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Calculate the test statisticOA .07B. 1.26C 10D. 63...

Question

Calculate the test statisticOA .07B. 1.26C 10D. 63

Calculate the test statistic OA .07 B. 1.26 C 10 D. 63



Answers

In Exercise $9-10,$ calculate the $P$ -value if the observed statistic is (a) $\bar{x}=98$ (b) $\bar{x}=101$ (c) $\bar{x}=102$

Calories per gram are normally distributed with music was 160 equals two. We want to test the no like this agent that music was 100 against. The alternative is not equal 100. With a sample size that where N. Is 931. They want to find the p value of the observed statistic. Is any of a three C. This question is not only an understanding of the language of hypothesis testing. To answer, we have to utilize properties the normal distribution to identify the P value for the statistic. So especially to A. And then B. And see what it's all be solved identically and A. We first calculate the Z. Score for our given X. Bar, Z known as x minus mu over sigma. Whatever equals 98 minus 100 over two, divided by nine equals 93. That's the p values probability. We observe a score as or more extreme than this. Because this is a two tailed tests. We have to multiply the probability by two. Thus this is a P value is two pz less than zero equals 00.26. We proceed in a similar fashion. It's all B and C. So in br Z scores 1.5. That's our p value is 0.1336. And C. R zero is three. S. R. P value is 30.2 steps

In question 19. We're going to be finding the 95% confidence interval for row and were given four cases. And in these four cases we have the sample sizes and the sample correlation, and we're going to use this devil off confidence belts to determine the nature vipers and confidence interval. So we need to have vertical lines and horizontal lines. And for those practical result, your lines are going to be using these red lines here. If you're going to use your book, you could use a ruler to draw the magical Ninth. So let's start with the first case. In the first case, we have r equals 0.6, so we should move to r equals 0.6. So I would move my leg two r equals 016 that we have. Guess then, after that, a move my horizontal line so that it's much is a sample size of 50. We have two fifties. We have a 50 here that talk, and we also have a 50 here. The bottom Celeste us from the top and you go to the bottom. So I'm going to move my lane up until I get to 50 50 eso. As you can see, we have 50 here and goes up until it meets. Yeah, well, we have a 50. Here it goes until it means the vertical line at this point. So let me just suckle that point for you to see that this is where the line the 50 line for 50 meets with with the vertical life. Place me to move. It's likely up. Yes. So that's the point. Where the two queen site. Okay, so that's the fast 50. The second fifties, at the bottom. You can see the second fifties here, and I have to see where two lines meet and find it somewhere here so they know how to move my line up. So now we have it. Thank you to that point. Good. So now we have our to limits s so we can see clearly that of the 95 confidence interval is from 0.4 on the bottom two 0.7, this is 0.7 and this is your 0.8 and 0.75 So we could approximately to be 0.74 No, that's how fast confidence interval. So it's 0.420174 Then the second confidence interval this when the sample size is 12 and are easier. Negative Europe for five. So I want to do that and we're going to see how that goes. Three. Move this fast. Then we move. Must to article negative 0.45 Remember, we had a rule that this would be much easier and faster. So 0.45 this year and then we go to 12. Sample signs off 12. This is where the sample size of trophies. So the top line me. Move this lying down. Yeah. So the top line is here? Yes, there we have it. Onda, Uh, the bottom line is here. We should look for 12. Case 12 is here to this point. Yes. Okay, so now our 95% confidence interval stance from negative 0.8, slightly above negative 0.8, we could say negative. 0.81 It's going to be from negative 0.81 to Ah, the took back slightly above positive one. Good. This is one. And this is 1.5. So this is 0.1. Yet because 0.1. Then this would be 0.15 tweets from negative 0.812 Positive. 0.15 Okay, let's go to the next one. So we have an R equals 0.8 toe. Have to move my vertical line to the side. Believe it's easier to move from here. Okay, so going all the way to 0.8. Good. And after that, we go to a sample size off six. So we need to commit Mickey concert with the sample size of six. Okay. On where they meet, the me tell my head top curing. Then we now go to the other line and look for some process of six as well. We need to move the hours under line and wicked coincide. Yeah, I got it the length. All right. So go up until where the line coincide. So six coincides at that point somewhere, the center good. So now we are able to tell how where the two points are. So as you can see, the fast point is just above zero. And that's going to be yeah, slightly above zero and equal six. And that's going to be at zero point five, just above 0.5, because his 0.6 0.6 actually yes. 0.6 to the top part Here is 0.95 case of one more to go. We start with our negative 0.56 We have to move now. You are vertical nine. Remove it to negative zero from 560 This is negative floor. This is Nicotine Five, this is negative. Zero point 55 slightly to the left. So I assume that's approximately negative. 0.56 Now we're looking for sample size of 200. Okay. Very close to each other. Going to start here. The rights of 200 the 1st 200 year and the 2nd 1 200 is these points. We're going to move this land until gets down. Yeah, I have it. Okay, so this is where 200 ease death case. So you see that they're very close to each other now. Unless that and see the the law won its negatives. Negative. 0.6 five. But someone is negative. 0.65 to que that's faster in the 2nd 1 It's negative. 0.4 five. Good. And now we have all the confidence intervals for the four cases. And now you know how to read from the confidence bells.

What in this problem, we want to determine the follow if the output voltage is normally distributed with standard deviations 0.25 volts and the manufacturer, which is to test the null hypothesis new equals five volts because the alternative is not equal five. Using a sample size, n equals eight, calculate the p value of the observed test statistic is one of a few. See this question is challenge your understanding of the language hypothesis testing and proper implementation to solve it to determine the p w i E. The probability we observed data as a more extreme than he's given X five. So we utilize the standard normal distribution to find first, calculate Z. So for export equals 5.20 is 5.2 minutes, 5.25, 28 people, 2.26. That's because it's a two tailed tests, you cannot equal five. Our p value is two pz greater than zero equals 00.119. We follow identical steps, A, B and C and B. R. Z values 3.39. Thus two pz lessons or not because this is a negative value is 20.3. Finally, and see, Xena is 1.13. That's the p value is two pz greater than zero equals 00.1292

What in this problem, we want to determine the follow if the output voltage is normally distributed with standard deviations 0.25 volts and the manufacturer, which is to test the null hypothesis new equals five volts because the alternative is not equal five. Using a sample size, n equals eight, calculate the p value of the observed test statistic is one of a few. See this question is challenge your understanding of the language hypothesis testing and proper implementation to solve it to determine the p w i E. The probability we observed data as a more extreme than he's given X five. So we utilize the standard normal distribution to find first, calculate Z. So for export equals 5.20 is 5.2 minutes, 5.25, 28 people, 2.26. That's because it's a two tailed tests, you cannot equal five. Our p value is two pz greater than zero equals 00.119. We follow identical steps, A, B and C and B. R. Z values 3.39. Thus two pz lessons or not because this is a negative value is 20.3. Finally, and see, Xena is 1.13. That's the p value is two pz greater than zero equals 00.1292


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