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In the titration lab experiments, an aqueous solution of oxalic acid and solid potassium phthalate (KHP: a monoprotic acidzareeoed fr borkoficratioracidsing sbecoot...

Question

In the titration lab experiments, an aqueous solution of oxalic acid and solid potassium phthalate (KHP: a monoprotic acidzareeoed fr borkoficratioracidsing sbecootaeiom bydueee the mass of KHP dispensed calculate initial mass of test tube containing KHP 11.4099.8 final mass of test tube 10.6132g0 114099 g22.0230 &0.7960 &10.6139 &0.796 &

In the titration lab experiments, an aqueous solution of oxalic acid and solid potassium phthalate (KHP: a monoprotic acidzareeoed fr borkoficratioracidsing sbecootaeiom bydueee the mass of KHP dispensed calculate initial mass of test tube containing KHP 11.4099.8 final mass of test tube 10.6132g 0 114099 g 22.0230 & 0.7960 & 10.6139 & 0.796 &



Answers

Potassium hydrogen phthalate (abbreviated as KHP) has the molecular formula $\mathrm{KHC}_{8} \mathrm{H}_{4} \mathrm{O}_{4}$ and a molar mass of $204.22 \mathrm{~g} / \mathrm{mol}$. KHP has one acidic hydrogen. A solid sample of KHP is dissolved in $50 \mathrm{~mL}$ of water and titrated to the equivalence point with $22.90 \mathrm{~mL}$ of a $0.5010 \mathrm{M}$ NaOH solution. How many grams of KHP were used in the titration?

In this question, we need to determine the modularity of sodium hydroxide that's being standardized against a certain mass of potassium hydrogen salad. Now, potassium hydrogen satellite can be abbreviated by k H. P. So I'm gonna use the abbreviation most of the time when I talk about potassium hydrogen salad, but I've used the complete formula in the equation that I've written down here. So this is Kay H. P. That is the abbreviation of potassium hydrogen phallic. Now the mass of the PHP is given and then also the volume of the sodium hydroxide before deterioration started and then once the depression is done, so I still need to calculate the total volume of sodium hydroxide that was used for this standardization. And as I can do by saying the final volume 3 7.26 ml The initial volume of 0.23 million liters. And this gives the value of um 37 .37 Point 03 mL. Right? So I'm gonna use that volume as the volume of sodium, a drug side that was used during this standardization. Now for sensitization, it means actually means that this sodium hydroxide reacts with the HP. According to the strict geometric ratio of this reaction. And the strict geometric create a ratio year of sodium hydroxide, two K hp. Um is 1 to 1. The reaction is balanced as it is. Um So for us, in order to use this toy geometric ratio, we need to work with the number of moles. So the first thing would be here to convert the massive K. H. P. To the number of moles of K. H. P. And then I can use my stock geometric ratio of 1-1 to determine the number of moles off. So to hydroxide which will just actually be the same because of the 1-1 more ratio. Yeah. And then once I have the number of moles of sodium hydroxide, it's going to be easy to calculate polarity because I already have the volume of sodium hydroxide. All right. So for my first step here, I need to go and calculate a number of malls of K H. P. And that is going to be the mass of K H. P 0.5536 g divided by the molar mass of k hp. Now, instead of dividing by the molar mass, I can also multiply by the reciprocal mhm. Which, so the molar mass of GHB is 204. I'm just going to write it down here because I've pre calculated it. So the molar mass of K H. P. Is two of 4.2 grams per mole. So instead of saying I divide by 204.2 g per one mole. I can say I multiply with a reciprocal. So it's per it's one mole at the top and then 204.2 g at the bottom. So instead of saying divide by 204.2 Graham Sperm Mole I say I multiplied with a reciprocal which is one more over 204 to cramps. Right now I can use my stomach geometric ratio of Siri. Um hydroxide. Yeah two KH. B. Which is 1-1 to determine the number of moles of sierra madre oxide in terms of K. H. P. So it's one times K hp. So it's exactly the same as the number of moles of K. H. P. And now it's easy to get clarity from here because we know modularity. So the polarity of absolutely hydroxide is equal to the number of malls of. So it's just a clarity of sodium hydroxide is equal to. We know that the unit for more clarity is moles per liter. So that should give an indication what we need to do here. We need to take the number of moles of sodium hydroxide and divided by the volume of sodium hydroxide. So let's do that. Now. The number of moles of sodium hydroxide is one times the number of moles of H. P. So let's do that. We already indicated why? Already indicated earlier on how to calculate the number of moles of K HP. So it's a massive K. H. P times the reciprocal of the molar mass. One more Over 204.2 g. So this is how we calculate the number of moles of sodium hydroxide. And now we just need to divide by the volume of sodium hydroxide. But remember similarity is given in terms of moles per liter and the volume of sodium hydroxide that we have determined here by our subtraction of volume before and after filtration. He's in terms of ml, it's 37.3 mm. So we need to convert that two L. So this is 0.03 703 L. And now we can do the calculation. This gives an answer of 0.07321 melissa. This is the modularity of sodium hydroxide. Um if we use 3 7.26 million liters of the solution in order during sensitization against 0.5536 g of KHB. All right, so let's just quickly recap standardization reaction. We um I have the start and in detraction values volume values of sodium hydroxide and I have the mass of the K H. P. And so from the reaction, I know that one mole of sodium hydroxide reacts with one mole of HP. So if I have the number of moles of K. hp, which I showed how to calculate, um I know that this is the same as the number of moles of sodium hydroxide due to that 1-1 mole ratio. So now that I have the number of moles of sodium hydroxide, I just need to divide this by the volume of sodium hydroxide, which are determined by subtracting the start filtration volume from the end titillation volume. And then I need to make sure that I work in terms of leet ist, not milliliters. So I converted the milliliters two liters and then divided this into the number of moles of sodium hydroxide. In order to calculate the similarity of sodium hydroxide.

So for this question, what we're gonna want to do first is find the moles of sodium hydroxide, which is what we're tight trading are potassium hydrogen valley with and we can find the moles of sodium hydroxide by doing the similarity times the volume in leaders. So we were given concentration and that the volume we were giving him milliliters Patou over from the leaders. Two leaders we just divide by 1000. So our leader value is 0.0 20 for six, which gives us a value of 0.20 3.20 46 Moles of an a O. H. So we know that our potassium, hydrogen sally and sodium hydroxide exists is a wonder one molar ratio. So one mole of the potassium partnership Valley is neutralized by one bowl of anyway H so we can find the mass of our potassium hydrogen valley. By taking the moles instances a 1 to 1 ratio we could use the moles of NH got 0.20 for six times a molecular weight which we know to be 204.2 to using a periodic table. So overall we find the mass of our potassium hydrogen. Sally to be 0.4178 grands.

Hello. But this is uh the balanced chemical reaction for what is going on. So we can calculate the mole of GHP. Which is to go to the mass of Malema's. The mass was given us 0.0 sorry 0.1082 And of course the mullahs mass just get the individual mass. Individual mullah masses. Sorry for potassium for hydrogen endeavor phosphorus they just add them up. These are just constant. Okay that's gonna give you 204.22 So if you divide it you're gonna get this citizen number of most of PHP. Okay now when you have this expression right here the more ratio is gonna be one is 21 everywhere. Right? So you have one more PHP being neutralized by one mole of sodium hydroxide. Okay because this one is the one right? Therefore what would this give you the one? We just come with? The albeit is equivalent? So because the 1 to 1 ratio is gonna be the same thing for sodium hydroxide. So the number of moles of sodium hydroxide is also 10.5 to 9. Okay, Because the more ratio is one is one, of course, once you have that there is a similarity with, the similarity is the number of most of the volume, volume uh, steady four by 67 military. Okay. So you're gonna find the modularity and this is gonna be our final answer for the modularity of sodium hydroxide. Okay, thank you very much.

Chapter six Problem 80 tells us about a reaction between sodium hydroxide and the molecule K H P. So we have sodium hydroxide reacting with K H P. And we're told that K HP has one acidic hydrogen. So we have 10 h i on from any ohh reacting with one acidic hydrogen, giving us each to oh, and since we have one of each of thes, we know that our equation is balanced or that any wage and K H P have a 1 to 1 relationship. So we're given some information about K, H, P and about the amount of sodium hydroxide, and we want to know the polarity of sodium hydroxide. So whether we can solve this is converting the grams of Cage P two moles of Cage P. Then, since one mole of K H P is equivalent to one mole of Joh will have the most of any away from there. Finally, we'll do moles divided by leaders of a nail each to get our mill Araji. So let's begin. We're starting out with K H P. And we know that we have 0.10 82 Gramps, we're given the molar Mass here, where one mole is equivalent to 204.22 grams. So that gives us 0.53 moles. Remember that this is also equivalent to the moles of any O. H. So to get the polarity of any Ohh, we'll take the number of moles and divide with a number of leaders, which in this case, 0.3467 That gives us our final polarity of 0.15 Moeller.


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