotta ask ourselves, does it have another hide or a key? So I see you right here. It has an alder hide. Right? So we're gonna name that, although, hey, although and then we gotta count the number of garbage. Got one, two, three, four. Okay, so we have four. So we used we fixed that were that kind of like, um, cutting off Petra that are right. And it's that way because we're goingto continue it with a no s e. Okay, again. Just a suffix for naming sugars. So part C is on Aldo Tat Rose. So that's some That's all we got for this problem. Um, I hope that was home.


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