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J0 points2 attempts leftCheck my work44.6877g sample of octane is burned in bomb calorimeter containing 7.86 X 10* g EzO. Civen thatt 282 X11Q' cal of energy i...

Question

J0 points2 attempts leftCheck my work44.6877g sample of octane is burned in bomb calorimeter containing 7.86 X 10* g EzO. Civen thatt 282 X11Q' cal of energy is released if the water temperature increases 3.59PC. Cakculate the energy released in J.Enter vour answer in scientific notation. Be sure to answer all parts: 10

J0 points 2 attempts left Check my work 44.6877g sample of octane is burned in bomb calorimeter containing 7.86 X 10* g EzO. Civen thatt 282 X11Q' cal of energy is released if the water temperature increases 3.59PC. Cakculate the energy released in J. Enter vour answer in scientific notation. Be sure to answer all parts: 10



Answers

Isooctane is a primary component of gasoline and gives gasoline its octane rating. Burning $1.00 \mathrm{~mL}$ of isooctane $(d=0.688 \mathrm{~g} / \mathrm{mL})$ releases $33.0 \mathrm{~kJ}$ of heat. When $10.00 \mathrm{~mL}$ of isooctane are burned in a bomb calorimeter, the tem- perature in the bomb and water rises from $23.2^{\circ} \mathrm{C}$ to $66.5^{\circ} \mathrm{C}$. The bomb con- tains $1.00 \mathrm{~kg}$ of water. What is the heat capacity of the calorimeter?

Yeah, we hear. And artie it is okay burning of one related. Oh, I saw pain is 31 zero kg sample of. I saw pain. Bacon. Yes, then me religion. Yeah, initiate temperature of Mhm bomb and water is 23.2° and Degrade and final temperature is 66 point five degrees integrated mass of water. Mhm income calorie meter is one kg That is 1000 specific heat of what? That It's supposed to 4.18 to programme degrees centigrade Since an activity stopped running of one envelope sample is 33 kg jewel therefore. And I did. It is after. Yeah, yeah. After burning off then re later of sample X equals two tragedy into then is the question she handed A ticket or two. That is but it you know, you know you don't you in a bomb calorie meter. He had given up by the action is absorbed by the calorie meter including metal bomb and water. Therefore do. The action is equal to minus you. Get unlimited thank you. Direction is he goes to minus that specific heat of the of the matter. Is C Carroll limited Therefore do you go when we do Yes. The karate meeting into data? Yes, I'm into the water into data. Yeah duration is minus you know, you know the Sequels right now. See get the emitter into the city is 66 1 five minus To achieve 1 2 US masses 1000 into Specifically specifically the water is 4.18 into That, that is 66 -66.45. final strategy 12 therefore 20,000 and Sequels to who did see one? You too see carol the meter Yes. 180 99 Yeah. Yeah. See calorie meter is the question. Yes. Mhm. Okay this is supposed to 20 451.24 seven two part thing is integrated. That can be written as three 44 You don't you? Well that is integrated. The specific doctor perimeter is cheap, one for €4 jewels party disintegrated.

Okay, let's determine the final temperature of the calorie emitter. We'll need to use the result from the previous question. We've calculated the total heat capacity from the previous question is equal to 10 points 84 kg joules per degrees Celsius. So our total capacity is equal to the heat capacity for the water, plus the heat capacity for the Ben's OIC acid. So we know the total heat capacity is 10.84 kg jewels per degrees Celsius. That he capacity of water is 4.18 Kill a Jules per kilogram degrees Celsius, The mass of water. It's 0.987 kg. We have 987 g, but will convert that 2 kg and then the heat capacity of the Benzo kassid. So solving this, we can calculate the heat capacity of the Benzo Gazza, the C six, h five, C O. H. And this would be equal to 6.72 kilo jewels per degree Celsius. And we know that the heat capacity yeah, for the Benz OIC acid would be equal to the entropy. Change over the adult a t change in temperatures. So he capacity benzo cast a 6.7 to kill a Jules per degrees Celsius. Theon therapy change is 26.4 to kill a Jules per gram, and we know that we have 1.56 g of the benzo a kassid and IT final temperature minus the initial temperature 23.32 degrees Celsius. Solving this equation for the final temperature, we will find that this is equal to 27.48 degrees Celsius and this would be the final temperature in the calorie emitter.

The amount of heat evolved in the accelerometer is proportional to the amount of iso octane that is present within the bomb. So when we have not 0.5 g of isO octane that is burnt, we have 24.6 kg joules of energy released. So what we can do is calculate the amount of heat released when we have 100 mg. So we take 24.6 kg jewels divided by 0.5 g, which is equal to X divided by 9.1 g. When we solve for X, which is 4.81 kg jewels. Yeah. And so the queue of reaction is equal to the mass of each tour. Multiplied by the specific heat capacity of each tour, multiplied by delta T. Multiplied by the specific heat capacity of the color perimeter multiplied by delta T. We're looking to solve the delta T. Which is equal to Q. Of reaction divided by the mass of H 20 Multiplied by its specific heat capacity. H 20 multiplied, and then we add the specific heat capacity of the calorie meter, And so the value we get is not .9°C. And so we know that delta T. Is equal to T. Final takeaway T initial were T final. We can solve for us 24.5°C. Mhm.

So were piggybacking off of exercise 12 Well, so we need to figure out what is the final temperature of the Colorado or contents. So what we're doing is we're figuring out. So there's water filled in this cholera emitter. We've got some initial scenarios. Some of our sample, um, and we have the delta e of our sample as well. So we first need to figure out how much energy is going to be gained by the water on the campus calorie emitter. So we know he. So we're trying to find the heat release here, so we know that we've got 1.56 grams of our substance, right of I think it was of our benzoate. Assad. Yeah. Um, and then we've got our delta E, which is in killer Jewels program. So what we can do is we can use dimensional analysis to get rid of the grams to figure out how much energy is being released just by our substance itself into the calorie Mader. Then we need to figure out the heat game by the calorie meter. Um, because that's gonna help us to figure out our delta, our delta tr change in temperature. So if we're following conservation of energy, the heat released by our substance should be equivalent to the heat gained by our calorie meter. And then we use a really easy Q equals M C Delta T. But we have to have two parts of this here. We have to have the part of what's going on with our substance, plus the information with the calorie ometer. So we know our our water is point A. You know, Jules per degree kilogram. So this is everything that's happening with the water times 0.987 kilograms The mass of the water times change in temperature, plus what's going on with the actual calorie emitter itself? It's explained. 66 Hillary jewels partner degree Celsius cottons change in temperature. So we go through. We worked through Ramat. We end up with a delta T of 2.586 degrees Celsius. So then if we just do chief, I know minus t initial you get changing temperatures are, um, initial temperature waas 23.32 The final minus 23.32 equals are changing temperatures, or T final would B 25.91 degrees Celsius


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