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Draw the major organic product of the reaction shown belowOHKzCrzOz HzSO4, HzOYou do not have to consider stereochemistry You do not have tO explicitly draw H atoms...

Question

Draw the major organic product of the reaction shown belowOHKzCrzOz HzSO4, HzOYou do not have to consider stereochemistry You do not have tO explicitly draw H atoms In cases where there is more than one answer; just draw onecpy AaE>/ #wo @0 [F

Draw the major organic product of the reaction shown below OH KzCrzOz HzSO4, HzO You do not have to consider stereochemistry You do not have tO explicitly draw H atoms In cases where there is more than one answer; just draw one cpy AaE >/ #wo @0 [F



Answers

Draw the organic products formed when cyclopentene is treated with each reagent. With some reagents, no reaction occurs.
a. H$_2$ + Pd-C
b. H$_2$ + Lindlar catalyst
c. Na, NH$_3$
d. $CH_3CO_3$H
e. [1] $CH_3CO_3H$; [2] $H_2O, HO^-$
f. [1] $OsO_4 + NMO$; [2] $NaHSO_3, H_2O$
g. KMnO$_4$, H$_2$O, HO$^-$
h. [1] LiAIH$_4$; [2] H$_2$O
i. [1] O$_3$; [2] CH$_3$SCH$_3$
j. (CH$_3$)$_3$COOH, Ti[OCH(CH$_3$)$_2$]$_4$, ($-$)-DET
k. mCPBA
I. Product in (k); then [1] LiAIH$_4$; [2] H$_2$O

Let's take a look at more reactions of al canes. Well, let's take the first one with each 20 in each to us of four. Well, we know that that will produce the Markov Makov product in an alcohol so well, which carbon involving the, uh the l keen four carbons adjacent to the Al Cain will contain the alcohol. Well, the most stable carbon is that one. So that will be where the alcohol will be. And that will be your product stick. It will get the next one. Here we have this out keen with brahmi and water. So we know that that will produce the mark optical product relative to the alcohol. The alcohol would be the most stable. Be at the most stable carbon, and the Bruning will be at the last stable carbon. We know that boring nation produces the anti Markov Nukaga alcohol, which means less stable al keen or less stable alcohol of the Al King. So the less stable carbon is that one because a tertiary carbon is very, very stable. So that will be where alcohol will be produced, bro Ming. Now, this doesn't produce a carbo cat ion. So We're kind of just limited to a bro. Mean Adam here and abroad. Ming Adam. There those analysis. Well, this will cleave this double bond producing to Aldo hides. And from the looks of it, this molecule symmetric relative to that out keen. So it will just produce to molecules this Aldo hide, and that will be your final product.

This question is as the reaction off. Ah, one mess hopes cycle hex symbol with the striations. So within our eight in a h sodium hydride isa base. So it will be pro tem late. Ah, this Ah, I said it. Broughtem. And so the product of this will be sorry. Um, song What's sodium chloride? No reaction will happen Which ate beer The ah, the uh ah h plus we're problem, mate The age and then it will generate the Kabul can tie in Would just stay boy enough and then would be our minus It will farm one. Missed you Uh Psychlo Hexen one bro My eyes, the air war happen the same reaction with HBO from Kabul Katana will he give us and then subsequently will see a minus will generate the coordinated product sum for it, as it, on the other hand, react with it will also from ah generate the kabocha tie in. However, the next step will be s so far to minus attached. This and this one go back in here and so it will generate this often the most substituted all the fit is the most able proud of sodium hypochlorite. More reaction. Sorry. Sorry of hypochlorite sodium bicarbonate sodium hydride. Then see a story series to be Are so the first step, uh, we've seen in the previous page will farm the sodium salt and then we'll see is three cs to be our The old miners over here's gonna attack. This one is a living group, and the product will be a neither. So, last poc 03 First reaction with P o seal three will generate off course what the hell appeared in. Oh, yeah, that's right. And then see a minus attack here. Make this one become a good living group. She's a final brother.

All right. Reaction. Uh, this question has us or it's the product of reaction off one medal Sacra Jackson on with this creation over here. So the 1st 1 this one's really strong base sodium plus H minus eight minus will be pro tem It this one and you will have the product off Minus Enable us with this saw. HBR is to be out with us Broughtem night the ah ah ohh group which make it become a good living group and then generate a couple car tie in and b R minus will farm the pro might compound a CEO. It's ah same mechanism. And so the product will be see over here. So boric acid or act differently Supported gas. It will also farm first also farm Ah, broughtem late. The whole group generate the cable car tie in. But then the, uh s so far to minus gonna attack this hydrogen. And so it generated all off in over here, the most up student olive being is the strongest nuclear fire or sorry. I think I blew a sodium bromide and solve your problem. I will have no reaction. Ah, sodium bicarbonate potentially can't deport, mate No, it cannot. Sorry. Um no reaction. Sodium hydride will assist you see, in the previous space the first time with sodium hydride, we will generate the, uh, costs I first oh minus and a bus. And then with ch three c is to be our wonder go nuclear flick substitution over here. And the final product is an ether. Ah poc l three and Peter then poc 03 imputed In the first reaction out, Holbrook will react with p o c l three simple nuclear very substitution with the have a period in will generate this intermediate over here and then period in with the lamp here on the hydrogen. Sorry on the night vision will attack this product. This one now become a good living girl. And so you will end up with this kind of products to substituted all the fit

For this question, we have to draw the Lewis structures of the following molecule. So for part A, we have C two after four or a touch of for ethylene draw the Louis structure. We will count the number of bounds electrons that we have. So each carbon has four valence electrons and each floor has seven, so of a total of £36 electrons. So to draw the loose structure, we will have the carbon. And we know that there is a carbon to carbon double bond because in the name, uh, Tetra for ethylene, that Ian at the end indicates that there is a carbon carbon double block. So each carbon has bonded to two florins. And we will use the rest of our electrons to complete the octet of the florins and that we have exactly enough electrons to do so. So that is, they lose structure for part A. For part B, we have propane again. We're gonna count the number of bounce left drugs that we have. Each carbon has four valence electrons and each hydrogen has one, so it gives us a total of 20 bounce electrons. You will have a three carbon chain and then we have eight electrons, so each carbon will have enough hydrogen to complete York types of carbons. This uses up all of our electrons as well Call with bonds. So that is a little structure of her heartbeat. For part C, we have you to dying, and again we're going to count the number of electrons and the total number of electrons. For this, uh, is 20 to 22 bounds electrons and the name of you to die. And we know that we will have to carbon to carbon Delavan somewhere in the molecule so we can have a carbon carbon double bond here and then another carbon. And then I had a carbon carbon double bond. We have ch two sore. First carbon will be wanted to two hydrogen. Our next carbon is bonded to one hydrogen. Our next carbon has also bonded to one higher gent in our last carbon is bonded to to hide regions in all these bonds, um, use of all of our electrons and all of our carbons with full locked up for party. We have pro pine. The number of bounce elections that we have in total is 16 and by the name Propylene. We know that we will have a carbon to carbon triple bond. So we have our first carbon CHD, which has bonded to three hydrogen and you will be carving Dickerman Single bond and then thes two carbons will be bonded by a triple bond. So that is where our triple bond is, and we have this last Carbon is born into one hydrogen so that issues of all of our electrons and all of our carbon of people locked up so that it's a little structure for party. Last day for party, we have been doing acid. You will. We have £46 electrons and we'll start by drawing a normal benzene ring. So will be alternating or carbon to carbon single bonds and carbon to carbon double bones. Five of the carbons will be attached to a hydrogen and one will have a acid. So this carbon is wanted to this carbon and you will have a carbon oxygen double bond and then a carbon oxygen single bond just bonded to hydrogen. We will use the rest of our electrons to have the lone pairs to our oxygen's. This is where our ass it is and we will have bins OIC acid. So that is a little structure for party


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