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3. What is the frequency of a light wave with 6Onm? How much energy does mole of these photons have?What is the range of visible light in nm? Which colcr oflight ha...

Question

3. What is the frequency of a light wave with 6Onm? How much energy does mole of these photons have?What is the range of visible light in nm? Which colcr oflight has thc highest energy and why?

3. What is the frequency of a light wave with 6Onm? How much energy does mole of these photons have? What is the range of visible light in nm? Which colcr oflight has thc highest energy and why?



Answers

(1) What is the energy range (in joules and eV) of
photons in the visible spectrum, of wavelength 410 $\mathrm{nm}$ to
750 $\mathrm{nm} ?$

In order to solve this problem, we're going to need to remember how did you calculate the energy food? So the energy of a photon e is equal to Planck's constant times the speed of light see, divided by the wavelength of the Fulton, where HC is 1240 electoral votes nanometers. Also, we will need to remember, um, some regions of the electromagnetic spectrum. So remember that you've Eli, that is ultraviolet light is equal to eyes in the range off, uh, 10 millimeters to 400 m. Visible light is in the range of 400 m to 700 millimeters, and infrared light is in the range of 700 millimeters to one millimeter. So what we have in our problem is three energies their energies of Fulton's eso. The first Fulton has an energy off 0.3. I have 10 votes. The second photon has an energy of three electoral votes and finally, the third photon has an energy off 30 electoral votes. And our goal is to calculate both the wavelength corresponding to this energy this energies on and also to which a region of the electromagnetic spectrum these photos below. So Let's start with a notice that easy which you h silver London. Meaning that Lunda is h silvery. So on. The one is 1240 electron gold centimeters and then we have two divided by 0.3 electing votes. So lumber one is equal to, uh, 4133 electoral votes. Now notice that this is between 700 nanometers and one millimeter, meaning that it's in the infrared spectrum. Then in question be plumbed A is HC divided by London, entered, divided by E. So this is equal to 413.3 electoral votes. Okay, And this is in the visible spectrum. It's between 400 m and 700 millimeters. Uh huh Oh, yeah. Okay, then the question see, the energy is 30 actual votes, so it's 1240 divided by 30. That's 41.33 electron works, and this is between centimeters and 400 m. Meaning that is, it's in the ultraviolet spectrum which concludes or exercise

Hi, everyone. This is the problem Based on energy. Off photo energy off photo is defined as as she by London in problem it is given we have toe find a reverent off photo having energy three times off energy off the photo off prevalent eight contain in a meter energy off this photon will be as c y lambda one on energy off other photon is SCV Lambda Tau And here it is given he too is three times off. Even so, it will be as she while under two, will be three times off SG by Lundergan Hands learned to build build under one y three. That is eight contained nanometer divided by three. So it is Toby to 73.3 three nanometer. That's all. Thanks for watching it.

This question were given various photo energies and we want to find what s D? We think for each of these four tons and we're gonna use the question right equals tow hitch, see over and rearranging this to find everything that is see over he right? And so we're gonna use this formula to find everything for each off our different energies. So for the 1st 1 I'm gonna do the entire step there is putting develops it. If us on the top is the bank's constant propriety, spittle flecked, you fight it by the energy. There is no point tree evey. But in order to get in terms off meters, we'll have to use. I have to use ah as I units for our energy. And so we have to convert our electron volts into juice by multiplying by 1.6 time stand cough minus 19 juice per e v ranked And from here, read on for us Equation E. We've thing that we should get be 4110 40. So you're full point. What? Full times 10 to pull off minus six. Meet us. But since we wanted in terms off nano meters, we will need to multiply by 10 to powerful nine to get in terms off, then return reshoot gets for 40 meters. We do the same thing for the subsequent energies you see over he and remember to convert the energy from electoral votes into jewels. Using the collection Fekter every shoot gets for 14 centimeters. You lost parts for the 30 electoral votes. We should get 41.4 nano meters so that identify what we thinks. Thea, let me know. The visible range ranges from 400 meters to 700 meters. So beyond the same international media studies for it where s below 400 Enemy s? This is ultra violets, so we should be a very easily identify. So the 1st 1 is much greater than some 100 meters. So this should be you for it. The second we think he's actually we didn't this range of visible light so should be visible and last e the final answer. It's actually way below D 400 a widow rich and so he must be ultra fight. That's

Here. We want to find the energy of a photon with a visible light of 500 nanometers so you could find the equation. Your textbook, which is that the energy of a photon is equal to plants constant, which is known as H bar multiplied by the frequency of our photon. So place constant is equal to about 6.63 times 10 to the negative 34 Jules to unit of energy. I also know that frequency is given by the speed of light divided by our wavelength, the speed of light SP 10% of the eight meters per second. And our wavelength in this case is 500 times 10 to the negative nine meters. So negative 500 centimeters. When we do this, how we get a result of six times 10 to the 14 hurts rude and then plug into our equation. We multiply this by Plank's constant. We get an answer of four times 10 to the negative nine


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