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The amount of $\mathrm{O}_{2}$ for me a at N.T.P by the complete combastion of $1 \mathrm{~kg}$ coal is? (a) $22.4 \mathrm{~L}$ (b) $2240 \mathrm{~L}$ (c) $1866 \mathrm{~L}$ (d) $100 \mathrm{~L}$

Here. We have one minus eight. Divide by two W minus one is equal to negative. 16 divided by two W minus one squared. First thing I'm gonna do is I'm going to substitute you Is equal to W minus. What? So that gives us one minus eight over you is equal to negative. 16. Over. You squared. I could rewrite this using negative exponents, which I'm gonna do. So that is one minus eight. Huge. The negative First power is equal to negative. 16. You to make their second power. Okay. And I'm gonna get everything on one side giving me at 16. You, um, argued negative power. So I have 16 youth, the negative to power. Minus eight. Used native one power plus one is equal to zero. Okay, so now this looks like a normal cosmetic, and then do another substitution here. I'm going to say, um w is equal to huge the negative first power. So that means w square. It is a huge the native second, I'm doing this. We can see that this is just a normal quadratic equation. So I have 16 w squared minus beat. W W was originally variable is probably a bad idea. Um, I'm going to say x so. 16 X squared, minus eight X plus one equals zero. Okay, now within. Solve this. Um, and it could be factory ble. That is a possibility. Um, let's see. Do I want to factor it? I'm gonna use completing the square, so no, I mean, she's 1/4 to formula. That will be easiest, because I know that will work. So this is my A term. This is my B term. This is my C term. So I have X will be equal to negative. Be so eight plus or minus the square root of B squared minus four times a time. See, all over two A. So that gives us, except eight plus or minus the square root of, um, so eight squared is 64 and then four times 16 is also 64. Sorting square is Europe over two times 16 which is 32. So x will be equal to 8/32. Amazing. Okay, So 8/32 who divide both by eight. You get one fourth. So x will be ableto one force. Um, and there's only one value because plus or minus here doesn't change the value. So now we have to go back here and do some substituting back in. So, um, X is you to negative one. So that means if I've raised both to negative first power, I get that you is equal to four, and then I'm actually solving for W. So to w minus one is equal to four. So I add one. I get to w 0 to 5. Um, so divide by two, and I get that w Is it to five halves? That's not quite right. So what I do here? Um, 16 times two is 32. Um, let's see. Double checking all my work. Eight divided by 32. That is 1/4 to W minus one. Yeah, they add one to both sides. And I get fired, perhaps. Okay, don't be used five halves. Um

Well, everyone, this is Ricky and they were working on a problem. Five from a model test number six. And so this is a question asking us about sphere that's inscribed in a cube. And what the ratio of the falling sphere to the booth. All right, So to start this question, let's write down the formulas for both of our severe and for acute first fear, 4/3 choir cute. And for the volume of the Cube, a heart issues this will rather Cuba's the length aside. Yes, threes as cute. And then, if we translate this where the length of side ISS equal to the radius spear, get or rather the diameter of the spear, get what you are. That's a cute Wallace to paint way Now if we look at the ratio votes spear. Q. Start with Why are huge? Huge. You see that? Ready? I drop out. And for my what a fine two. Everything's fine Pi over 63.14 over six, which is about 0.52 I hope this video is helpful. Seeing that

Start taking a look at here is a chemical synthesis, so I'll run through each of the steps that we need so fast You have the addition off H I. This is 21 missile cyclo painting. This gives us our Markov knockoff product. That is one iota one missile cyclo panting. So in our second step, we have the reduction of our Al Keen with hydrogen in the presence off a transition metal will generate our al cane. And so then we have myth are cyclo plantain in Assad step. We have the hydration off the Al Keen that takes place. So in our fourth step here we have the addition of cold sulfuric acid which gives us our alcohol. Hydrogen sulfate fifth step now are ill. Kyle hydrogen sulfate are easily hydrolyzed by water to give alcohol's. In our next step, we have the addition of HBR. So you are one missile Cyclo Pantene gives the Markov knockoff product. Following this, we have the addition of a halogen, which is an anti edition about our double bond. Therefore, when the halogen of the Al Keen is carried out in the presence of water, the major product is or halo alcohol. And so in the next step, we have the addition of HCL 21 missile Cyclo Pantene gives us our McCartney cough product off one Clara one metal cyclo plantain on, then Step nine. Now we have the oxidation of Al Keene's using a zone followed by the cleavage off the resulting owes denied to Carbonell compounds that is widely used for the determination off the structure of our unsaturated compounds. So following this, we have Osmond tetra oxide that is used to synthesize this one to Dial's Next we have treatment where the hot, basic potassium permanganate which oxidative leak leaves the double bond off the alkaline. So following this, we have a very useful lab procedure for synthesizing our alcohol's. So from our Calkins, we avoid the rearrangement in a two step method. So firstly, we have ox emasculation followed by DEMAR curation. Lastly, we have hijab oration, oxidation reactions. That is, we geo selective

This question Struck's us to solve for tea by using natural logarithms. What we know is that looking at this question, the first step is we can consolidate our exponents with tea each. The three T minus two t is 8/5. Take the natural order of both sides. Now we know this is actually a trick because natural longtime Z's simply one leaving us with tea is equivalent to this could be written as natural eight minus natural. Over five is a decimal. This is approximately 0.47