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Number of of KMn04 (molar mass: 158.0 g/mol} in 2.00 Lofa0.350M Calculate the number of moles and the grams solution.S0...

Question

Number of of KMn04 (molar mass: 158.0 g/mol} in 2.00 Lofa0.350M Calculate the number of moles and the grams solution.S0

number of of KMn04 (molar mass: 158.0 g/mol} in 2.00 Lofa0.350M Calculate the number of moles and the grams solution. S0



Answers

Calculate the molar mass for a substance given its chemical formula; use molar mass to convert between grams and moles. How many moles are contained in each of the following? a. $25.0 \mathrm{g}$ of $\mathrm{Ca}$ b. $5.00 \mathrm{g}$ of $\mathrm{S}$ c. $40.0 \mathrm{g}$ of $\mathrm{H}_{2} \mathrm{O}$ d. $100.0 \mathrm{g}$ of $\mathrm{O}_{2}$

So here we have to calculate the more mass for substance and then converted two grams Start the moles from grams. So in part A, they're four grams of helium. So divide that by the molar mass, which is four grams per mole. So this is the more mass on this could just one more of helium part B four grams of s n 02 But that more mass which is s n 118.71 plus two times 16 1 50 went 71 grams is the molar mass. Here we get 0.3 moles of SN, go to and part C. We have four grands. Divide that by the molar mass, which is CR, which is finding on the periods table 52 plus three times 16 The oxygen's plus three times 1.1 for the head regions who is 103.3 grams. This is the molar mass. And for divided, we get 0.0 four grant no balls of CR Mitch three party. You got four grams and divide that by see a three and two. So three times 40 point 01 r 08 calcium plus two times 14 point over for the nitrogen is that we get per moon 1 48 0.26 grams. This is the molar mass and we get zero point three moles of see a three and to

The total mass of the solution is equal to 50 grands and the more fraction of road Yuria in Solution This 0.77 The Moler, Mass up stole lewd is a court to 60 grams for more and the Moler Mass. For water, it's 18 grams purple. So let's consider the mass of the Yuria as him. Um, that's the mass of the solid, so the mass of water is a good 50 minus m, so we consider the full on relationship more fraction off. A salute is equal to number off. Most of the solid, divided by most off solid plus most off solvent and most off salute can be calculated by mass divided by Moeller mess. So the mole's of to salute Yuria is equal to mm. Divided by 60 in the most of water is equal to 50 minus m divided by into. So now we can call the mole fraction of the area with the new equation a small fraction of Furia equal to 0.770 that is in of the soul it divided by in a salute plus in a solve it. So we want to. I love being this two numbers form we have zero point 77 equal to X, divided by 60. Divide about extreme. About my 60 plus 50 minus x divided by 80. So if we combine this two terms together we get three x plus 10 times 50 minus six divided by 118. So now multiply this on a tough We have three x divided by great X plus 500 minus 10 X equal to their 0.77 So we write this term we have 0.77 times three x plus 100 minus 10 x you go to three x so zero coined 231 x plus 38.5 minus 0.77 x minus three x you call two zeros who? So now we come by all the ex terms we get a negative 3.539 x equal to negative 3 38.5 So we have X equal to 10.9 grams. Therefore, the mass of the Yuria Is he going to 10.9

Let us now solve this problem from the chapter solutions and their physical properties. In this problem, we are given that the solutions of these substances the first one is 21.7% equity solutions of ethanol, and the second one is 10.684 model solution of your area. No, next to the first one. We need to calculate the mole fraction of the solvent in each case, the first one we need to calculate the more fraction of ethanol. And in the second one, we need to complete the more friction of beauty. Um, now let's start with the first one. The solution is 21.7% ethanol by mass, it means in 100 grand solution. The mass of eternal is 21.7 g interest. The mass of water will be 78 0.3 grand. The molar mass of eternal is 46 grand Permal, and that of voter is 18 point not to gram per mole. Let us now calculate the number of modes of these components. Number of modes of ethanol will be equal to 21.7, divided by 46. And this gives the value as 0.471 more number of moles of water would be 78.3, divided by 18 points, not too. And this gives the value as 4.35 Mourners. Now, according to the formula, more friction. We can write more friction of it and all as equals to a number of months of ethanol in the solution, divided by total number of months of Ethan or in water, that is number of months of ethanol, plus number of modes of water. Now substituting the values we have, we can write 0.471 divided by 0.471 plus 4.35 Further so living we can have 0.471 divided by 4.8 to 5. And on solving, we get a small fraction of eternal as point, not nine 77 Let's come at the part B here we to calculate the mole fraction of 0.684 moral solution of your area point 684 and means 0.684 Malls of your area are present in when 1000 g water. It means the number of most of your e a r. 0.684 in the mass of water is 1000 grand. Here we will calculate the number of months of water that is, it puts to 1000. They worried by 18 points, not too. And this comes as 55.49 months. Now, according to the formula of more friction, we can have more fraction of your area as equals to a number of months of furia, divided by the sum of a number of months of your area and number of months of water, substituting the values we can write. 0.684 divided by 0.684 plus 55.49 Further solving we can right 0.684 divided by 56.17 and on solving we can, right? The more fraction of your area in the solution is point, not 1 to 2. So these are the required more fractions of ethanol and the area in the given a quest Solutions

For E were calculating the mole fraction of ethanol. And so we're going to assume we have 100 grams. Ah, the solution. And if we have 100 grams, that would mean that 21.7% or 21.7 grams, would be ethanol and 100 minus that, which would be 78.3 grams. Would be water would hold its iniquitous solution. So let's calculate the moles of ethanol and be equal to 21.7 grounds. Moeller, Mass. 46 Parents promote. This would yield 472 moles of the ethanol moles of H 20 would be 78.3 grams and molar mass of water, 18 grams per mole. This would yield 4.35 rules of water. Now it's calculator more fraction. See her seat to each bible each. This would be 472 moles 472 moles plus 4.35 moles working out the mole fraction here more fraction works up to you. 0.979 for be for us to find the mole fraction of a 0.684 moral you re f solution. So, um We're told that we have 0.684 Molo Maria. Which means we have 0.684 moles. Uh, Yuria, Huh? Um, one kilogram. Uh, water. So let's calculate the moves of each 20 We have one kilogram or 1000 grams of water, 18 grams per mole. This would work out to 55.5 moves of water. Therefore more fraction of you Rio would be equal to you. 0.684 moles of Yuria The total moles has 0.684 moles plus 55.5 moles. And this will work out to a mole fraction that's equal to 0.0 1 to 2. There's are more fraction of Yuria for part B.


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