MFCsEpoKC 6L1TH 43.7HA 40 1.5 Proton Nha3.02.52.01.0 PPM10 PPHcarcon 43 Nhr...

Calculate the final concentrations of $\mathrm{K}^{+}(a q), \mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)$ $\mathrm{Ba}^{2+}(a q),$ and $\mathrm{Br}^{-}(a q)$ in a solution prepared by adding $0.100 \mathrm{L}$ of $6.0 \times 10^{-4} \mathrm{M} \mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$ to $0.150 \mathrm{L}$ of $1.0 \overline{\mathrm{X}}$ $10^{-4} \mathrm{M} \mathrm{BaBr}_{2} .\left(\text { For } \mathrm{BaC}_{2} \mathrm{O}_{4}, K_{\mathrm{sp}}=2.3 \times 10^{-8} .\right)$

To answer this question. We were going to use the Henderson Hasselbach equation and were given the K A value, which is 1.8 times 10 to the negative fifth and the pH was which is 4.39 In order to answer this, we need to get the PKK value from the K value. And to do that, all you do is take the negative log of the K value. That's essentially what the P means is negative lock. So the negative log of 1.8 times 10 to the negative sift and he put that in your calculator and the P K equals 4.75 king. Oh, use a new screen here. So the PH is 4.39 We're gonna use our Anderson Hasselbach equation here, So that's 4.75 plus the log of the concentrations. This part always takes a long time to write, all right. And all you have to do is attract the 4.75 over, and you get negative 0.35 for 3.5. If you round up when you put that in your calculator equals, log the concentrations and to get rid of the log. You just go 10 to the long to on a power, uh, log. It's always so hard to explain what that actually is. It's basically and you do that on both sides here, so 10 to the negative 100.355 And that equals point for for to Moller, and that is your concentration ratio.

Have these Sony ability part of constant chaos. Piece of this star equilibrium expression for a chemical equation where this value represents the soul ability, often ionic compound. Just one more piece of contextual information we need to know is that our concentration refers to the amount of substance in a defined space, and concentration is often expressed in units off mass per unit volume. That's what we're needing to do here is just put on some missing information. So fastly my chaos Pete, which is my Sony but it's a part of constant for S R. C 03 is 5.9 times 10 to the minus 10 my S R F To annoy Onek. Concentration is 2.0 time to tend to the minus three on my A G to C 03 catatonic concentration as 2.6 times 10 to minus four

So here we have HF has a K of 3.5 times sense in their fourth and so we're doing the same problem twice. Um, with just different values for the constellation. In the first time, we have 0.5 Moeller HF. Now, when you do a nice table, what the result is gonna be is that you'll have k equal to, uh, X squared over 0.5 minus X, where X is equal to the concentration of HBO plus, which is also equal to the concentration of af minus. Now, if you're not comfortable this go ahead and do a nice table. Further reaction HF plus water becoming f minus h 30 plus and convince yourself that this is the answer you should get. Now we have K we're gonna ignore this value of X because this could be so much smaller than 0.5 And so, if we solve this, we can get some value for X, which, like we said, is equal to the concentration of age trio plus and that value is going to be 4.1 times tense. A negative third mullah. Now this gives us the information we need to figure out the percent association because if you look at this from this reaction, the percentage of UH molecules that started here that became F minus or H 30 plus is equal to this amount each the amount of HBO Plosser af minus over the total amount that we started with. And so the way we would do that as percent association equals 4.1 times tense negative third over the initial concentration 0.5 And when you do that, you'll get the fraction 0.803 which is any point of 3%. Next problems will be very similar. It's actually identical, really just changed the number. And so r K equals X squared over 0.5 minus x. Ignore this value of X. The axe that you're going to get is equal 2.836 If you take that 0.836 and divide that by the initial concentration 0.5, you'll get the percent association or you'll get rather, um, permit. That's not the right number. My apologies. The correct number that you will get will be ah, 0.132 0.132 And when you divide that by 0.5, you'll get 0.264 which is also the 2.6%.

In this question we have to calculate the ph job $0.15 C. S. Three and S. Three. See it. That I find this one and K. B. Four, C. H. Three and H. To middle lemon is given as 415 times came to the bar negative. For now we know a time scale B. S. K. W. And we can find A. A. From here K. Will be 10 to the power minus part which is kw divided by K. P. Which is 4.5 10 to the power minus four. So the value for K. Is 2.22 times. Taking the power minus 11. This is the battle for K. Now we write the question here we're considering CS three in A. Three plus S. B. Eight plus. That's right. B. H. Plus plus water ace trio plus plus B. Let's make the ice table here. Initial concentration is 0.15 joe Jiro chains concentration minus six plus six plus six. And equilibrium concentration 0.15 minus X. X. And X. Now write the expression for K A. K A. Is concentration of east rio plus times concentration of P divided by concentration of Yeah, concentration of B eight blast. Now we already calculated the value for a as 2.2 times 10 to the part negative 11 concentration of based through pluses X concentration be also it. So let's write a square and equilibrium concentration of Bh plus that is C. S. Three and S. Three. C. L. Is 0.15 minus six. Here we are making that simplifying assumption and where exists a lot lot less than in 0.15 So we are ignoring a value for X. Therefore X square is 2.2 times 10 to the negative 11 times 0.15 Therefore X will be route over 2.2 times 10 to department 11 times zero point 15 The value for X is 1.82 times 10 to the power minus six. Motor. It means concentration up. Therefore, concentration of his trio plus is 1.82 times 10 to the power negative six. Now it is negative law is theO plus concentration. Which is there 1.82 times 10 to the power negative seats. So the value for P. A. T. S. There are 48 years 5.74 Now we'll check. Our simplifying assumption is valid or not percent. Ionization is here 1.2 times 10 to the four negative sees divided by initial concentration 40.2 point 15 times sunday. And this value is very very small. 0.1 person. So our simplifying assumption is fairly, and the answer to this question is ph is 5.74